Task

Write a function/procedure/subroutine that is called with an integer value and returns the middle three digits of the integer if possible or a clear indication of an error if this is not possible.

Note: The order of the middle digits should be preserved.

Your function should be tested with the following values; the first line should return valid answers, those of the second line should return clear indications of an error:

123, 12345, 1234567, 987654321, 10001, -10001, -123, -100, 100, -12345
1, 2, -1, -10, 2002, -2002, 0

Show your output on this page.




'http://rosettacode.org/wiki/Middle_three_digits

Function mid3n(n)
	'Remove the number's sign.
	n = CStr(Abs(n))
	If Len(n) < 3 Or Len(n) Mod 2 = 0 Then
		mid3n = "Invalid: Either the length of n < 3 or an even number."
	ElseIf Round(Len(n)/2) > Len(n)/2 Then
		mid3n = Mid(n,Round(Len(n)/2)-1,3)
	Else
		mid3n = Mid(n,Round(Len(n)/2),3)
	End If
End Function
 
'Calling the function.
arrn = Array(123,12345,1234567,987654321,10001,-10001,-123,-100,100,-12345,_
			1,2,-1,-10,2002,-2002,0)
For Each n In arrn
	WScript.StdOut.Write n & ": " & mid3n(n)
	WScript.StdOut.WriteLine
Next