Task

Write a program that solves the odd word problem with the restrictions given below.



Description

You are promised an input stream consisting of English letters and punctuations.

It is guaranteed that:

 the words (sequence of consecutive letters) are delimited by one and only one punctuation,
 the stream will begin with a word,
 the words will be at least one letter long,   and 
 a full stop (a period, [.]) appears after, and only after, the last word.


Example

A stream with six words:

 what,is,the;meaning,of:life. 


The task is to reverse the letters in every other word while leaving punctuations intact, producing:

 what,si,the;gninaem,of:efil. 
while observing the following restrictions:

 Only I/O allowed is reading or writing one character at a time, which means: no reading in a string, no peeking ahead, no pushing characters back into the stream, and no storing characters in a global variable for later use;
 You are not to explicitly save characters in a collection data structure, such as arrays, strings, hash tables, etc, for later reversal;
 You are allowed to use recursions, closures, continuations, threads, co-routines, etc., even if their use implies the storage of multiple characters.


Test cases

Work on both the   "life"   example given above, and also the text:

 we,are;not,in,kansas;any,more.


package main
 
import (
    "bytes"
    "fmt"
    "io"
    "os"
    "unicode"
)
 
func main() {
    owp(os.Stdout, bytes.NewBufferString("what,is,the;meaning,of:life."))
    fmt.Println()
    owp(os.Stdout, bytes.NewBufferString("we,are;not,in,kansas;any,more."))
    fmt.Println()
}
 
func owp(dst io.Writer, src io.Reader) {
    byte_in := func () byte {
        bs := make([]byte, 1)
        src.Read(bs)
        return bs[0]
    }
    byte_out := func (b byte) { dst.Write([]byte{b}) }    
    var odd func() byte
    odd = func() byte {
        s := byte_in()
        if unicode.IsPunct(rune(s)) {
            return s
        }
        b := odd()
        byte_out(s)
        return b
    }
    for {
        for {
            b := byte_in()
            byte_out(b)
            if b == '.' {
                return
            }
            if unicode.IsPunct(rune(b)) {
                break
            }
        }
        b := odd()
        byte_out(b)
        if b == '.' {
            return
        }
    }
}