This is a real-world medical entrance exam question, please give the true answer based on the question and selection. Topic name: Biostatistics, Subject name: Social & Preventive Medicine
[{'content': 'Chance of passing a genetic disease &;y&; trait by the affected parents to children is 0.16. They plan to have two children. Prabability of both the children having &;y&; trait is - \nSelect and explain. \nA. zero, B. 0.16, C. 0.32, D. 0.0256', 'role': 'user'}, {'content': 'Answer: D \nExplanation: <p> In the given question, chance of passing a Genetic disease &;y&; trait by the affected parents to children is 0.16 and they plan to have two children, Probability of 1st child having &;y&; trait P(A)=0.16(16%). Probability of 2nd child having &;y&; trait,P(B)= 0.16(16%). Probability of both the children having &;y&; trait is. P( total)=P(A)+P(B). P(total)=0.16*0.16=0.0256(2.56%). Reference:Simple Biostatistics by Indrayan & Indrayan,1st edition,pg no:105-107. <\\p>', 'role': 'assistant'}]