
import java.util.Arrays
import java.util.HashSet


/**
 * Scores 100/100
 * @param A
 * @return
 */
fun solution(A: IntArray?): Int {
    return Arrays.stream(A).distinct().toArray().size
}

/**
 * Manual solution
 */
fun solution2(A: IntArray): Int {
    val unique: HashSet<Int> = HashSet<Int>()
    for (i in A.indices) {
        unique.add(A[i])
    }
    return unique.size
}


/**
 * Write a function
 *
 * class Solution { public int solution(int[] A); }
 *
 * that, given an array A consisting of N integers, returns the number of distinct values in array A.
 *
 * For example, given array A consisting of six elements such that:
 *
 *  A[0] = 2    A[1] = 1    A[2] = 1
 *  A[3] = 2    A[4] = 3    A[5] = 1
 * the function should return 3, because there are 3 distinct values appearing in array A, namely 1, 2 and 3.
 *
 * Write an efficient algorithm for the following assumptions:
 *
 * N is an integer within the range [0..100,000];
 * each element of array A is an integer within the range [−1,000,000..1,000,000].
 */

import java.util.Arrays
import java.util.HashSet


/**
 * Scores 100/100
 * @param A
 * @return
 */
fun solution(A: IntArray?): Int {
    return Arrays.stream(A).distinct().toArray().size
}

/**
 * Manual solution
 */
fun solution2(A: IntArray): Int {
    val unique: HashSet<Int> = HashSet<Int>()
    for (i in A.indices) {
        unique.add(A[i])
    }
    return unique.size
}


/**
 * Write a function
 *
 * class Solution { public int solution(int[] A); }
 *
 * that, given an array A consisting of N integers, returns the number of distinct values in array A.
 *
 * For example, given array A consisting of six elements such that:
 *
 *  A[0] = 2    A[1] = 1    A[2] = 1
 *  A[3] = 2    A[4] = 3    A[5] = 1
 * the function should return 3, because there are 3 distinct values appearing in array A, namely 1, 2 and 3.
 *
 * Write an efficient algorithm for the following assumptions:
 *
 * N is an integer within the range [0..100,000];
 * each element of array A is an integer within the range [−1,000,000..1,000,000].
 */