<jupyter_start><jupyter_text>基本程序设计- 一切代码输入，请使用英文输入法  编写一个简单的程序- 圆公式面积： area = radius \* radius \* 3.1415  在Python里面不需要定义数据的类型  控制台的读取与输入- input 输入进去的是字符串- eval - 在jupyter用shift + tab 键可以跳出解释文档  变量命名的规范- 由字母、数字、下划线构成- 不能以数字开头 \*- 标识符不能是关键词(实际上是可以强制改变的，但是对于代码规范而言是极其不适合)- 可以是任意长度- 驼峰式命名  变量、赋值语句和赋值表达式- 变量: 通俗理解为可以变化的量- x = 2 \* x + 1 在数学中是一个方程，而在语言中它是一个表达式- test = test + 1 \* 变量在赋值之前必须有值  同时赋值var1, var2,var3... = exp1,exp2,exp3...  定义常量- 常量：表示一种定值标识符，适合于多次使用的场景。比如PI- 注意：在其他低级语言中如果定义了常量，那么，该常量是不可以被改变的，但是在Python中一切皆对象，常量也是可以被改变的  数值数据类型和运算符- 在Python中有两种数值类型（int 和 float）适用于加减乘除、模、幂次  运算符 /、//、**  运算符 %  EP：- 25/4 多少，如果要将其转变为整数该怎么改写- 输入一个数字判断是奇数还是偶数- 进阶: 输入一个秒数，写一个程序将其转换成分和秒：例如500秒等于8分20秒- 进阶: 如果今天是星期六，那么10天以后是星期几？ 提示：每个星期的第0天是星期天  科学计数法- 1.234e+2- 1.234e-2  计算表达式和运算优先级  增强型赋值运算  类型转换- float  -> int- 四舍五入 round  EP:- 如果一个年营业税为0.06%，那么对于197.55e+2的年收入，需要交税为多少？(结果保留2为小数)- 必须使用科学计数法  Project- 用Python写一个贷款计算器程序：输入的是月供(monthlyPayment) 输出的是总还款数(totalpayment)![](../Photo/05.png)  Homework- 1<jupyter_code>celsius = int(input('Enter a degree in Celsius:'))
fahrenheit = (9 / 5.0) * celsius + 32
print('{} Celsius is {} Fahrenheit'.format(celsius,fahrenheit))<jupyter_output>Enter a degree in Celsius:43
43 Celsius is 109.4 Fahrenheit<jupyter_text>- 2<jupyter_code>import math
radius,length=map(float,input('Enter the radius and length of a cylinder:').split())
area = radius * radius * math.pi
volume = area * length 
print('The area is {}'.format('%.4f' % area))
print('The volume is {}'.format('%.1f' % volume))<jupyter_output>Enter the radius and length of a cylinder:5.5 12
The area is 95.0332
The volume is 1140.4<jupyter_text>- 3<jupyter_code>feet = float(input('Enter a value for feet:'))
meters = feet * 0.305
print('{} feet is {} meters'.format(feet,meters))<jupyter_output>Enter a value for feet:16.5
16.5 feet is 5.0325 meters<jupyter_text>- 4<jupyter_code>M = float(input('Enter the amount of water in kilograms:'))
initialTemperature = float(input('Enter the initial temperature:'))
finalTemperature = float(input('Enter the final temperature:'))
Q = M * (finalTemperature - initialTemperature) * 4184
print('The energy needed is {}'.format(Q))<jupyter_output>Enter the amount of water in kilograms:55.5
Enter the initial temperature:3.5
Enter the final temperature:10.5
The energy needed is 1625484.0<jupyter_text>- 5<jupyter_code>balance,interest = map(float,input('Enter balance and interest rate (e.g.,3 for 3%):').split())
L = balance * (interest / 1200)
print('The interest is {}'.format('%.5f' % L))<jupyter_output>Enter balance and interest rate (e.g.,3 for 3%):1000 3.5
The interest is 2.91667<jupyter_text>- 6<jupyter_code>v0,v1,t= map(float,input('Enter v0,v1,and t:').split())
a = (v1 - v0)/t
print('The average accelration is {}'.format('%.4f' % a))<jupyter_output>Enter v0,v1,and t:5.5 50.9 4.5
The average accelration is 10.0889<jupyter_text>- 7 进阶<jupyter_code>amount = int(input('Enter the monthly saving amount:'))
count=0
for i in range(6):
    account_six = (amount + count) * (1 + 0.00417)
    count = account_six
print('After the sixth mount,the account value is {}'.format('%.2f' % count ))<jupyter_output>Enter the monthly saving amount:100
After the sixth mount,the account value is 608.82<jupyter_text>- 8 进阶<jupyter_code>number = int(input('Enter a number between 0 and 1000:'))
sum = (number % 10) + ((number // 10) % 10) + (number // 100)
print('The sum of the digits is {}'.format(sum))<jupyter_output>Enter a number between 0 and 1000:999
The sum of the digits is 27
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