package com.stevesun.solutions;

/**
 * Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

 Integers in each row are sorted in ascending from left to right.
 Integers in each column are sorted in ascending from top to bottom.
 For example,

 Consider the following matrix:

 [
 [1,   4,  7, 11, 15],
 [2,   5,  8, 12, 19],
 [3,   6,  9, 16, 22],
 [10, 13, 14, 17, 24],
 [18, 21, 23, 26, 30]
 ]
 Given target = 5, return true.

 Given target = 20, return false.
 */
public class Searcha2DMatrixII {

    public boolean searchMatrix(int[][] matrix, int target) {
        int m = matrix.length;
        int n = matrix[0].length;
        int x = 0;
        int y = n - 1;
        while (x < m && y >= 0) {
            if (target == matrix[x][y]) {
                return true;
            } else if (target > matrix[x][y]) {
                x++;
            } else {
                y--;
            }
        }
        return false;
    }

}

package com.stevesun.solutions;

/**
 * Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

 Integers in each row are sorted in ascending from left to right.
 Integers in each column are sorted in ascending from top to bottom.
 For example,

 Consider the following matrix:

 [
 [1,   4,  7, 11, 15],
 [2,   5,  8, 12, 19],
 [3,   6,  9, 16, 22],
 [10, 13, 14, 17, 24],
 [18, 21, 23, 26, 30]
 ]
 Given target = 5, return true.

 Given target = 20, return false.
 */
public class Searcha2DMatrixII {

    public boolean searchMatrix(int[][] matrix, int target) {
        int m = matrix.length;
        int n = matrix[0].length;
        int x = 0;
        int y = n - 1;
        while (x < m && y >= 0) {
            if (target == matrix[x][y]) {
                return true;
            } else if (target > matrix[x][y]) {
                x++;
            } else {
                y--;
            }
        }
        return false;
    }
}

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