The population frequency for phenylketonuria is 1 in 10,000. What is the carrier frequency for the disease?: (A) Jan-50, (B) 1/100, (C) 1/500, (D) 1/1000
Answer is A. a. 1/50(Ref: Nelson's 20/e p 598)It is based on Hardy Weinberg principle: Simplifying it,Carrier frequency for an autosomal recessive disorder = twice the square root of disease incidenceSo 2 X square root of 1/10,000 gives 1/50 as the answer.