<jupyter_start><jupyter_text>Given an integer n, return a string array answer (1-indexed) where:- answer[i] == "FizzBuzz" if i is divisible by 3 and 5.- answer[i] == "Fizz" if i is divisible by 3.- answer[i] == "Buzz" if i is divisible by 5.- answer[i] == i (as a string) if none of the above conditions are true. Example 1:Input: n = 3\Output: ["1","2","Fizz"]Example 2:Input: n = 5\Output: ["1","2","Fizz","4","Buzz"]Example 3:Input: n = 15\Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"] Constraints:$1 \leq n \leq 10^4$<jupyter_code>class Solution:
    def fizzBuzz(self, n: int):
        res = [i for i in range(1,n+1)]

        final = []
        for i in range(len(res)):

            if res[i] % 3 == 0 and res[i] % 5 == 0:
                final.append('FizzBuzz')
                continue

            if res[i] % 3 == 0:
                final.append('Fizz')
                continue

            if res[i] % 5 == 0:
                final.append('Buzz')
                continue

            final.append(str(res[i]))

        return(final)
                
x = Solution()
x.fizzBuzz(15)<jupyter_output><empty_output>
{'fraction_non_alphanumeric': 0.18197278911564627, 'fraction_numerical': 0.03741496598639456, 'mean_word_length': 2.34375, 'pattern_counts': {'":': 0, '<': 5, '<?xml version=': 0, '>': 5, 'https://': 0, 'lorem ipsum': 0, 'www.': 0, 'xml': 0}, 'pii_count': 0, 'substrings_counts': 0, 'word_list_counts': {'cursed_substrings.json': 0, 'profanity_word_list.json': 0, 'sexual_word_list.json': 0, 'zh_pornsignals.json': 0}}
{'chain_length': '1', 'dir': 'jupyter-structured-clean-dedup', 'id': '521574', 'license': 'MIT', 'n_tokens_mistral': 443, 'n_tokens_neox': 402, 'n_words': 111, 'path': '412FizzBuzz.ipynb', 'repo_name': 'AndrewM1130/leetcode', 'size': '1176'}