Solve the Stable marriage problem using the Gale/Shapley algorithm.


Problem description

Given an equal number of men and women to be paired for marriage, each man ranks all the women in order of his preference and each woman ranks all the men in order of her preference.

A stable set of engagements for marriage is one where no man prefers a woman over the one he is engaged to, where that other woman also prefers that man over the one she is engaged to. I.e. with consulting marriages, there would be no reason for the engagements between the people to change.

Gale and Shapley proved that there is a stable set of engagements for any set of preferences and the first link above gives their algorithm for finding a set of stable engagements.


Task Specifics

Given ten males:

   abe, bob, col, dan, ed, fred, gav, hal, ian, jon

And ten females:

   abi, bea, cath, dee, eve, fay, gay, hope, ivy, jan

And a complete list of ranked preferences, where the most liked is to the left:

  abe: abi, eve, cath, ivy, jan, dee, fay, bea, hope, gay
  bob: cath, hope, abi, dee, eve, fay, bea, jan, ivy, gay
  col: hope, eve, abi, dee, bea, fay, ivy, gay, cath, jan
  dan: ivy, fay, dee, gay, hope, eve, jan, bea, cath, abi
   ed: jan, dee, bea, cath, fay, eve, abi, ivy, hope, gay
 fred: bea, abi, dee, gay, eve, ivy, cath, jan, hope, fay
  gav: gay, eve, ivy, bea, cath, abi, dee, hope, jan, fay
  hal: abi, eve, hope, fay, ivy, cath, jan, bea, gay, dee
  ian: hope, cath, dee, gay, bea, abi, fay, ivy, jan, eve
  jon: abi, fay, jan, gay, eve, bea, dee, cath, ivy, hope
   
  abi: bob, fred, jon, gav, ian, abe, dan, ed, col, hal
  bea: bob, abe, col, fred, gav, dan, ian, ed, jon, hal
 cath: fred, bob, ed, gav, hal, col, ian, abe, dan, jon
  dee: fred, jon, col, abe, ian, hal, gav, dan, bob, ed
  eve: jon, hal, fred, dan, abe, gav, col, ed, ian, bob
  fay: bob, abe, ed, ian, jon, dan, fred, gav, col, hal
  gay: jon, gav, hal, fred, bob, abe, col, ed, dan, ian
 hope: gav, jon, bob, abe, ian, dan, hal, ed, col, fred
  ivy: ian, col, hal, gav, fred, bob, abe, ed, jon, dan
  jan: ed, hal, gav, abe, bob, jon, col, ian, fred, dan

 Use the Gale Shapley algorithm to find a stable set of engagements
 Perturb this set of engagements to form an unstable set of engagements then check this new set for stability.

References

 The Stable Marriage Problem. (Eloquent description and background information).
 Gale-Shapley Algorithm Demonstration.
 Another Gale-Shapley Algorithm Demonstration.
 Stable Marriage Problem - Numberphile (Video).
 Stable Marriage Problem (the math bit) (Video).
 The Stable Marriage Problem and School Choice. (Excellent exposition)


{-# LANGUAGE TemplateHaskell #-}
import Lens.Micro
import Lens.Micro.TH
import Data.List (union, delete)
 
type Preferences a = (a, [a])
type Couple a = (a,a)
data State a = State { _freeGuys :: [a]
                     , _guys :: [Preferences a]
                     , _girls :: [Preferences a]}
 
makeLenses ''State