Can I do this in C++ (if yes, what is the syntax?):

```
void func(string* strs) {
    // do something
}
func({"abc", "cde"});

```

I want to pass an array to a function, without instantiating it as a variable.
['https://Stackoverflow.com/questions/2767139', 'https://Stackoverflow.com', 'https://Stackoverflow.com/users/187141/']
It can't be done in the current C++, as defined by C++03.

The feature you are looking for is called "compound literals". It is present in C language, as defined by C99 (with C-specific capabilities, of course), but not in C++.

A similar feature is planned for C++ as well, but it is not there yet.
As written, you can't do this. The function expects a pointer-to-string. Even if you were able to pass an array as a literal, the function call would generate errors because literals are considered constant (thus, the array of literals would be of type `const string*`, not `string*` as the function expects).