这种方程是4x+5y=28
方程4x+5y=28是一个具有两个变量x和y的线性方程.由于它代表了xy平面上的直线,因此该方程有多种解决方案.为了解决y的问题,我们可以重新排列方程并将变量y分离:首先,我们可以从两边减去4x,以获得: 5y=-4x+28 接下来,我们可以把两边分为5,以获得y的值,以获得x: y= (-4/5) x+28/5 这是一个直线方程的斜率切口形式,斜率为 -4/5,而y切口为28/5.所以,对于任何x的值,我们可以使用这个方程找到y的相应值.另外,如果我们有 y的值,我们可以解决另一个方程的值.例如,如果 x=0 (x/4) = (x=0 (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5) = (x=0/5)),那么,如果 y=2=2=2=2=2=2=2=2=2=2=2=2=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3=3