给出字符串numerteks,即一个字母中的数字,您需要输出相应的整数.为此,修订了计数系统:数字1到999都是以基本字符串的组合表示的,一,二,三,四,五,六,七,八,九和较高的值十和一百.对于1到9来说,一切都是正常的.然而:10到999只用上述字符串的组合写入,空间分开.一些例子:10,11,12,等等:一十,一十一,一十二,等等. 20,30,..., 90:两十一,三十九,...,十一, 21, 31,..., 91:两十一,三十一,...,九十一.100是一百,305是三百,425是四百,999是九百.根据相应的数字,您需要输出一个整数,输出五个.
You can solve this problem by splitting the input string into individual words, and then mapping each word to its corresponding integer value. You can keep track of the current value as you iterate through the words, applying the appropriate arithmetic operations based on the words encountered (e.g. multiplying by 100 for "hundred", adding 10 for "ten", etc.). Here's some sample Python code to accomplish this:

```
def number_from_text(numbertext):
    nums = {"one": 1, "two": 2, "three": 3, "four": 4, "five": 5,
            "six": 6, "seven": 7, "eight": 8, "nine": 9, "ten": 10,
            "eleven": 11, "twelve": 12, "thirteen": 13, "fourteen": 14,
            "fifteen": 15, "sixteen": 16, "seventeen": 17, "eighteen": 18,
            "nineteen": 19, "twenty": 20, "thirty": 30, "forty": 40,
            "fifty": 50, "sixty": 60, "seventy": 70, "eighty": 80,
            "ninety": 90, "hundred": 100}

    total = 0
    last_num = None
    for word in numbertext.split():
        if word == "hundred":
            total *= 100
        elif word == "ten":
            if last_num and last_num < 10:
                total = (total - last_num) + nums.get(last_num * 10 + nums[word], 0)
            else:
                total += nums[word]
        else:
            total += nums.get(word, 0)
        last_num = nums.get(word, None)

    return total
```

Here, `nums` is a dictionary mapping each word to its corresponding integer value. We start with `total` equal to 0, and initialize `last_num` to `None` to keep track of the last number encountered.

We then loop through each word in `numbertext.split()`, and apply the appropriate arithmetic operation based on the word. If the word is "hundred", we multiply `total` by 100. If the word is "ten", we check if the last number encountered was less than 10 (since these cases require special handling), and modify `total` accordingly. If the word is any other number word, we simply add its integer value to `total`.

Finally, we return the total.