Datasets:
HusnaManakkot
/
haispider

Dataset card Viewer Files Community
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allergy_1
SELECT advisor , count(*) FROM Student GROUP BY advisor
How many students does each advisor have?
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allergy_1
SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1
Which advisor has most number of students?
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allergy_1
SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1
Give the advisor with the most students.
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[ "Give", "the", "advisor", "with", "the", "most", "students", "." ]
allergy_1
SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat"
How many students have cat allergies?
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allergy_1
SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat"
How many students are affected by cat allergies?
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[ "How", "many", "students", "are", "affected", "by", "cat", "allergies", "?" ]
allergy_1
SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2
Show all student IDs who have at least two allergies.
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allergy_1
SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2
What are the students ids of students who have more than one allergy?
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allergy_1
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
What are the student ids of students who don't have any allergies?
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allergy_1
SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
Which students are unaffected by allergies?
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[ "Which", "students", "are", "unaffected", "by", "allergies", "?" ]
allergy_1
SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs"
How many female students have milk or egg allergies?
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[ "How", "many", "female", "students", "have", "milk", "or", "egg", "allergies", "?" ]
allergy_1
SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs"
How many students who are female are allergic to milk or eggs?
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allergy_1
SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food"
How many students have a food allergy?
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[ "How", "many", "students", "have", "a", "food", "allergy", "?" ]
allergy_1
SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food"
How many students are affected by food related allergies?
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allergy_1
SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
Which allergy has most number of students affected?
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allergy_1
SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1
Which allergy is the most common?
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allergy_1
SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy
Show all allergies with number of students affected.
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[ "Show", "all", "allergies", "with", "number", "of", "students", "affected", "." ]
allergy_1
SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy
How many students have each different allergy?
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allergy_1
SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype
Show all allergy type with number of students affected.
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[ "Show", "all", "allergy", "type", "with", "number", "of", "students", "affected", "." ]
allergy_1
SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype
How many students are affected by each allergy type?
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[ "How", "many", "students", "are", "affected", "by", "each", "allergy", "type", "?" ]
allergy_1
SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
Find the last name and age of the student who has allergy to both milk and cat.
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allergy_1
SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
What are the last names and ages of the students who are allergic to milk and cat?
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allergy_1
SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy
What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.
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allergy_1
SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy
What are the allergies the girl named Lisa has? And what are the types of them? Order the result by allergy names.
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allergy_1
SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
Find the first name and gender of the student who has allergy to milk but not cat.
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allergy_1
SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
What are the first name and gender of the students who have allergy to milk but can put up with cats?
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allergy_1
SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")
Find the average age of the students who have allergies with food and animal types.
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allergy_1
SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")
How old are the students with allergies to food and animal types on average?
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allergy_1
SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
List the first and last name of the students who do not have any food type allergy.
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[ "List", "the", "first", "and", "last", "name", "of", "the", "students", "who", "do", "not", "have", "any", "food", "type", "allergy", "." ]
allergy_1
SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
What is the full name of each student who is not allergic to any type of food.
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[ "What", "is", "the", "full", "name", "of", "each", "student", "who", "is", "not", "allergic", "to", "any", "type", "of", "food", "." ]
allergy_1
SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
Find the number of male (sex is 'M') students who have some food type allery.
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[ "Find", "the", "number", "of", "male", "(", "sex", "is", "'M", "'", ")", "students", "who", "have", "some", "food", "type", "allery", "." ]
allergy_1
SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
How many male students (sex is 'M') are allergic to any type of food?
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[ "How", "many", "male", "students", "(", "sex", "is", "'M", "'", ")", "are", "allergic", "to", "any", "type", "of", "food", "?" ]
allergy_1
SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat"
Find the different first names and cities of the students who have allergy to milk or cat.
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allergy_1
SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat"
What are the distinct first names and cities of the students who have allergy either to milk or to cat?
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allergy_1
SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal")
Find the number of students who are older than 18 and do not have allergy to either food or animal.
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allergy_1
SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal")
How many students are over 18 and do not have allergy to food type or animal type?
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[ "How", "many", "students", "are", "over", "18", "and", "do", "not", "have", "allergy", "to", "food", "type", "or", "animal", "type", "?" ]
allergy_1
SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy")
Find the first name and major of the students who are not allegry to soy.
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[ "Find", "the", "first", "name", "and", "major", "of", "the", "students", "who", "are", "not", "allegry", "to", "soy", "." ]
allergy_1
SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy")
What are the first name and major of the students who are able to consume soy?
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[ "What", "are", "the", "first", "name", "and", "major", "of", "the", "students", "who", "are", "able", "to", "consume", "soy", "?" ]
store_1
SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5;
A list of the top 5 countries by number of invoices. List country name and number of invoices.
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[ "A", "list", "of", "the", "top", "5", "countries", "by", "number", "of", "invoices", ".", "List", "country", "name", "and", "number", "of", "invoices", "." ]
store_1
SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5;
What are the top 5 countries by number of invoices and how many do they have?
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[ "What", "are", "the", "top", "5", "countries", "by", "number", "of", "invoices", "and", "how", "many", "do", "they", "have", "?" ]
store_1
SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8;
A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size.
