你是一个产品经理,目前领导一个团队开发一个新产品.不幸的是,你产品的最新版本失败了质量检查.由于每个版本都是基于之前的版本开发的,所以坏版本之后的所有版本都是坏的.假设你有n个版本 [1,2,..., n],你想找出第一个坏版本,这导致下面的所有版本都是坏的.你得到了一个 bool API isBadVersion ((version)) 返回版本是否坏.实现一个函数来找到第一个坏版本.你应该尽量减少对 API 的调用.
To find the first bad version, you can use binary search. 

Start with the middle version and check if it is bad. If it is, then all versions after it are also bad, so you check the left half. If it's not, then all versions before it are good, so you check the right half. Continue this process until you find the first bad version.

Here is an implementation of the function:

```
def firstBadVersion(n):
    """
    :type n: int
    :rtype: int
    """
    left = 1
    right = n
    while left < right:
        mid = (left + right) // 2
        if isBadVersion(mid):
            right = mid
        else:
            left = mid + 1
    return left
```

The function uses two pointers `left` and `right` to keep track of the range of versions we are looking at. We start with the entire range [1, n]. In each iteration of the while loop, we calculate the middle version and check if it is bad. If it is, we update our range to [left, mid], because all versions after `mid` are also bad. If it's not, we update our range to [mid+1, right], because all versions before `mid+1` are good. We continue this process until `left == right`, at which point we have found the first bad version.