import lxml.html as lh
import urllib.request, urllib.error, urllib.parse
url = 'http://bit.ly/bf1T12'
doc = lh.parse(urllib.request.urlopen(url))
blurb = doc.xpath(
    '//td[child::*[text()="Additional  Info"]]/following-sibling::td/text()')
blurb = [text for text in blurb if text != '\xa0']
print('\n'.join(blurb))
Parsing HTML with Lxml