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[ "select", "billing_country", ",", "sum", "(", "total", ")", "from", "invoices", "group", "by", "billing_country", "order", "by", "sum", "(", "total", ")", "desc", "limit", "value" ]
[ "A", "list", "of", "the", "top", "8", "countries", "by", "gross/total", "invoice", "size", ".", "List", "country", "name", "and", "gross", "invoice", "size", "." ]
store_1
SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8;
What are the names of the top 8 countries by total invoice size and what are those sizes?
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[ "What", "are", "the", "names", "of", "the", "top", "8", "countries", "by", "total", "invoice", "size", "and", "what", "are", "those", "sizes", "?" ]
store_1
SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10;
A list of the top 10 countries by average invoice size. List country name and average invoice size.
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[ "A", "list", "of", "the", "top", "10", "countries", "by", "average", "invoice", "size", ".", "List", "country", "name", "and", "average", "invoice", "size", "." ]
store_1
SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10;
What are the names of the countries and average invoice size of the top countries by size?
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[ "What", "are", "the", "names", "of", "the", "countries", "and", "average", "invoice", "size", "of", "the", "top", "countries", "by", "size", "?" ]
store_1
SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5;
Find out 5 customers who most recently purchased something. List customers' first and last name.
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[ "Find", "out", "5", "customers", "who", "most", "recently", "purchased", "something", ".", "List", "customers", "'", "first", "and", "last", "name", "." ]
store_1
SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5;
What are the first and last names of the 5 customers who purchased something most recently?
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[ "What", "are", "the", "first", "and", "last", "names", "of", "the", "5", "customers", "who", "purchased", "something", "most", "recently", "?" ]
store_1
SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10;
Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders.
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store_1
SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10;
What are the top 10 customers' first and last names by total number of orders and how many orders did they make?
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store_1
SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10;
List the top 10 customers by total gross sales. List customers' first and last name and total gross sales.
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store_1
SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10;
What are the top 10 customers' first and last names with the highest gross sales, and also what are the sales?
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store_1
SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5;
List the top 5 genres by number of tracks. List genres name and total tracks.
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SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5;
How many tracks does each genre have and what are the names of the top 5?
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SELECT title FROM albums;
List every album's title.
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SELECT title FROM albums;
What are the titles of all the albums?
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SELECT title FROM albums ORDER BY title;
List every album ordered by album title in ascending order.
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SELECT title FROM albums ORDER BY title;
What are the titles of all the albums alphabetically ascending?
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SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title;
List every album whose title starts with A in alphabetical order.
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SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title;
What are the titles of all albums that start with A in alphabetical order?
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SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10;
List the customers first and last name of 10 least expensive invoices.
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SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10;
What are the first and last names of the customers with the 10 cheapest invoices?
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SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
List total amount of invoice from Chicago, IL.
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SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
What are the total amount of money in the invoices billed from Chicago, Illinois?
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SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
List the number of invoices from Chicago, IL.
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SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL";
How many invoices were billed from Chicago, IL?
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SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state;
List the number of invoices from the US, grouped by state.
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SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state;
How many invoices were billed from each state?
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SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1;
List the state in the US with the most invoices.
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SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1;
What are the states with the most invoices?
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SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA";
List the number of invoices and the invoice total from California.
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SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA";
What is the number of invoices and total money billed in them from CA?
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SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith";
List Aerosmith's albums.
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SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith";
What are the titles of all the Aerosmith albums?
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SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham";
How many albums does Billy Cobham has?
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SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham";
How many albums has Billy Cobam released?
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SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins";
Eduardo Martins is a customer at which company?
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SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins";
What is the company where Eduardo Martins is a customer?
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SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber";
What is Astrid Gruber's email and phone number?
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SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber";
What is the email and phone number of Astrid Gruber the customer?
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SELECT count(*) FROM customers WHERE city = "Prague";
How many customers live in Prague city?
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SELECT count(*) FROM customers WHERE city = "Prague";
How many customers live in the city of Prague?
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SELECT count(*) FROM customers WHERE state = "CA";
How many customers in state of CA?
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SELECT count(*) FROM customers WHERE state = "CA";
How many customers are from California?
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SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida";
What country does Roberto Almeida live?
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SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida";
In which country does Roberto Almeida?
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SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'
List the name of albums that are released by aritist whose name has 'Led'
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SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%'
What is the title of the album that was released by the artist whose name has the phrase 'Led'?
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SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson";
How many customers does Steve Johnson support?
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SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson";
What is the count of customers that Steve Johnson supports?
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SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
What is the title, phone and hire date of Nancy Edwards?
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SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
What is the title, phone number and hire date for the employee named Nancy Edwards?
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SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards";
find the full name of employees who report to Nancy Edwards?
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SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards";
What is the first and last name of the employee who reports to Nancy Edwards?
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SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
What is the address of employee Nancy Edwards?
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SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
What is Nancy Edwards's address?
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SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
Find the full name of employee who supported the most number of customers.
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SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
What is the full name of the employee who has the most customers?
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SELECT count(*) FROM employees WHERE country = "Canada";
How many employees are living in Canada?
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SELECT count(*) FROM employees WHERE country = "Canada";
How many employees live in Canada?
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SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
What is employee Nancy Edwards's phone number?
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SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards";
What is the the phone number of Nancy Edwards?
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SELECT first_name , last_name FROM employees ORDER BY birth_date DESC LIMIT 1;
Who is the youngest employee in the company? List employee's first and last name.
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