Loops/Wrong ranges

You are encouraged to solve this task according to the task description, using any language you may know.
Some languages have syntax or function(s) to generate a range of numeric values from a start value, a stop value, and an increment.

The purpose of this task is to select the range syntax/function that would generate at least two increasing numbers when given a stop value more than the start value and a positive increment of less than half the difference.   You are then to use that same syntax/function but with different parameters; and show, here, what would happen.

Use these values if possible:



start 
stop 
increment 
Comment


 -2
2
1
Normal


 -2
2
0
Zero increment


 -2
2
-1
Increments away from stop value


 -2
2
10
First increment is beyond stop value


2
-2
1
Start more than stop: positive increment


2
2
1
Start equal stop: positive increment


2
2
-1
Start equal stop: negative increment


2
2
0
Start equal stop: zero increment


0
0
0
Start equal stop equal zero: zero increment

Related tasks

   Loop over multiple arrays simultaneously
   Loops/Break
   Loops/Continue
   Loops/Do-while
   Loops/Downward for
   Loops/For
   Loops/For with a specified step
   Loops/Foreach
   Loops/Increment loop index within loop body
   Loops/Infinite
   Loops/N plus one half
   Loops/Nested
   Loops/While
   Loops/with multiple ranges
   Loops/Wrong ranges


struct Seq {
    start int
    stop int
    incr int
    comment          string
}
 
const examples = [
    Seq{-2, 2, 1, "Normal"},
    Seq{-2, 2, 0, "Zero increment"},
    Seq{-2, 2, -1, "Increments away from stop value"},
    Seq{-2, 2, 10, "First increment is beyond stop value"},
    Seq{2, -2, 1, "Start more than stop: positive increment"},
    Seq{2, 2, 1, "Start equal stop: positive increment"},
    Seq{2, 2, -1, "Start equal stop: negative increment"},
    Seq{2, 2, 0, "Start equal stop: zero increment"},
    Seq{0, 0, 0, "Start equal stop equal zero: zero increment"},
]
 
fn sequence(s Seq, limit int) []int {
    mut seq := []int{}
    for i, c := s.start, 0; i <= s.stop && c < limit; i, c = i+s.incr, c+1 {
        seq << i
    }
    return seq
}
 
fn main() {
    limit := 10
    for ex in examples {
        println(ex.comment)
        print("Range($ex.start, $ex.stop, $ex.incr) -> ")
        println(sequence(ex, limit))
        println('')
    }
}