This is a real-world medical entrance exam question, please give the true answer based on the question and selection. Topic name: All India exam, Subject name: Microbiology
[{'content': 'The postoperative quality of life (QOL) scores of 200 prostate cancer patients have a mean of 60 and a standard detion of 10. How many patients are expected to have a QOL score between 40 and 80? \nSelect and explain. \nA. 190, B. 136, C. 120, D. 140', 'role': 'user'}, {'content': 'Answer: A \nExplanation: The values enclosed in a normal distribution curve are:Mean +- 1 SD 68% of data Mean +- 2 SD 95% of dataMean +- 3 SD 99% of dataIn the above question,Mean = 60SD = 10Hence, the range of values from 40 to 80 i.e. 60 +- 20 (Mean +- 2 SD) would include 95% of the readings.Therefore, the total number of readings in the given range = (95 x 200) / 100 = 190Hence, 190 patients are expected to have a QOL score between 40 and 80.', 'role': 'assistant'}]