If prevalence of diabetes is 10%, the probability that three people selected at random from the population will have diabetes is -: (A) 0.01, (B) 0.03, (C) 0.001, (D) 0.003
Answer is C. Ref :Parks 23rd edition Prevalence = 10% So probability of selecting a person having DM = 10/100= 0.1 So probability of selecting 3 persons with diabetes = 0.1*0.1*0.1= 0.001