This is a real-world medical entrance exam question, please give the true answer based on the question and selection. Topic name: None, Subject name: Biochemistry
Oxidation of a fatty acid with an odd number of carbon atoms yields: 
Select and explain. 
A. Acetyl-CoA plus a molecule of Propionyl-CoA, B. Two molecules of Acetyl CoA, C. Two molecules of Propionyl CoA, D. Acetyl CoA only
A: Acetyl-CoA plus a molecule of Propionyl-CoA
Answer: A: Acetyl-CoA plus a molecule of Propionyl-CoA 
Explanation: Fatty acids with an odd number of carbon atoms are oxidized by  the  pathway  of  β xidation  described  above  producing acetyl  CoA  until  a  three-carbon  (propionyl-CoA)  residue remains. This compound is converted to succinyl-CoA, a constituent of the citric acid cycle. Hence, the propionyl residue from an odd-chain fatty acid is the only part of a fatty acid that is glucogenic.
HARPERS ILLUSTRATED BIOCHEMISTRY30th ed, Page No:225