/**
 * You have a RecentCounter class which counts the number of recent requests within a certain time frame.
 *
 * Implement the RecentCounter class:
 *
 * RecentCounter() Initializes the counter with zero recent requests.
 * int ping(int t) Adds a new request at time t, where t represents some time in milliseconds,
 * and returns the number of requests that has happened in the past 3000 milliseconds (including the new request).
 * Specifically, return the number of requests that have happened in the inclusive range [t - 3000, t].
 * It is guaranteed that every call to ping uses a strictly larger value of t than the previous call.
 *
 *
 *
 * Example 1:
 *
 * Input
 * ["RecentCounter", "ping", "ping", "ping", "ping"]
 * [[], [1], [100], [3001], [3002]]
 * Output
 * [null, 1, 2, 3, 3]
 *
 * Explanation
 * RecentCounter recentCounter = new RecentCounter();
 * recentCounter.ping(1);     // requests = [1], range is [-2999,1], return 1
 * recentCounter.ping(100);   // requests = [1, 100], range is [-2900,100], return 2
 * recentCounter.ping(3001);  // requests = [1, 100, 3001], range is [1,3001], return 3
 * recentCounter.ping(3002);  // requests = [1, 100, 3001, 3002], range is [2,3002], return 3
 *
 *
 * Constraints:
 *
 * 1 <= t <= 10^9
 * Each test case will call ping with strictly increasing values of t.
 * At most 10^4 calls will be made to ping.
 * @see <a href="https://leetcode.com/problems/number-of-recent-calls/">LeetCode</a>
 */
class RecentCounter() {

    val requests = mutableListOf<Int>()

    fun ping(t: Int): Int {
        requests.add(t)

        while (requests.first() < t - 3000) {
            requests.removeFirst()
        }

        return requests.size
    }
}

/**
 * Your RecentCounter object will be instantiated and called as such:
 * var obj = RecentCounter()
 * var param_1 = obj.ping(t)
 */

/**
 * You have a RecentCounter class which counts the number of recent requests within a certain time frame.
 *
 * Implement the RecentCounter class:
 *
 * RecentCounter() Initializes the counter with zero recent requests.
 * int ping(int t) Adds a new request at time t, where t represents some time in milliseconds,
 * and returns the number of requests that has happened in the past 3000 milliseconds (including the new request).
 * Specifically, return the number of requests that have happened in the inclusive range [t - 3000, t].
 * It is guaranteed that every call to ping uses a strictly larger value of t than the previous call.
 *
 *
 *
 * Example 1:
 *
 * Input
 * ["RecentCounter", "ping", "ping", "ping", "ping"]
 * [[], [1], [100], [3001], [3002]]
 * Output
 * [null, 1, 2, 3, 3]
 *
 * Explanation
 * RecentCounter recentCounter = new RecentCounter();
 * recentCounter.ping(1);     // requests = [1], range is [-2999,1], return 1
 * recentCounter.ping(100);   // requests = [1, 100], range is [-2900,100], return 2
 * recentCounter.ping(3001);  // requests = [1, 100, 3001], range is [1,3001], return 3
 * recentCounter.ping(3002);  // requests = [1, 100, 3001, 3002], range is [2,3002], return 3
 *
 *
 * Constraints:
 *
 * 1 <= t <= 10^9
 * Each test case will call ping with strictly increasing values of t.
 * At most 10^4 calls will be made to ping.
 * @see <a href="https://leetcode.com/problems/number-of-recent-calls/">LeetCode</a>
 */
class RecentCounter() {

    val requests = mutableListOf<Int>()

    fun ping(t: Int): Int {
        requests.add(t)

        while (requests.first() < t - 3000) {
            requests.removeFirst()
        }

        return requests.size
    }
}

/**
 * Your RecentCounter object will be instantiated and called as such:
 * var obj = RecentCounter()
 * var param_1 = obj.ping(t)
 */
