package com.fishercoder.solutions;

/**
 * 760. Find Anagram Mappings
 *
 * Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.
 * We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.
 * These lists A and B may contain duplicates. If there are multiple answers, output any of them.

 For example, given

 A = [12, 28, 46, 32, 50]
 B = [50, 12, 32, 46, 28]

 We should return
 [1, 4, 3, 2, 0]
 as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.

 Note:

 A, B have equal lengths in range [1, 100].
 A[i], B[i] are integers in range [0, 10^5].
 */
public class _760 {
  public static class Solution1 {
    public int[] anagramMappings(int[] A, int[] B) {
      int[] result = new int[A.length];
      for (int i = 0; i < A.length; i++) {
        for (int j = 0; j < B.length; j++) {
          if (A[i] == B[j]) {
            result[i] = j;
          }
        }
      }
      return result;
    }
  }
}

package com.fishercoder.solutions;

public class _760 {
    public static class Solution1 {
        public int[] anagramMappings(int[] A, int[] B) {
            int[] result = new int[A.length];
            for (int i = 0; i < A.length; i++) {
                for (int j = 0; j < B.length; j++) {
                    if (A[i] == B[j]) {
                        result[i] = j;
                    }
                }
            }
            return result;
        }
    }
}

refactor 760