This is a real-world medical entrance exam question, please give the true answer based on the question and selection. Topic name: None, Subject name: Unknown
The prevalence of Candida glabrata infection is found to be 80% in a population of 100. If the test is repeated for 95% confidence levels, then what will be the range of prevalence for the Candida glabrata infection? 
Select and explain. 
A. 70 to 90, B. 72 to 88, C. 65 to 95, D. 4 to 100
B: 72 to 88
Answer: B: 72 to 88 
Explanation: The range obtained by repeating a test is given by the formula: p ± 2 √p (100-p) / n
where,
p = prevalence of the study as established from previous studies n = sample size used for the present study
In this particular example, p = 80
n = 100.
Hence, the range estimated would be = 80 ± 2 √80 (100-80) / 100

80 ± 2 x 4
80 ± 8
72 to 88