在Java中解决:输入:行1:整数对的数量N.以下行:两个整数a和b (由空格分开).输出:对于每个整数a和b的N对,根据a2+b2分别大于,小于或等于 (a+b)2,在直线上显示>, <或 =.
Here's the solution in Java:
```
import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt(); // number of pairs

    for (int i = 0; i < n; i++) {
      int a = sc.nextInt();
      int b = sc.nextInt();
      int sumSquared = (a + b) * (a + b);
      int squaredSum = a * a + b * b;
      
      if (sumSquared < squaredSum) {
        System.out.println("<");
      } else if (sumSquared > squaredSum) {
        System.out.println(">");
      } else {
        System.out.println("=");
      }
    }
    sc.close();
  }
}
```
Explanation:
We input the number of pairs of integers, then scan the pairs one by one. Then we calculate the sum of squares and the square of the sum. Finally, we compare them and output '>', '<', or '=' depending on the comparison result.

Note: This solution assumes that the input is valid and follows the given format. It does not handle any exceptions or errors caused by invalid input.