I have recently started learning more about complex numbers and stumbled upon this problem:

Plot the numbers $z$ in the complex plane that fulfil $|z-2i| ≤ 1$ and $\text{Im} (z) ≥ 2$

I know that $\text{Im}(z) ≥ 2$ means that all imaginary numbers who are positioned somewhere on the horizontal line $\text{Im} = 2$ or above the line can be plotted. However I’m not quite sure what $ |z-2i| ≤ 1 $ means. I understand that if I only had $|z| ≤ 1$ that would mean I can plot all numbers inside a circle with the radius $1$ including the ones on the circles circumference. But I don’t really understand what the term $-2i$ does to the circle. I compared it to other similar questions and came to the conclusion that the centre should be at $2i$ instead of $0$. My problem is that I don’t quite understand why the circle gets a centre at $2i$ and not at $-2i$. Thankful for any help and explanation.
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Let's write z=x+iy and then the inequality $ |z-2i|\leq1$ becomes $ |x+(y-2)i|\leq1 $ so we get $x^2+(y-2)^2 \leq 1$. Can you see it now?
Hint let $z=x+iy$ so equation on squaring becomes $x^2+(y-2)^2\leq 1$. Now do you understand why is it $+2i$