<commit_before>def square_of_sum(number):
    pass


def sum_of_squares(number):
    pass


def difference_of_squares(number):
    pass
<commit_msg>Une solution à "Difference of Squares" dans la track Python de Exercism<commit_after>def square_of_sum(number):
    return sum(range(1, number+1))**2


def sum_of_squares(number):
    return sum([x**2 for x in range(1, number+1)])


def difference_of_squares(number):
    return square_of_sum(number) - sum_of_squares(number)

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