Gram-stained periorbital exudates in severe panophthalmitis with cellulitis in an elderly diabetic shows irregular branching aseptate and broad hyphae. Which of the following is the most likely diagnosis: (A) Candida, (B) Aspergillus, (C) Pencillium, (D) Apophysomyces species
Answer is D. Candida shows pseudohyphae. Aspergillus and Penicillium showed septate hyphae. Reference: Textbook of Microbiology; Baveja; 4th edition