A friend of mine runs a pharmacy.   He has a specialized function in his Dispensary application which receives a decimal value of currency and replaces it to a standard value.   This value is regulated by a government department.



Task

Given a floating point value between   0.00   and   1.00,   rescale according to the following table:

>=  0.00  <  0.06  :=  0.10
>=  0.06  <  0.11  :=  0.18
>=  0.11  <  0.16  :=  0.26
>=  0.16  <  0.21  :=  0.32
>=  0.21  <  0.26  :=  0.38
>=  0.26  <  0.31  :=  0.44
>=  0.31  <  0.36  :=  0.50
>=  0.36  <  0.41  :=  0.54
>=  0.41  <  0.46  :=  0.58
>=  0.46  <  0.51  :=  0.62
>=  0.51  <  0.56  :=  0.66
>=  0.56  <  0.61  :=  0.70
>=  0.61  <  0.66  :=  0.74
>=  0.66  <  0.71  :=  0.78
>=  0.71  <  0.76  :=  0.82
>=  0.76  <  0.81  :=  0.86
>=  0.81  <  0.86  :=  0.90
>=  0.86  <  0.91  :=  0.94
>=  0.91  <  0.96  :=  0.98
>=  0.96  <  1.01  :=  1.00



For i = 0 To 100 Step 5
  Print Using "+?.##"; i, Using "+?.##"; FUNC(_Normalize (FUNC(_Classify (i))))
Next 
 
End
 
_Normalize                             ' normalize the price
  Param (1)                            ' class
  Local (4)                            ' accumulator, increment, switch and iterator
 
  b@ = 0 : c@ = 10 : d@ = 2            ' setup accumulator, increment and switch
 
  For e@ = 0 to a@                     ' from zero to class
    If And(e@ + 1, d@) Then d@ = And(d@ + d@, 15) : c@ = c@ - 2
    b@ = b@ + c@                       ' switch increment if needed
  Next                                 ' accumulate price
Return (Min(b@, 100))                  ' clip top of price in accumulator
                                       ' calculate class
_Classify Param (1) : Return ((a@ - (a@>0)) / 5)