There are 100 doors in a row that are all initially closed.

You make 100 passes by the doors.

The first time through, visit every door and  toggle  the door  (if the door is closed,  open it;   if it is open,  close it).

The second time, only visit every 2nd door   (door #2, #4, #6, ...),   and toggle it.

The third time, visit every 3rd door   (door #3, #6, #9, ...), etc,   until you only visit the 100th door.



Task

Answer the question:   what state are the doors in after the last pass?   Which are open, which are closed?


Alternate:
As noted in this page's   discussion page,   the only doors that remain open are those whose numbers are perfect squares.

Opening only those doors is an   optimization   that may also be expressed;
however, as should be obvious, this defeats the intent of comparing implementations across programming languages.




 
--#SET TERMINATOR @
 
SET SERVEROUTPUT ON @
 
BEGIN
 DECLARE TYPE DOORS_ARRAY AS BOOLEAN ARRAY [100];
 DECLARE DOORS DOORS_ARRAY;
 DECLARE I SMALLINT;
 DECLARE J SMALLINT;
 DECLARE STATUS CHAR(10);
 DECLARE SIZE SMALLINT DEFAULT 100;
 
 -- Initializes the array, with all spaces (doors) as false (closed).
 SET I = 1;
 WHILE (I <= SIZE) DO
  SET DOORS[I] = FALSE;
  SET I = I + 1;
 END WHILE;
 
 -- Processes the doors.
 SET I = 1;
 WHILE (I <= SIZE) DO
  SET J = 1;
  WHILE (J <= SIZE) DO
   IF (MOD(J, I) = 0) THEN
    IF (DOORS[J] = TRUE) THEN
     SET DOORS[J] = FALSE;
    ELSE
     SET DOORS[J] = TRUE;
    END IF;
   END IF;
   SET J = J + 1;
  END WHILE;
  SET I = I + 1;
 END WHILE;
 
 -- Prints the final status o the doors.
 SET I = 1;
 WHILE (I <= SIZE) DO
  SET STATUS = (CASE WHEN (DOORS[I] = TRUE) THEN 'OPEN' ELSE 'CLOSED' END);
  CALL DBMS_OUTPUT.PUT_LINE('Door ' || I || ' is '|| STATUS);
  SET I = I + 1;
 END WHILE;
END @
 