package com.fishercoder.solutions;

/**
 * 724. Find Pivot Index
 *
 * Given an array of integers nums, write a method that returns the "pivot" index of this array.
 * We define the pivot index as the index where the sum of the numbers to the left of the index is equal
 * to the sum of the numbers to the right of the index.
 * If no such index exists, we should return -1. If there are multiple pivot indexes, you should return the left-most pivot index.

 Example 1:
 Input:
 nums = [1, 7, 3, 6, 5, 6]
 Output: 3
 Explanation:
 The sum of the numbers to the left of index 3 (nums[3] = 6) is equal to the sum of numbers to the right of index 3.
 Also, 3 is the first index where this occurs.

 Example 2:
 Input:
 nums = [1, 2, 3]
 Output: -1
 Explanation:
 There is no index that satisfies the conditions in the problem statement.

 Note:
 The length of nums will be in the range [0, 10000].
 Each element nums[i] will be an integer in the range [-1000, 1000].
 */
public class _724 {
    public static class Solution1 {
        public int pivotIndex(int[] nums) {
            if (nums == null || nums.length == 0) {
                return -1;
            }
            int[] sums = new int[nums.length];
            sums[0] = nums[0];
            for (int i = 1; i < nums.length; i++) {
                sums[i] = sums[i - 1] + nums[i];
            }
            int result = -1;
            for (int i = 0; i < nums.length; i++) {
                if (i == 0 && 0 == sums[nums.length - 1] - sums[i] || (i > 0 && sums[i - 1] == sums[nums.length - 1] - sums[i])) {
                    result = i;
                    break;
                }
            }
            return result;
        }
    }
}

package com.fishercoder.solutions;

/**
 * 724. Find Pivot Index
 *
 * Given an array of integers nums, write a method that returns the "pivot" index of this array.
 * We define the pivot index as the index where the sum of the numbers to the left of the index is equal
 * to the sum of the numbers to the right of the index.
 * If no such index exists, we should return -1. If there are multiple pivot indexes, you should return the left-most pivot index.

 Example 1:
 Input:
 nums = [1, 7, 3, 6, 5, 6]
 Output: 3
 Explanation:
 The sum of the numbers to the left of index 3 (nums[3] = 6) is equal to the sum of numbers to the right of index 3.
 Also, 3 is the first index where this occurs.

 Example 2:
 Input:
 nums = [1, 2, 3]
 Output: -1
 Explanation:
 There is no index that satisfies the conditions in the problem statement.

 Note:
 The length of nums will be in the range [0, 10000].
 Each element nums[i] will be an integer in the range [-1000, 1000].
 */
public class _724 {
    public static class Solution1 {
        public int pivotIndex(int[] nums) {
            if (nums == null || nums.length == 0) {
                return -1;
            }
            int[] sums = new int[nums.length];
            sums[0] = nums[0];
            for (int i = 1; i < nums.length; i++) {
                sums[i] = sums[i - 1] + nums[i];
            }
            for (int i = 0; i < nums.length; i++) {
                if (i == 0 && 0 == sums[nums.length - 1] - sums[i] || (i > 0 && sums[i - 1] == sums[nums.length - 1] - sums[i])) {
                    return i;
                }
            }
            return -1;
        }
    }
}

refactor 724