
Sorting Algorithm

This is a sorting algorithm.   It may be applied to a set of data in order to sort it.    
For comparing various sorts, see compare sorts.  
For other sorting algorithms,   see sorting algorithms,   or:

O(n logn) sorts
Heap sort |
Merge sort |
Patience sort |
Quick sort
O(n log2n) sorts
Shell Sort
O(n2) sorts
Bubble sort |
Cocktail sort |
Cocktail sort with shifting bounds |
Comb sort |
Cycle sort |
Gnome sort |
Insertion sort |
Selection sort |
Strand sort
other sorts
Bead sort |
Bogo sort |
Common sorted list |
Composite structures sort |
Custom comparator sort |
Counting sort |
Disjoint sublist sort |
External sort |
Jort sort |
Lexicographical sort |
Natural sorting |
Order by pair comparisons |
Order disjoint list items |
Order two numerical lists |
Object identifier (OID) sort |
Pancake sort |
Quickselect |
Permutation sort |
Radix sort |
Ranking methods |
Remove duplicate elements |
Sleep sort |
Stooge sort |
[Sort letters of a string] |
Three variable sort |
Topological sort |
Tree sort


Given   M   as a list of items and another list   N   of items chosen from   M,   create   M'   as a list with the first occurrences of items from   N   sorted to be in one of the set of indices of their original occurrence in   M   but in the order given by their order in   N.

That is, items in   N   are taken from   M   without replacement, then the corresponding positions in   M'   are filled by successive items from   N.



For example

if   M   is   'the cat sat on the mat'
And   N   is   'mat cat' 
Then the result   M'   is   'the mat sat on the cat'. 
The words not in   N   are left in their original positions.



If there are duplications then only the first instances in   M   up to as many as are mentioned in   N   are potentially re-ordered.



For example

  M = 'A B C A B C A B C' 
  N = 'C A C A' 
Is ordered as:

 M' = 'C B A C B A A B C' 


Show the output, here, for at least the following inputs:

Data M: 'the cat sat on the mat' Order N: 'mat cat'
Data M: 'the cat sat on the mat' Order N: 'cat mat'
Data M: 'A B C A B C A B C'      Order N: 'C A C A'
Data M: 'A B C A B D A B E'      Order N: 'E A D A'
Data M: 'A B'                    Order N: 'B'      
Data M: 'A B'                    Order N: 'B A'    
Data M: 'A B B A'                Order N: 'B A'



Cf

 Sort disjoint sublist


import java.util.Arrays;
import java.util.BitSet;
import org.apache.commons.lang3.ArrayUtils;
 
public class OrderDisjointItems {
 
    public static void main(String[] args) {
        final String[][] MNs = {{"the cat sat on the mat", "mat cat"},
        {"the cat sat on the mat", "cat mat"},
        {"A B C A B C A B C", "C A C A"}, {"A B C A B D A B E", "E A D A"},
        {"A B", "B"}, {"A B", "B A"}, {"A B B A", "B A"}, {"X X Y", "X"}};
 
        for (String[] a : MNs) {
            String[] r = orderDisjointItems(a[0].split(" "), a[1].split(" "));
            System.out.printf("%s | %s -> %s%n", a[0], a[1], Arrays.toString(r));
        }
    }
 
    // if input items cannot be null
    static String[] orderDisjointItems(String[] m, String[] n) {
        for (String e : n) {
            int idx = ArrayUtils.indexOf(m, e);
            if (idx != -1)
                m[idx] = null;
        }
        for (int i = 0, j = 0; i < m.length; i++) {
            if (m[i] == null)
                m[i] = n[j++];
        }
        return m;
    }
 
    // otherwise
    static String[] orderDisjointItems2(String[] m, String[] n) {
        BitSet bitSet = new BitSet(m.length);
        for (String e : n) {
            int idx = -1;
            do {
                idx = ArrayUtils.indexOf(m, e, idx + 1);
            } while (idx != -1 && bitSet.get(idx));
            if (idx != -1)
                bitSet.set(idx);
        }
        for (int i = 0, j = 0; i < m.length; i++) {
            if (bitSet.get(i))
                m[i] = n[j++];
        }
        return m;
    }
}