Q:

Unique rows, considering two columns, in R, without order

Unlike questions I've found, I want to get the unique of two columns without order. 
I have a df: 
df<-cbind(c("a","b","c","b"),c("b","d","e","a"))
> df
     [,1] [,2]
 [1,] "a"  "b" 
 [2,] "b"  "d" 
 [3,] "c"  "e" 
 [4,] "b"  "a" 

In this case, row 1 and row 4 are "duplicates" in the sense that b-a is the same as b-a.
I know how to find unique of columns 1 and 2 but I would find each row unique under this approach.

A:

If it's just two columns, you can also use pmin and pmax, like this:
library(data.table)
unique(as.data.table(df)[, c("V1", "V2") := list(pmin(V1, V2),
                         pmax(V1, V2))], by = c("V1", "V2"))
#    V1 V2
# 1:  a  b
# 2:  b  d
# 3:  c  e

A similar approach using "dplyr" might be:
library(dplyr)
data.frame(df, stringsAsFactors = FALSE) %>% 
  mutate(key = paste0(pmin(X1, X2), pmax(X1, X2), sep = "")) %>% 
  distinct(key)
#   X1 X2 key
# 1  a  b  ab
# 2  b  d  bd
# 3  c  e  ce

A:

There are lot's of ways to do this, here is one:
unique(t(apply(df, 1, sort)))
duplicated(t(apply(df, 1, sort)))

One gives the unique rows, the other gives the mask.

A:

You could use igraph to create a undirected graph and then convert back to a data.frame
unique(get.data.frame(graph.data.frame(df, directed=FALSE),"edges"))

