Task

Take a   Natural Number   in a given base and return the sum of its digits:

   110         sums to   1
   123410   sums to   10
   fe16       sums to   29
   f0e16     sums to   29


F sum_digits(=n, base)
   V r = 0
   L n > 0
      r += n % base
      n I/= base
   R r
 
print(sum_digits(1, 10))
print(sum_digits(1234, 10))
print(sum_digits(F'E, 16))
print(sum_digits(0F'0E, 16))