<jupyter_start><jupyter_text>list, find the length, find elements between the second element and the 3rd from the end, use append, use remove<jupyter_code>list_1 = [1, 4, 8, 2, 0, 6, 9, 3, 5, 2]
len(list_1)
print(list_1[2:-3])
list_1.append("cat")
list_1
list_1.remove("cat")
list_1<jupyter_output><empty_output>
{'fraction_non_alphanumeric': 0.14102564102564102, 'fraction_numerical': 0.0641025641025641, 'mean_word_length': 6.825, 'pattern_counts': {'":': 0, '<': 5, '<?xml version=': 0, '>': 5, 'https://': 0, 'lorem ipsum': 0, 'www.': 0, 'xml': 0}, 'pii_count': 0, 'substrings_counts': 0, 'word_list_counts': {'cursed_substrings.json': 0, 'profanity_word_list.json': 0, 'sexual_word_list.json': 0, 'zh_pornsignals.json': 0}}
{'chain_length': '1', 'dir': 'jupyter-structured-clean-dedup', 'id': '641446', 'license': 'MIT', 'n_tokens_mistral': 140, 'n_tokens_neox': 129, 'n_words': 36, 'path': 'lesson 2.ipynb', 'repo_name': 'anpalana89/Econometrics2022', 'size': '312'}