给出两个字符串 s 和 t,如果 t 是 s 的反符号,则返回 true,否则返回 false. Anagram 是一个单词或句子,由重新排列不同的单词或句子的字母形成,通常使用所有原始字母一次.
You can solve this problem by creating two dictionaries to store the frequency of characters in both strings, and then compare them. If the dictionaries are equal, return true. Otherwise, return false.

Here's the Python code for the solution:

```
def is_anagram(s, t):
    if len(s) != len(t):
        return False
    
    s_dict = {}
    t_dict = {}
    
    for char in s:
        if char not in s_dict:
            s_dict[char] = 0
        s_dict[char] += 1
        
    for char in t:
        if char not in t_dict:
            t_dict[char] = 0
        t_dict[char] += 1
        
    return s_dict == t_dict
```

You can call this function by passing two strings as arguments and it will return True if the second string is an anagram of the first one, and False otherwise.