A friend of mine runs a pharmacy.   He has a specialized function in his Dispensary application which receives a decimal value of currency and replaces it to a standard value.   This value is regulated by a government department.



Task

Given a floating point value between   0.00   and   1.00,   rescale according to the following table:

>=  0.00  <  0.06  :=  0.10
>=  0.06  <  0.11  :=  0.18
>=  0.11  <  0.16  :=  0.26
>=  0.16  <  0.21  :=  0.32
>=  0.21  <  0.26  :=  0.38
>=  0.26  <  0.31  :=  0.44
>=  0.31  <  0.36  :=  0.50
>=  0.36  <  0.41  :=  0.54
>=  0.41  <  0.46  :=  0.58
>=  0.46  <  0.51  :=  0.62
>=  0.51  <  0.56  :=  0.66
>=  0.56  <  0.61  :=  0.70
>=  0.61  <  0.66  :=  0.74
>=  0.66  <  0.71  :=  0.78
>=  0.71  <  0.76  :=  0.82
>=  0.76  <  0.81  :=  0.86
>=  0.81  <  0.86  :=  0.90
>=  0.86  <  0.91  :=  0.94
>=  0.91  <  0.96  :=  0.98
>=  0.96  <  1.01  :=  1.00



data .06, .1,.11,.18,.16,.26,.21,.32,.26,.38,.31,.44,.36,.50,.41,.54,.46,.58,.51,.62
data .56,.66,.61,.70,.66,.74,.71,.78,.76,.82,.81,.86,.86,.90,.91,.94,.96,.98 
 
dim od(100)
dim nd(100)
for i = 1 to 19
read oldDec
read newDec
j = j + 1
for j = j to oldDec * 100
   nd(j) = newDec
next j
next i
 
[loop]
input "Gimme a number";numb
decm  = val(using("##",(numb mod 1) * 100))
print numb;" -->";nd(decm)
 
goto [loop]