<jupyter_start><jupyter_text>问题描述判断一个整数是否为回文数, 不要使用额外的内存  实现<jupyter_code># 方法一
def is_palindrome(x):
    """
    :type x: int
    :rtype: bool
    """
    if x < 0:
        return False
    return x == int(str(x)[::-1])

is_palindrome(123454321)
# 方法二
def is_palindrome(x):
    """
    :type x: int
    :rtype: bool
    """
    if x < 0:
        return False
    base = 1
    while x / base >= 10:
        base *= 10
    while x:
        left = x // base
        right = x % 10
        if left != right:
            return False
        x = (x % base) // 10
        base = base / 100
    return True    
    
is_palindrome(123454321)<jupyter_output><empty_output>
{'fraction_non_alphanumeric': 0.12349397590361445, 'fraction_numerical': 0.04969879518072289, 'mean_word_length': 1.7708333333333333, 'pattern_counts': {'":': 0, '<': 7, '<?xml version=': 0, '>': 6, 'https://': 0, 'lorem ipsum': 0, 'www.': 0, 'xml': 0}, 'pii_count': 0, 'substrings_counts': 0, 'word_list_counts': {'cursed_substrings.json': 0, 'profanity_word_list.json': 0, 'sexual_word_list.json': 0, 'zh_pornsignals.json': 0}}
{'chain_length': '1', 'dir': 'jupyter-structured-clean-dedup', 'id': '614937', 'license': 'MIT', 'n_tokens_mistral': 296, 'n_tokens_neox': 273, 'n_words': 64, 'path': 'palindrome_number.ipynb', 'repo_name': '12ff806/algorithms', 'size': '664'}