/*
--- Day 7: The Treachery of Whales ---

A giant whale has decided your submarine is its next meal, and it's much faster than you are.
There's nowhere to run!

Suddenly, a swarm of crabs (each in its own tiny submarine - it's too deep for them otherwise) zooms
in to rescue you! They seem to be preparing to blast a hole in the ocean floor; sensors indicate a
massive underground cave system just beyond where they're aiming!

The crab submarines all need to be aligned before they'll have enough power to blast a large enough
hole for your submarine to get through. However, it doesn't look like they'll be aligned before the
whale catches you! Maybe you can help?

There's one major catch - crab submarines can only move horizontally.

You quickly make a list of the horizontal position of each crab (your puzzle input). Crab submarines
have limited fuel, so you need to find a way to make all of their horizontal positions match while
requiring them to spend as little fuel as possible.

For example, consider the following horizontal positions:

```
16,1,2,0,4,2,7,1,2,14
```

This means there's a crab with horizontal position 16, a crab with horizontal position 1, and so on.

Each change of 1 step in horizontal position of a single crab costs 1 fuel. You could choose any
horizontal position to align them all on, but the one that costs the least fuel is horizontal
position 2:

- Move from 16 to 2: 14 fuel
- Move from 1 to 2: 1 fuel
- Move from 2 to 2: 0 fuel
- Move from 0 to 2: 2 fuel
- Move from 4 to 2: 2 fuel
- Move from 2 to 2: 0 fuel
- Move from 7 to 2: 5 fuel
- Move from 1 to 2: 1 fuel
- Move from 2 to 2: 0 fuel
- Move from 14 to 2: 12 fuel

This costs a total of 37 fuel. This is the cheapest possible outcome; more expensive outcomes
include aligning at position 1 (41 fuel), position 3 (39 fuel), or position 10 (71 fuel).

Determine the horizontal position that the crabs can align to using the least fuel possible. How
much fuel must they spend to align to that position?
*/

package com.curtislb.adventofcode.year2021.day07.part1

import com.curtislb.adventofcode.common.number.medianOrNull
import com.curtislb.adventofcode.common.parse.parseInts
import java.nio.file.Path
import java.nio.file.Paths
import kotlin.math.abs

/**
 * Returns the solution to the puzzle for 2021, day 7, part 1.
 *
 * @param inputPath The path to the input file for this puzzle.
 */
fun solve(inputPath: Path = Paths.get("..", "input", "input.txt")): Int {
    val positions = inputPath.toFile().readText().parseInts()
    val bestPosition = positions.medianOrNull() ?: 0
    return positions.sumOf { abs(it - bestPosition) }
}

fun main() {
    println(solve())
}

/*
--- Day 7: The Treachery of Whales ---

A giant whale has decided your submarine is its next meal, and it's much faster than you are.
There's nowhere to run!

Suddenly, a swarm of crabs (each in its own tiny submarine - it's too deep for them otherwise) zooms
in to rescue you! They seem to be preparing to blast a hole in the ocean floor; sensors indicate a
massive underground cave system just beyond where they're aiming!

The crab submarines all need to be aligned before they'll have enough power to blast a large enough
hole for your submarine to get through. However, it doesn't look like they'll be aligned before the
whale catches you! Maybe you can help?

There's one major catch - crab submarines can only move horizontally.

You quickly make a list of the horizontal position of each crab (your puzzle input). Crab submarines
have limited fuel, so you need to find a way to make all of their horizontal positions match while
requiring them to spend as little fuel as possible.

For example, consider the following horizontal positions:

```
16,1,2,0,4,2,7,1,2,14
```

This means there's a crab with horizontal position 16, a crab with horizontal position 1, and so on.

Each change of 1 step in horizontal position of a single crab costs 1 fuel. You could choose any
horizontal position to align them all on, but the one that costs the least fuel is horizontal
position 2:

- Move from 16 to 2: 14 fuel
- Move from 1 to 2: 1 fuel
- Move from 2 to 2: 0 fuel
- Move from 0 to 2: 2 fuel
- Move from 4 to 2: 2 fuel
- Move from 2 to 2: 0 fuel
- Move from 7 to 2: 5 fuel
- Move from 1 to 2: 1 fuel
- Move from 2 to 2: 0 fuel
- Move from 14 to 2: 12 fuel

This costs a total of 37 fuel. This is the cheapest possible outcome; more expensive outcomes
include aligning at position 1 (41 fuel), position 3 (39 fuel), or position 10 (71 fuel).

Determine the horizontal position that the crabs can align to using the least fuel possible. How
much fuel must they spend to align to that position?
*/

package com.curtislb.adventofcode.year2021.day07.part1

import com.curtislb.adventofcode.common.number.medianOrNull
import com.curtislb.adventofcode.common.parse.parseInts
import java.nio.file.Path
import java.nio.file.Paths
import kotlin.math.abs

/**
 * Returns the solution to the puzzle for 2021, day 7, part 1.
 *
 * @param inputPath The path to the input file for this puzzle.
 */
fun solve(inputPath: Path = Paths.get("..", "input", "input.txt")): Int {
    val positions = inputPath.toFile().readText().parseInts()
    val bestPosition = positions.medianOrNull() ?: 0
    return positions.sumOf { abs(it - bestPosition) }
}

fun main() {
    println(solve())
}
