4-rings or 4-squares puzzle

You are encouraged to solve this task according to the task description, using any language you may know.
Task

Replace       a, b, c, d, e, f,   and
  g        with the decimal
digits   LOW   ───►   HIGH

such that the sum of the letters inside of each of the four large squares add up to
the same sum.

            ╔══════════════╗      ╔══════════════╗
            ║              ║      ║              ║
            ║      a       ║      ║      e       ║
            ║              ║      ║              ║
            ║          ┌───╫──────╫───┐      ┌───╫─────────┐
            ║          │   ║      ║   │      │   ║         │
            ║          │ b ║      ║ d │      │ f ║         │
            ║          │   ║      ║   │      │   ║         │
            ║          │   ║      ║   │      │   ║         │
            ╚══════════╪═══╝      ╚═══╪══════╪═══╝         │
                       │       c      │      │      g      │
                       │              │      │             │
                       │              │      │             │
                       └──────────────┘      └─────────────┘

Show all output here.



   Show all solutions for each letter being unique with
        LOW=1     HIGH=7

   Show all solutions for each letter being unique with
        LOW=3     HIGH=9

   Show only the   number   of solutions when each letter can be non-unique
        LOW=0     HIGH=9



Related task

 Solve the no connection puzzle


 
#include <stdio.h>
 
#define TRUE 1
#define FALSE 0
 
int a,b,c,d,e,f,g;
int lo,hi,unique,show;
int solutions;
 
void
bf()
{
    for (f = lo;f <= hi; f++)
        if ((!unique) ||
           ((f != a) && (f != c) && (f != d) && (f != g) && (f != e)))
            {
            b = e + f - c;
            if ((b >= lo) && (b <= hi) &&
                   ((!unique) || ((b != a) && (b != c) &&
                   (b != d) && (b != g) && (b != e) && (b != f))))
                {
                solutions++;
                if (show)
                    printf("%d %d %d %d %d %d %d\n",a,b,c,d,e,f,g);
                }
            }
}
 
 
void
ge()
{
    for (e = lo;e <= hi; e++)
        if ((!unique) || ((e != a) && (e != c) && (e != d)))
            {
            g = d + e;
            if ((g >= lo) && (g <= hi) &&
                   ((!unique) || ((g != a) && (g != c) &&
                   (g != d) && (g != e))))
                bf();
            }
}
 
void
acd()
{
    for (c = lo;c <= hi; c++)
        for (d = lo;d <= hi; d++)
            if ((!unique) || (c != d))
                {
                a = c + d;
                if ((a >= lo) && (a <= hi) &&
                   ((!unique) || ((c != 0) && (d != 0))))
                    ge();
                }
}
 
 
void
foursquares(int plo,int phi, int punique,int pshow)
{
    lo = plo;
    hi = phi;
    unique = punique;
    show = pshow;
    solutions = 0;
 
    printf("\n");
 
    acd();
 
    if (unique)
        printf("\n%d unique solutions in %d to %d\n",solutions,lo,hi);
    else
        printf("\n%d non-unique solutions in %d to %d\n",solutions,lo,hi);
}
 
main()
{
    foursquares(1,7,TRUE,TRUE);
    foursquares(3,9,TRUE,TRUE);
    foursquares(0,9,FALSE,FALSE);
}
 