Given a positive integer, count the number of its positive divisors.



Task
Show the result for the first   100   positive integers.



Related task
  Tau number


int N, D, C;
[Format(3, 0);
for N:= 1 to 100 do
    [C:= 0;
    for D:= 1 to N do
        if rem(N/D) = 0 then C:= C+1;
    RlOut(0, float(C));
    if rem(N/20) = 0 then CrLf(0);
    ];
]