Task

Display the row and column in the periodic table of the given atomic number.

The periodic table

Let us consider the following periodic table representation.

     __________________________________________________________________________ 
    |   1   2   3   4   5   6   7   8   9   10  11  12  13  14  15  16  17  18 |
    |                                                                          |
    |1  H                                                                   He |
    |                                                                          |
    |2  Li  Be                                          B   C   N   O   F   Ne |
    |                                                                          |
    |3  Na  Mg                                          Al  Si  P   S   Cl  Ar |
    |                                                                          |
    |4  K   Ca  Sc  Ti  V   Cr  Mn  Fe  Co  Ni  Cu  Zn  Ga  Ge  As  Se  Br  Kr |
    |                                                                          |
    |5  Rb  Sr  Y   Zr  Nb  Mo  Tc  Ru  Rh  Pd  Ag  Cd  In  Sn  Sb  Te  I   Xe |
    |                                                                          |
    |6  Cs  Ba  *   Hf  Ta  W   Re  Os  Ir  Pt  Au  Hg  Tl  Pb  Bi  Po  At  Rn |
    |                                                                          |
    |7  Fr  Ra  °   Rf  Db  Sg  Bh  Hs  Mt  Ds  Rg  Cn  Nh  Fl  Mc  Lv  Ts  Og |
    |__________________________________________________________________________|
    |                                                                          |
    |                                                                          |
    |8  Lantanoidi* La  Ce  Pr  Nd  Pm  Sm  Eu  Gd  Tb  Dy  Ho  Er  Tm  Yb  Lu |
    |                                                                          |
    |9   Aktinoidi° Ak  Th  Pa  U   Np  Pu  Am  Cm  Bk  Cf  Es  Fm  Md  No  Lr |
    |__________________________________________________________________________|

Example test cases;
   1 -> 1 1
   2 -> 1 18
   29 -> 4 11
   42 -> 5 6
   57 -> 8 4
   58 -> 8 5
   72 -> 6 4
   89 -> 9 4
Details;
The representation of the periodic table may be represented in various way. The one presented in this challenge does have the following property : Lantanides and Aktinoides are all in a dedicated row, hence there is no element that is placed at 6, 3 nor 7, 3.

You may take a look at the atomic number repartitions here.

The atomic number is at least 1, at most 118.



See also
 
   the periodic table
   This task was an idea from CompSciFact
   The periodic table in ascii that was used as template


 
def perta(atomic) -> (int, int):
 
    NOBLES = 2, 10, 18, 36, 54, 86, 118
    INTERTWINED = 0, 0, 0, 0, 0, 57, 89
    INTERTWINING_SIZE = 14
    LINE_WIDTH = 18
 
    prev_noble = 0
    for row, noble in enumerate(NOBLES):
        if atomic <= noble:  # we are at the good row. We now need to determine the column
            nb_elem = noble - prev_noble  # number of elements on that row
            rank =  atomic - prev_noble  # rank of the input element among elements
            if INTERTWINED[row] and INTERTWINED[row] <= atomic <= INTERTWINED[row] + INTERTWINING_SIZE:  # lantanides or actinides
                row += 2
                col = rank + 1
            else:  # not a lantanide nor actinide
                # handle empty spaces between 1-2, 4-5 and 12-13.
                nb_empty = LINE_WIDTH - nb_elem  # spaces count as columns
                inside_left_element_rank = 2 if noble > 2 else 1
                col = rank + (nb_empty if rank > inside_left_element_rank else 0)
            break
        prev_noble = noble
    return row+1, col
 
 
 
# small test suite
 
TESTS = {
    1: (1, 1),
    2: (1, 18),
    29: (4,11),
    42: (5, 6),
    58: (8, 5),
    59: (8, 6),
    57: (8, 4),
    71: (8, 18),
    72: (6, 4),
    89: (9, 4),
    90: (9, 5),
    103: (9, 18),
}
 
for input, out in TESTS.items():
    found = perta(input)
    print('TEST:{:3d} -> '.format(input) + str(found) + (f' ; ERROR: expected {out}' if found != out else ''))
 
 