Q:

Exception while validating a date string in Java

I have found nice function which is validating the format and correctness of date String. I wanted to upgrade it to validate only >= 1900 years. 
So this is what I found:
public boolean isDateValid(String date) {
    try {
        DateFormat df = new SimpleDateFormat("dd-MM-yyyy");
        df.setLenient(false);
        df.parse(date);
        return true;
    } catch (ParseException e) {
        return false;
    }
}

And this is my upgraded version:
public boolean isDateValid(String date) {
    try {
        DateFormat df = new SimpleDateFormat("dd-MM-yyyy");
        df.setLenient(false);
        df.parse(date);
        Integer year = Integer.parseInt(date.substring(6, 10));
        if (year>= 1900)
            return true;
        else
            return false;
    } catch (ParseException e) {
        return false;
    }
}

So instead of returning true I am checking if the year variable is greater or equal to 1900. The problem is when I run this function with "12-12-1xxx" (edit: or "12-12-1abc"). NumberFormatException is thrown while parsing year String to int. It definitely should not happen because ParseException should be thrown first, breaking the try {} block.
It looks like validation from first listing does not work properly because it accepts every "yyyy" part which begins with a number. Yet everything works fine for "12-12-xxxx" (edit: or "12-12-abcd").
EDIT:
Stop voting down my question and focus while you are reading. The question is very clear: why new SimpleDateFormat("dd-MM-yyyy").parse("12-12-1xxx") does not throw a ParseException? 

A:

As I understand from javadoc the SimpleDateFormat will take 1 as valid part of the year and will parse it. Instead you can try to validate date with regular expressions. You can find some examples here Regex to validate date format dd/mm/yyyy

