<jupyter_start><jupyter_text>No gráfico abaixo, quero colocar um subplot só com o comportamento da alta tecnologia<jupyter_code>linestyles = ['-.','-.', '-.', '-.', '-.', '-.', 'solid', 'solid', 'solid', 'solid', 'solid', 'solid', 'dotted', 'dotted', 'dotted', 'dotted', 'dotted', 'dotted']

linecolors = ['#274E13','#38761D','#6AA84F','#93C47D', '#B45F06','#cb8934','#dba452','#FFE599','#351C75','#674EA7','#8E7CC3','#B4A7D6']

plt.figure(figsize=(15,10))
for i, linestyle, color in zip(range(len(df_aggregated.index)), linestyles, linecolors):
    plt.plot(df_aggregated.loc[df_aggregated.index[i]], linestyle=linestyle, linewidth=3)
plt.legend(df_aggregated.index,  loc='upper left', bbox_to_anchor=(1.05, 1));
plt.title('Personnel by Technological Level of Industry (2007-2015) \n');
#### df_aggregated['2007 a 2009 (%)'] = ((df_aggregated[2009] / df_aggregated[2007] - 1) * 100).values
df_aggregated['2009 a 2011 (%)'] = ((df_aggregated[2011] / df_aggregated[2009] - 1) * 100).values
df_aggregated['2011 a 2013 (%)'] = ((df_aggregated[2013] / df_aggregated[2011] - 1) * 100).values
df_aggregated['2013 a 2015 (%)'] = ((df_aggregated[2015] / df_aggregated[2013] - 1) * 100).values

df_aggregated<jupyter_output><empty_output>
{'fraction_non_alphanumeric': 0.21969080553295361, 'fraction_numerical': 0.11635475996745322, 'mean_word_length': 6.987012987012987, 'pattern_counts': {'":': 0, '<': 5, '<?xml version=': 0, '>': 5, 'https://': 0, 'lorem ipsum': 0, 'www.': 0, 'xml': 0}, 'pii_count': 0, 'substrings_counts': 0, 'word_list_counts': {'cursed_substrings.json': 0, 'profanity_word_list.json': 0, 'sexual_word_list.json': 0, 'zh_pornsignals.json': 0}}
{'chain_length': '1', 'dir': 'jupyter-structured-clean-dedup', 'id': '318988', 'license': 'MIT', 'n_tokens_mistral': 595, 'n_tokens_neox': 468, 'n_words': 83, 'path': 'app_rais/2 analysis_services.ipynb', 'repo_name': 'augustogeog/inovation_panel', 'size': '1229'}