continued fraction
Mathworld





a

0


+









b

1












a

1


+









b

2












a

2


+









b

3












a

3


+
⋱

















{\displaystyle a_{0}+{\cfrac {b_{1}}{a_{1}+{\cfrac {b_{2}}{a_{2}+{\cfrac {b_{3}}{a_{3}+\ddots }}}}}}}


The task is to write a program which generates such a number and prints a real representation of it. The code should be tested by calculating and printing the square root of 2, Napier's Constant, and Pi, using the following coefficients:

For the square root of 2, use 




a

0


=
1


{\displaystyle a_{0}=1}

 then 




a

N


=
2


{\displaystyle a_{N}=2}

. 




b

N




{\displaystyle b_{N}}

 is always 



1


{\displaystyle 1}

.







2


=
1
+








1









2
+








1









2
+








1









2
+
⋱

















{\displaystyle {\sqrt {2}}=1+{\cfrac {1}{2+{\cfrac {1}{2+{\cfrac {1}{2+\ddots }}}}}}}


For Napier's Constant, use 




a

0


=
2


{\displaystyle a_{0}=2}

, then 




a

N


=
N


{\displaystyle a_{N}=N}

. 




b

1


=
1


{\displaystyle b_{1}=1}

 then 




b

N


=
N
−
1


{\displaystyle b_{N}=N-1}

.





e
=
2
+








1









1
+








1









2
+








2









3
+








3









4
+
⋱






















{\displaystyle e=2+{\cfrac {1}{1+{\cfrac {1}{2+{\cfrac {2}{3+{\cfrac {3}{4+\ddots }}}}}}}}}


For Pi, use 




a

0


=
3


{\displaystyle a_{0}=3}

 then 




a

N


=
6


{\displaystyle a_{N}=6}

. 




b

N


=
(
2
N
−
1

)

2




{\displaystyle b_{N}=(2N-1)^{2}}

.





π
=
3
+








1









6
+








9









6
+








25









6
+
⋱

















{\displaystyle \pi =3+{\cfrac {1}{6+{\cfrac {9}{6+{\cfrac {25}{6+\ddots }}}}}}}




See also

   Continued fraction/Arithmetic for tasks that do arithmetic over continued fractions.


#include <iomanip>
#include <iostream>
#include <tuple>
 
typedef std::tuple<double,double> coeff_t; // coefficients type
typedef coeff_t (*func_t)(int); // callback function type
 
double calc(func_t func, int n)
{
    double a, b, temp = 0;
    for (; n > 0; --n) {
        std::tie(a, b) = func(n);
        temp = b / (a + temp);
    }
    std::tie(a, b) = func(0);
    return a + temp;
}
 
coeff_t sqrt2(int n)
{
    return coeff_t(n > 0 ? 2 : 1, 1);
}
 
coeff_t napier(int n)
{
    return coeff_t(n > 0 ? n : 2, n > 1 ? n - 1 : 1);
}
 
coeff_t pi(int n)
{
    return coeff_t(n > 0 ? 6 : 3, (2 * n - 1) * (2 * n - 1));
}
 
int main()
{
    std::streamsize old_prec = std::cout.precision(15); // set output digits
    std::cout 
        << calc(sqrt2, 20) << '\n'
        << calc(napier, 15) << '\n'
        << calc(pi, 10000) << '\n'
        << std::setprecision(old_prec); // reset precision
}