A friend of mine runs a pharmacy.   He has a specialized function in his Dispensary application which receives a decimal value of currency and replaces it to a standard value.   This value is regulated by a government department.



Task

Given a floating point value between   0.00   and   1.00,   rescale according to the following table:

>=  0.00  <  0.06  :=  0.10
>=  0.06  <  0.11  :=  0.18
>=  0.11  <  0.16  :=  0.26
>=  0.16  <  0.21  :=  0.32
>=  0.21  <  0.26  :=  0.38
>=  0.26  <  0.31  :=  0.44
>=  0.31  <  0.36  :=  0.50
>=  0.36  <  0.41  :=  0.54
>=  0.41  <  0.46  :=  0.58
>=  0.46  <  0.51  :=  0.62
>=  0.51  <  0.56  :=  0.66
>=  0.56  <  0.61  :=  0.70
>=  0.61  <  0.66  :=  0.74
>=  0.66  <  0.71  :=  0.78
>=  0.71  <  0.76  :=  0.82
>=  0.76  <  0.81  :=  0.86
>=  0.81  <  0.86  :=  0.90
>=  0.86  <  0.91  :=  0.94
>=  0.91  <  0.96  :=  0.98
>=  0.96  <  1.01  :=  1.00



def rescale_price_fraction(value)
  raise ArgumentError, "value=#{value}, must have: 0 <= value < 1.01" if value < 0 || value >= 1.01
  if     value < 0.06  then  0.10
  elsif  value < 0.11  then  0.18
  elsif  value < 0.16  then  0.26
  elsif  value < 0.21  then  0.32
  elsif  value < 0.26  then  0.38
  elsif  value < 0.31  then  0.44
  elsif  value < 0.36  then  0.50
  elsif  value < 0.41  then  0.54
  elsif  value < 0.46  then  0.58
  elsif  value < 0.51  then  0.62
  elsif  value < 0.56  then  0.66
  elsif  value < 0.61  then  0.70
  elsif  value < 0.66  then  0.74
  elsif  value < 0.71  then  0.78
  elsif  value < 0.76  then  0.82
  elsif  value < 0.81  then  0.86
  elsif  value < 0.86  then  0.90
  elsif  value < 0.91  then  0.94
  elsif  value < 0.96  then  0.98
  elsif  value < 1.01  then  1.00
  end
end