There be many a land lubber that knows naught of the pirate ways and gives direction by degree!
They know not how to box the compass!



Task description

 Create a function that takes a heading in degrees and returns the correct 32-point compass heading.
 Use the function to print and display a table of Index, Compass point, and Degree; rather like the corresponding columns from, the first table of the wikipedia article, but use only the following 33 headings as input:
[0.0, 16.87, 16.88, 33.75, 50.62, 50.63, 67.5, 84.37, 84.38, 101.25, 118.12, 118.13, 135.0, 151.87, 151.88, 168.75, 185.62, 185.63, 202.5, 219.37, 219.38, 236.25, 253.12, 253.13, 270.0, 286.87, 286.88, 303.75, 320.62, 320.63, 337.5, 354.37, 354.38]. (They should give the same order of points but are spread throughout the ranges of acceptance).


Notes;
 The headings and indices can be calculated from this pseudocode:
for i in 0..32 inclusive:
    heading = i * 11.25
    case i %3:
      if 1: heading += 5.62; break
      if 2: heading -= 5.62; break
    end
    index = ( i mod 32) + 1
 The column of indices can be thought of as an enumeration of the thirty two cardinal points (see talk page)..


sub point (Int $index) {
    my $ix = $index % 32;
    if $ix +& 1
        { "&point(($ix + 1) +& 28) by &point(((2 - ($ix +& 2)) * 4) + $ix +& 24)" }
    elsif $ix +& 2
        { "&point(($ix + 2) +& 24)-&point(($ix +| 4) +& 28)" }
    elsif $ix +& 4
        { "&point(($ix + 8) +& 16)&point(($ix +| 8) +& 24)" }
    else
        { <north east south west>[$ix div 8]; }
}
 
sub test-angle ($ix) { $ix * 11.25 + (0, 5.62, -5.62)[ $ix % 3 ] }
sub angle-to-point(\𝜽) { floor 𝜽 / 360 * 32 + 0.5 }
 
for 0 .. 32 -> $ix {
    my \𝜽 = test-angle($ix);
    printf "  %2d %6.2f° %s\n",
              $ix % 32 + 1,
                  𝜽,
                         tc point angle-to-point 𝜽;
}