A friend of mine runs a pharmacy.   He has a specialized function in his Dispensary application which receives a decimal value of currency and replaces it to a standard value.   This value is regulated by a government department.



Task

Given a floating point value between   0.00   and   1.00,   rescale according to the following table:

>=  0.00  <  0.06  :=  0.10
>=  0.06  <  0.11  :=  0.18
>=  0.11  <  0.16  :=  0.26
>=  0.16  <  0.21  :=  0.32
>=  0.21  <  0.26  :=  0.38
>=  0.26  <  0.31  :=  0.44
>=  0.31  <  0.36  :=  0.50
>=  0.36  <  0.41  :=  0.54
>=  0.41  <  0.46  :=  0.58
>=  0.46  <  0.51  :=  0.62
>=  0.51  <  0.56  :=  0.66
>=  0.56  <  0.61  :=  0.70
>=  0.61  <  0.66  :=  0.74
>=  0.66  <  0.71  :=  0.78
>=  0.71  <  0.76  :=  0.82
>=  0.76  <  0.81  :=  0.86
>=  0.81  <  0.86  :=  0.90
>=  0.86  <  0.91  :=  0.94
>=  0.91  <  0.96  :=  0.98
>=  0.96  <  1.01  :=  1.00



$ include "seed7_05.s7i";
  include "float.s7i";
 
const func float: computePrice (in float: x) is func
  result
    var float: price is 0.0;
  begin
    if x >= 0.0 and x < 0.06 then
      price := 0.10;
    elsif x < 0.11 then
      price := 0.18;
    elsif x < 0.36 then
      price := flt(((trunc(x * 100.0) - 11) div 5) * 6 + 26) / 100.0;
    elsif x < 0.96 then
      price := flt(((trunc(x * 100.0) - 31) div 5) * 4 + 50) / 100.0;
    else
      price := 1.0;
    end if;
  end func;
 
const proc: main is func
  local
    var integer: i is 0;
  begin
    for i range 0 to 100 do
      writeln(flt(i) / 100.0 digits 2 <& " " <& computePrice(flt(i) / 100.0) digits 2);
    end for;
  end func;