使用调试技术对以下函数进行逆向工程: f(x) = x^2+3
首先,我们需要观察函数的行为,使用一些基本的输入输出对.例如: * f(0) = 0^2 + 3 = 3 * f(1) = 1^2 + 3 = 4 * f(2) = 2^2 + 3 = 7 * f(3) = 3^2 + 3 = 12 从这些观察中,我们可以看到,对于任何值的x,函数返回了输入值的平方数加上一个常数值 3. 2. **测试边缘情况:**为了进一步确认我们的观察,让我们测试一些边缘情况,例如负值和较大的平方值. * f(-1) (f^2 + 3 = f^2 = f^2 = f^2 = f^2 = f^2 = f^3 = f^3 = c^3 = c^3 = c^3 = c^3 = x^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 = c^3 c^3 = c^3 = c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3 c^3