This programming task, is to calculate ANY binomial coefficient.

However, it has to be able to output   






(


5
3


)





{\displaystyle {\binom {5}{3}}}

,   which is   10.

This formula is recommended:


 






(


n
k


)



=



n
!


(
n
−
k
)
!
k
!



=



n
(
n
−
1
)
(
n
−
2
)
…
(
n
−
k
+
1
)


k
(
k
−
1
)
(
k
−
2
)
…
1





{\displaystyle {\binom {n}{k}}={\frac {n!}{(n-k)!k!}}={\frac {n(n-1)(n-2)\ldots (n-k+1)}{k(k-1)(k-2)\ldots 1}}}





See Also:

 Combinations and permutations
 Pascal's triangle

 The number of samples of size k from n objects.


With   combinations and permutations   generation tasks. 






 Order Unimportant

 Order Important


 Without replacement








(


n
k


)




=

n



C

k


=



n
(
n
−
1
)
…
(
n
−
k
+
1
)


k
(
k
−
1
)
…
1





{\displaystyle {\binom {n}{k}}=^{n}\operatorname {C} _{k}={\frac {n(n-1)\ldots (n-k+1)}{k(k-1)\dots 1}}}










n



P

k


=
n
⋅
(
n
−
1
)
⋅
(
n
−
2
)
⋯
(
n
−
k
+
1
)


{\displaystyle ^{n}\operatorname {P} _{k}=n\cdot (n-1)\cdot (n-2)\cdots (n-k+1)}




Task: Combinations

Task: Permutations


 With replacement








(



n
+
k
−
1

k


)




=

n
+
k
−
1



C

k


=



(
n
+
k
−
1
)
!


(
n
−
1
)
!
k
!





{\displaystyle {\binom {n+k-1}{k}}=^{n+k-1}\operatorname {C} _{k}={(n+k-1)! \over (n-1)!k!}}








n

k




{\displaystyle n^{k}}




Task: Combinations with repetitions

Task: Permutations with repetitions



sub binomial {
    use bigint;
    my ($r, $n, $k) = (1, @_);
    for (1 .. $k) { $r *= $n--; $r /= $_ }
    $r;
}
 
print binomial(5, 3);