求满足sqrt(3x+5)/sqrt(6x+5)=sqrt(5)/3的x值.将答案表达为常数.
1. 两边的交叉乘法:sqrt(3x+5) /sqrt(6x+5) =sqrt(5) / 3成为sqrt(3x+5) =sqrt(5) *sqrt(6x+5) 2. 两边的平方,以消除根基: (3sqrt(3x+5))) ^2 = (sqrt(5) *sqrt(6x+5)) ^2 3. 简化: 9(3x+5) = 5(6x+5) 4. 求 x: 20 = 3x,所以x = 20/3 5. 通过验证它满足原始方程来检查解决方案.