<jupyter_start><jupyter_text>Given an array, rotate the array to the right by k steps, where k is non-negative.**Example 1:**    Input: [1,2,3,4,5,6,7] and k = 3    Output: [5,6,7,1,2,3,4]*Explanation:*    rotate 1 steps to the right: [7,1,2,3,4,5,6]    rotate 2 steps to the right: [6,7,1,2,3,4,5]    rotate 3 steps to the right: [5,6,7,1,2,3,4]**Example 2:**    Input: [-1,-100,3,99] and k = 2    Output: [3,99,-1,-100]*Explanation: *    rotate 1 steps to the right: [99,-1,-100,3]    rotate 2 steps to the right: [3,99,-1,-100]**Note:**- Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.- Could you do it in-place with O(1) extra space?  Thought1. Pop the last number and insert it into the head of the array2. Change the number's position directly.<jupyter_code>def rotate(self, nums, k):
    """
    :type nums: List[int]
    :type k: int
    :rtype: void Do not return anything, modify nums in-place instead.
    """
    for _ in range(k):
        tmp=nums.pop()
        nums.insert(0,tmp)
def rotate(self, nums, k):
    """
    :type nums: List[int]
    :type k: int
    :rtype: void Do not return anything, modify nums in-place instead.
    """
    nums[:k] ,nums[k:] = nums[len(nums)-k:] , nums[:len(nums)-k]<jupyter_output><empty_output>
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