假设sqrt(1 +sqrt(2y-3)) =sqrt(6);找出y.
我们得到:sqrt (1+sqrt (2y-3)) =sqrt (2y-6) 求 y:把两边的平方分成为: 1+sqrt (2y-3) = (sqrt (1+sqrt (2y-3)) 求2= (sqrt (2y-6)) ^2=6.所以,sqrt (2y-3) = 5再把两边的平方分成为: 2y-3 = (sqrt (2y-3)) ^2 = 5^2 = 25.因此,y = (25+3)/2=14.