linear algebra
Cramer's rule
system of linear equations


Given


 




{





a

1


x
+

b

1


y
+

c

1


z


=



d

1









a

2


x
+

b

2


y
+

c

2


z


=



d

2









a

3


x
+

b

3


y
+

c

3


z


=



d

3












{\displaystyle \left\{{\begin{matrix}a_{1}x+b_{1}y+c_{1}z&={\color {red}d_{1}}\\a_{2}x+b_{2}y+c_{2}z&={\color {red}d_{2}}\\a_{3}x+b_{3}y+c_{3}z&={\color {red}d_{3}}\end{matrix}}\right.}




which in matrix format is



 





[




a

1





b

1





c

1







a

2





b

2





c

2







a

3





b

3





c

3





]




[



x




y




z



]


=


[






d

1











d

2











d

3







]


.


{\displaystyle {\begin{bmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{bmatrix}}{\begin{bmatrix}x\\y\\z\end{bmatrix}}={\begin{bmatrix}{\color {red}d_{1}}\\{\color {red}d_{2}}\\{\color {red}d_{3}}\end{bmatrix}}.}




Then the values of 



x
,
y


{\displaystyle x,y}

 and 



z


{\displaystyle z}

 can be found as follows:







x
=



|






d

1







b

1





c

1









d

2







b

2





c

2









d

3







b

3





c

3





|


|




a

1





b

1





c

1







a

2





b

2





c

2







a

3





b

3





c

3





|



,

y
=



|




a

1







d

1







c

1







a

2







d

2







c

2







a

3







d

3







c

3





|


|




a

1





b

1





c

1







a

2





b

2





c

2







a

3





b

3





c

3





|



,

 and 

z
=



|




a

1





b

1







d

1









a

2





b

2







d

2









a

3





b

3







d

3







|


|




a

1





b

1





c

1







a

2





b

2





c

2







a

3





b

3





c

3





|



.


{\displaystyle x={\frac {\begin{vmatrix}{\color {red}d_{1}}&b_{1}&c_{1}\\{\color {red}d_{2}}&b_{2}&c_{2}\\{\color {red}d_{3}}&b_{3}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},\quad y={\frac {\begin{vmatrix}a_{1}&{\color {red}d_{1}}&c_{1}\\a_{2}&{\color {red}d_{2}}&c_{2}\\a_{3}&{\color {red}d_{3}}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},{\text{ and }}z={\frac {\begin{vmatrix}a_{1}&b_{1}&{\color {red}d_{1}}\\a_{2}&b_{2}&{\color {red}d_{2}}\\a_{3}&b_{3}&{\color {red}d_{3}}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}}.}






Task
Given the following system of equations:









{



2
w
−
x
+
5
y
+
z
=
−
3




3
w
+
2
x
+
2
y
−
6
z
=
−
32




w
+
3
x
+
3
y
−
z
=
−
47




5
w
−
2
x
−
3
y
+
3
z
=
49








{\displaystyle {\begin{cases}2w-x+5y+z=-3\\3w+2x+2y-6z=-32\\w+3x+3y-z=-47\\5w-2x-3y+3z=49\\\end{cases}}}




solve for 



w


{\displaystyle w}

, 



x


{\displaystyle x}

, 



y


{\displaystyle y}

 and 



z


{\displaystyle z}

, using Cramer's rule.




using System;
using System.Collections.Generic;
using static System.Linq.Enumerable;
 
public static class CramersRule
{
    public static void Main() {
        var equations = new [] {
            new [] { 2, -1,  5,  1,  -3 },
            new [] { 3,  2,  2, -6, -32 },
            new [] { 1,  3,  3, -1, -47 },
            new [] { 5, -2, -3,  3,  49 }
        };
        var solution = SolveCramer(equations);
        Console.WriteLine(solution.DelimitWith(", "));
    }
 
    public static int[] SolveCramer(int[][] equations) {
        int size = equations.Length;
        if (equations.Any(eq => eq.Length != size + 1)) throw new ArgumentException($"Each equation must have {size+1} terms.");
        int[,] matrix = new int[size, size];
        int[] column = new int[size];
        for (int r = 0; r < size; r++) {
            column[r] = equations[r][size];
            for (int c = 0; c < size; c++) {
                matrix[r, c] = equations[r][c];
            }
        }
        return Solve(new SubMatrix(matrix, column));
    }
 
    private static int[] Solve(SubMatrix matrix) {
        int det = matrix.Det();
        if (det == 0) throw new ArgumentException("The determinant is zero.");
 
        int[] answer = new int[matrix.Size];
        for (int i = 0; i < matrix.Size; i++) {
            matrix.ColumnIndex = i;
            answer[i] = matrix.Det() / det;
        }
        return answer;
    }
 
    //Extension method from library.
    static string DelimitWith<T>(this IEnumerable<T> source, string separator = " ") =>
        string.Join(separator ?? " ", source ?? Empty<T>());
 
    private class SubMatrix
    {
        private int[,] source;
        private SubMatrix prev;
        private int[] replaceColumn;
 
        public SubMatrix(int[,] source, int[] replaceColumn) {
            this.source = source;
            this.replaceColumn = replaceColumn;
            this.prev = null;
            this.ColumnIndex = -1;
            Size = replaceColumn.Length;
        }
 
        private SubMatrix(SubMatrix prev, int deletedColumnIndex = -1) {
            this.source = null;
            this.prev = prev;
            this.ColumnIndex = deletedColumnIndex;
            Size = prev.Size - 1;
        }
 
        public int ColumnIndex { get; set; }
        public int Size { get; }
 
        public int this[int row, int column] {
            get {
                if (source != null) return column == ColumnIndex ? replaceColumn[row] : source[row, column];
                return prev[row + 1, column < ColumnIndex ? column : column + 1];
            }
        }
 
        public int Det() {
            if (Size == 1) return this[0, 0];
            if (Size == 2) return this[0, 0] * this[1, 1] - this[0, 1] * this[1, 0];
            SubMatrix m = new SubMatrix(this);
            int det = 0;
            int sign = 1;
            for (int c = 0; c < Size; c++) {
                m.ColumnIndex = c;
                int d = m.Det();
                det += this[0, c] * d * sign;
                sign = -sign;
            }
            return det;
        }
 
        public void Print() {
            for (int r = 0; r < Size; r++) {
                Console.WriteLine(Range(0, Size).Select(c => this[r, c]).DelimitWith(", "));
            }
            Console.WriteLine();
        }
    }
 
}