func Sprintln(a ...interface{}) string {
	return fmt.Sprintln(convertArgs(a)...)
}
Sprintln is a wrapper for fmt.Sprintln that treats each argument as if it
were passed with a default Formatter interface returned by NewFormatter.  It
returns the resulting string.  See NewFormatter for formatting details.

This function is shorthand for the following syntax:

fmt.Sprintln(spew.NewFormatter(a), spew.NewFormatter(b))
package spew
import (
	"fmt"
	"io"
)
func Errorf(format string, a ...interface{}) (err error) {
	return fmt.Errorf(format, convertArgs(a)...)
}
func Fprint(w io.Writer, a ...interface{}) (n int, err error) {
	return fmt.Fprint(w, convertArgs(a)...)
}
func Fprintf(w io.Writer, format string, a ...interface{}) (n int, err error) {
	return fmt.Fprintf(w, format, convertArgs(a)...)
}
func Fprintln(w io.Writer, a ...interface{}) (n int, err error) {
	return fmt.Fprintln(w, convertArgs(a)...)
}
func Print(a ...interface{}) (n int, err error) {
	return fmt.Print(convertArgs(a)...)
}
func Printf(format string, a ...interface{}) (n int, err error) {
	return fmt.Printf(format, convertArgs(a)...)
}
func Println(a ...interface{}) (n int, err error) {
	return fmt.Println(convertArgs(a)...)
}
func Sprint(a ...interface{}) string {
	return fmt.Sprint(convertArgs(a)...)
}
func Sprintf(format string, a ...interface{}) string {
	return fmt.Sprintf(format, convertArgs(a)...)
}