A friend of mine runs a pharmacy.   He has a specialized function in his Dispensary application which receives a decimal value of currency and replaces it to a standard value.   This value is regulated by a government department.



Task

Given a floating point value between   0.00   and   1.00,   rescale according to the following table:

>=  0.00  <  0.06  :=  0.10
>=  0.06  <  0.11  :=  0.18
>=  0.11  <  0.16  :=  0.26
>=  0.16  <  0.21  :=  0.32
>=  0.21  <  0.26  :=  0.38
>=  0.26  <  0.31  :=  0.44
>=  0.31  <  0.36  :=  0.50
>=  0.36  <  0.41  :=  0.54
>=  0.41  <  0.46  :=  0.58
>=  0.46  <  0.51  :=  0.62
>=  0.51  <  0.56  :=  0.66
>=  0.56  <  0.61  :=  0.70
>=  0.61  <  0.66  :=  0.74
>=  0.66  <  0.71  :=  0.78
>=  0.71  <  0.76  :=  0.82
>=  0.76  <  0.81  :=  0.86
>=  0.81  <  0.86  :=  0.90
>=  0.86  <  0.91  :=  0.94
>=  0.91  <  0.96  :=  0.98
>=  0.96  <  1.01  :=  1.00



 
const PFCUT = [6:5:101]//100
const PFVAL = [10:8:26, 32:6:50, 54:4:98, 100]//100
 
function pricefraction{T<:FloatingPoint}(a::T)
    zero(T) <= a || error("a = ", a, ", but it must be >= 0.")
    a <= one(T) || error("a = ", a, ", but it must be <= 1.")
    convert(T, PFVAL[findfirst(a .< PFCUT)])
end
 
test = [0.:0.05:1., 0.51, 0.56, 0.61, rand(), rand(), rand(), rand()]
 
println("Testing the price fraction function")
for t in test
    println(@sprintf "    %.4f -> %.4f" t pricefraction(t))
end
 