
Sorting Algorithm

This is a sorting algorithm.   It may be applied to a set of data in order to sort it.    
For comparing various sorts, see compare sorts.  
For other sorting algorithms,   see sorting algorithms,   or:

O(n logn) sorts
Heap sort |
Merge sort |
Patience sort |
Quick sort
O(n log2n) sorts
Shell Sort
O(n2) sorts
Bubble sort |
Cocktail sort |
Cocktail sort with shifting bounds |
Comb sort |
Cycle sort |
Gnome sort |
Insertion sort |
Selection sort |
Strand sort
other sorts
Bead sort |
Bogo sort |
Common sorted list |
Composite structures sort |
Custom comparator sort |
Counting sort |
Disjoint sublist sort |
External sort |
Jort sort |
Lexicographical sort |
Natural sorting |
Order by pair comparisons |
Order disjoint list items |
Order two numerical lists |
Object identifier (OID) sort |
Pancake sort |
Quickselect |
Permutation sort |
Radix sort |
Ranking methods |
Remove duplicate elements |
Sleep sort |
Stooge sort |
[Sort letters of a string] |
Three variable sort |
Topological sort |
Tree sort




 This page uses content from Wikipedia. The original article was at Cocktail sort. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)



The cocktail shaker sort is an improvement on the Bubble Sort.

The improvement is basically that values "bubble" both directions through the array, because on each iteration the cocktail shaker sort bubble sorts once forwards and once backwards. Pseudocode for the algorithm (from wikipedia):

function cocktailSort( A : list of sortable items )
 do
   swapped := false
   for each i in 0 to length( A ) - 2 do
     if A[ i ] > A[ i+1 ] then // test whether the two 
                               // elements are in the wrong 
                               // order
       swap( A[ i ], A[ i+1 ] ) // let the two elements
                                // change places
       swapped := true;
   if swapped = false then
     // we can exit the outer loop here if no swaps occurred.
     break do-while loop;
   swapped := false
   for each i in length( A ) - 2 down to 0 do
     if A[ i ] > A[ i+1 ] then
       swap( A[ i ], A[ i+1 ] )
       swapped := true;
 while swapped; // if no elements have been swapped, 
                // then the list is sorted

Related task

   cocktail sort with shifting bounds


function CocktailSort ($a) {
    $l = $a.Length
	$m = 0
	if( $l -gt 1 )
	{
		$hasChanged = $true
		:outer while ($hasChanged) {
			$hasChanged = $false
			$l--
			for ($i = $m; $i -lt $l; $i++) {
				if ($a[$i] -gt $a[$i+1]) {
					$a[$i], $a[$i+1] = $a[$i+1], $a[$i]
					$hasChanged = $true
				}
			}
			if(-not $hasChanged) {
				break outer
			}
			$hasChanged = $false
			for ($i = $l; $i -gt $m; $i--) {
				if ($a[$i-1] -gt $a[$i]) {
					$a[$i-1], $a[$i] = $a[$i], $a[$i-1]
					$hasChanged = $true
				}
			}
			$m++
		}
	}
	$a
}
 
$l = 10; CocktailSort ( 1..$l | ForEach-Object { $Rand = New-Object Random }{ $Rand.Next( -( $l - 1 ), $l - 1 ) } )