I have 2 pages when button in page1 is clicked it will linked to the page 2, then the page2 will load with transition. The page loads with fade in and doesnt work with slidedown.

```
$(document).ready(function() {
            $("body").css("display", "none");
            $("body").fadeIn(2000);

    });

```

The code above works well,but the below doesnt work:

```
$(document).ready(function() {
            $("body").css("display", "none");
            $("body").slideDown(2000);

    });

```

My full code

```
<meta http-equiv="Page-Enter" content="blendTrans(Duration=1.0)">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>About</title>
<script type="text/javascript" src="C:/Users/jovine/Desktop/Anything/BAS/jquery.min.js"></script>
<script type="text/javascript" src="C:/Users/jovine/Desktop/Anything/BAS/jquery.fullbg.min.js"></script>
<link type="text/css" rel="stylesheet" href="basabout.css" media="all" />

<script type="text/javascript">
$(window).load(function(){ 
            $("body").slideUp(1).delay(2000).slideDown('slow');

});
</script>
</head>

<body>

<img class="fullbg" src="background2.png" id="background" style="z-index:-9999; " />

<script type="text/javascript">
$(window).load(function() {
    $("#background").fullBg();
});
</script>

<div id="header" class="header">
<img class="title" src="aboutus.png">
<br>
<img class="triangle" src="triangle.png">
</div>
<div id="content" class="content">
    <img class="subtitle" src="about.png">
    <br />
    <p class="subtitle_content">We are the voice of the Beauty industry in Singapore.
    <hr class="divider">
        <div class="logo">
        <img src="peoples.png" style="margin-left:70px;">
        <img src="roll.png" style="margin-left:340px;">
        <img src="mic.png" style="margin-left:440px;">
        </div>
        <div class="logo_title">
        <img src="whoarewe.png" style="margin-left:40px;">
        <img src="whatwedo.png" style="margin-left:320px;">
        <img src="whatscomingup.png" style="margin-left:420px;">
        </div>
        <div id="logo_content" class="logo_content">
        <p class="content1">BAS stand for Beauty Association of<br>Singapore. BAS was built to contribute<br>to the development, advancement and<br>prestige of the Beauty industry in<br>Singapore.</p>
        <p class="content2">We are inspired by purpose, and we<br>strive to be the voice of the burgeoning<br>Beauty industry in Singapore.</p>
        <p class="content3">STAY TUNED!</p>
        </div>

</div>
</body>
</html>

```
['https://Stackoverflow.com/questions/18226698', 'https://Stackoverflow.com', 'https://Stackoverflow.com/users/2681621/']
Have you tried using shutil?

```
import shutil
shutil.copy(src, dst)

```
There may be a problem with the way Python is passing the arguments to the shell command. Try using [subprocess.call](http://docs.python.org/2/library/subprocess.html#using-the-subprocess-module). This method takes arguments as an array and passes them that way to the command:

```
import subprocess
subprocess.call(["copy", "/b", '"imgFile.jpg" + "zipFile.zip"', "newImage.jpg"])

```