I have made this mouse hover image zoom page. But I want the output to be shown on the left side and only when someone hovers the mouse on it. In this code the output window is continuously opened.

HERE IS MY CODE:

```js
function imageZoom(imgID, resultID) {
  var img, lens, result, cx, cy;
  img = document.getElementById(imgID);
  result = document.getElementById(resultID);
  /*create lens:*/
  lens = document.createElement("DIV");
  lens.setAttribute("class", "img-zoom-lens");
  /*insert lens:*/
  img.parentElement.insertBefore(lens, img);
  /*calculate the ratio between result DIV and lens:*/
  cx = result.offsetWidth / lens.offsetWidth;
  cy = result.offsetHeight / lens.offsetHeight;
  /*set background properties for the result DIV:*/
  result.style.backgroundImage = "url('" + img.src + "')";
  result.style.backgroundSize = (img.width * cx) + "px " + (img.height * cy) + "px";
  /*execute a function when someone moves the cursor over the image, or the lens:*/
  lens.addEventListener("mousemove", moveLens);
  img.addEventListener("mousemove", moveLens);
  /*and also for touch screens:*/
  lens.addEventListener("touchmove", moveLens);
  img.addEventListener("touchmove", moveLens);

  function moveLens(e) {
    var pos, x, y;
    /*prevent any other actions that may occur when moving over the image:*/
    e.preventDefault();
    /*get the cursor's x and y positions:*/
    pos = getCursorPos(e);
    /*calculate the position of the lens:*/
    x = pos.x - (lens.offsetWidth / 2);
    y = pos.y - (lens.offsetHeight / 2);
    /*prevent the lens from being positioned outside the image:*/
    if (x > img.width - lens.offsetWidth) {
      x = img.width - lens.offsetWidth;
    }
    if (x < 0) {
      x = 0;
    }
    if (y > img.height - lens.offsetHeight) {
      y = img.height - lens.offsetHeight;
    }
    if (y < 0) {
      y = 0;
    }
    /*set the position of the lens:*/
    lens.style.left = x + "px";
    lens.style.top = y + "px";
    /*display what the lens "sees":*/
    result.style.backgroundPosition = "-" + (x * cx) + "px -" + (y * cy) + "px";
  }

  function getCursorPos(e) {
    var a, x = 0,
      y = 0;
    e = e || window.event;
    /*get the x and y positions of the image:*/
    a = img.getBoundingClientRect();
    /*calculate the cursor's x and y coordinates, relative to the image:*/
    x = e.pageX - a.left;
    y = e.pageY - a.top;
    /*consider any page scrolling:*/
    x = x - window.pageXOffset;
    y = y - window.pageYOffset;
    return {
      x: x,
      y: y
    };
  }
}

// Initiate zoom effect:
imageZoom("myimage", "myresult");
```

```css
* {
  box-sizing: border-box;
}

.img-zoom-container {
  position: relative;
}

.img-zoom-lens {
  position: absolute;
  border: 1px solid #d4d4d4;
  /*set the size of the lens:*/
  width: 40px;
  height: 40px;
}

.img-zoom-result {
  border: 1px solid #d4d4d4;
  /*set the size of the result div:*/
  width: 300px;
  height: 300px;
}
```

```html
<h1>Image Zoom</h1>

<p>Mouse over the image:</p>

<div class="img-zoom-container">
  <img id="myimage" src="img_girl.jpg" width="300" height="240">
  <div id="myresult" class="img-zoom-result"></div>
</div>

<p>The image must be placed inside a container with relative positioning.</p>
<p>The result can be put anywhere on the page, but must have the class name "img-zoom-result".</p>
<p>Make sure both the image and the result have IDs. These IDs are used when a javaScript initiates the zoom effect.</p>
```

The code is working perfectly, but the result should be on the right and it should be only shown when user hovers the mouse on it.
['https://Stackoverflow.com/questions/63146323', 'https://Stackoverflow.com', 'https://Stackoverflow.com/users/13993822/']
You can't set that flag. It's managed by Firebase Auth. My guess for the reason that it's always set true by default (for Google auth, as you imply here) is that Google manages the email verification scheme for their own accounts. You can be sure that, if you get an email address for a Google account, the email does in fact work and belong to the user.
As i can see that you are using google login , So if someone logins through google the email is already verified . If you want to send verification mail use email/password signin .