给出二进制树的根,返回每个树节点的倾斜总和.树节点的倾斜是所有左子树节点值和所有右子树节点值的总和之间的绝对差异.如果一个节点没有左子,那么左子树节点值的总和将被视为0.如果节点没有右子,则规则类似.
To solve this problem, you can create a recursive function that traverses the tree and calculates the tilt for each node. Here is an algorithm that you can follow:

1. Initialize a variable called "tiltSum" to 0.
2. Write a recursive function called "calculateTilt" that takes a node as an argument.
3. In the function, check if the node is null. If it is, return 0.
4. Recursively call calculateTilt for the left subtree and the right subtree of the node.
5. Calculate the tilt for the current node by taking the absolute difference between the sum of the values in the left subtree and the sum of the values in the right subtree.
6. Add the tilt to the "tiltSum" variable.
7. Return the sum of the values in the left subtree, the sum of the values in the right subtree, and the value of the current node, added together.
8. Call the calculateTilt function with the root node as the argument.
9. Return the value of "tiltSum".

Here is the Python code that implements the algorithm:

```
class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right

class Solution:
    def findTilt(self, root: TreeNode) -> int:
        tiltSum = 0
        
        def calculateTilt(node):
            nonlocal tiltSum
            if not node:
                return 0
            
            leftSum = calculateTilt(node.left)
            rightSum = calculateTilt(node.right)
            tilt = abs(leftSum - rightSum)
            tiltSum += tilt
            
            return leftSum + rightSum + node.val
        
        calculateTilt(root)
        
        return tiltSum
```

Note: This code assumes that the TreeNode class has a "val" attribute that stores the value of the node, and "left" and "right" attributes that point to the left and right subtrees of the node.