A friend of mine runs a pharmacy.   He has a specialized function in his Dispensary application which receives a decimal value of currency and replaces it to a standard value.   This value is regulated by a government department.



Task

Given a floating point value between   0.00   and   1.00,   rescale according to the following table:

>=  0.00  <  0.06  :=  0.10
>=  0.06  <  0.11  :=  0.18
>=  0.11  <  0.16  :=  0.26
>=  0.16  <  0.21  :=  0.32
>=  0.21  <  0.26  :=  0.38
>=  0.26  <  0.31  :=  0.44
>=  0.31  <  0.36  :=  0.50
>=  0.36  <  0.41  :=  0.54
>=  0.41  <  0.46  :=  0.58
>=  0.46  <  0.51  :=  0.62
>=  0.51  <  0.56  :=  0.66
>=  0.56  <  0.61  :=  0.70
>=  0.61  <  0.66  :=  0.74
>=  0.66  <  0.71  :=  0.78
>=  0.71  <  0.76  :=  0.82
>=  0.76  <  0.81  :=  0.86
>=  0.81  <  0.86  :=  0.90
>=  0.86  <  0.91  :=  0.94
>=  0.91  <  0.96  :=  0.98
>=  0.96  <  1.01  :=  1.00



 
see pricefraction(0.5)
 
func pricefraction n
     if n < 0.06 return 0.10 ok
     if n < 0.11 return 0.18 ok
     if n < 0.16 return 0.26 ok
     if n < 0.21 return 0.32 ok
     if n < 0.26 return 0.38 ok
     if n < 0.31 return 0.44 ok
     if n < 0.36 return 0.50 ok
     if n < 0.41 return 0.54 ok
     if n < 0.46 return 0.58 ok
     if n < 0.51 return 0.62 ok
     if n < 0.56 return 0.66 ok
     if n < 0.61 return 0.70 ok
     if n < 0.66 return 0.74 ok
     if n < 0.71 return 0.78 ok
     if n < 0.76 return 0.82 ok
     if n < 0.81 return 0.86 ok
     if n < 0.86 return 0.90 ok
     if n < 0.91 return 0.94 ok 
     if n < 0.96 return 0.98 ok
     return 1
 
 