Comma quibbling is a task originally set by Eric Lippert in his blog.



Task

Write a function to generate a string output which is the concatenation of input words from a list/sequence where:

 An input of no words produces the output string of just the two brace characters "{}".
 An input of just one word, e.g. ["ABC"], produces the output string of the word inside the two braces, e.g. "{ABC}".
 An input of two words, e.g. ["ABC", "DEF"], produces the output string of the two words inside the two braces with the words separated by the string " and ", e.g. "{ABC and DEF}".
 An input of three or more words, e.g. ["ABC", "DEF", "G", "H"], produces the output string of all but the last word separated by ", " with the last word separated by " and " and all within braces; e.g. "{ABC, DEF, G and H}".


Test your function with the following series of inputs showing your output here on this page:

 [] # (No input words).
 ["ABC"]
 ["ABC", "DEF"]
 ["ABC", "DEF", "G", "H"]


Note: Assume words are non-empty strings of uppercase characters for this task.




let inputs = [[], ["ABC"], ["ABC", "DEF"], ["ABC", "DEF", "G", "H"]]
 
func quibbling(var words:[String]) {
    if words.count == 0 {
        println("{}")
    } else if words.count == 1 {
        println("{\(words[0])}")
    } else if words.count == 2 {
        println("{\(words[0]) and \(words[1])}")
    } else {
        var output = "{"
        while words.count != 2 {
            output += words.removeAtIndex(0) + ", "
        }
        output += "\(words.removeAtIndex(0)) and \(words.removeAtIndex(0))}"
 
        println(output)
    }
}
 
for word in inputs {
    quibbling(word)
}