This is a real-world medical entrance exam question, please give the true answer based on the question and selection. Topic name: None, Subject name: Biochemistry
[{'content': 'Energy released by oxidation of 1 mole of acetyl CoA is: \nSelect and explain. \nA. 6 ATP, B. 8 ATP, C. 10 ATP, D. 15 ATP', 'role': 'user'}, {'content': 'Answer: C \nExplanation: Transpo in the respiratory chain of electrons from FADH2 and NADH leads to the synthesis of four high-energy phosphates for each of the seven cycles needed for the breakdown of palmitate to acetyl-CoA (7 x 4 = 28). A total of 8 mol of acetyl-CoA is formed, and each gives rise to 10 mol of ATP on oxidation in the citric acid cycle, making 8 x 10 = 80 mol. Two must be subtracted for the initial activation of the fatty acid, yielding a net gain of 106 mol of ATP per mole of palmitate, or 106 x 51.6 = 5470 kJ. This represents 68% of the free energy of combustion of palmitic acid. Ref: Harper 28th edition, chapter 22.', 'role': 'assistant'}]