Q:

Unique array of objects

I have an array that looks like this:
var persons = [Person]()

And a person contains this:
id : Int
name : String
age : Int
gender : String

In my persons list I have multiple persons, but how do I sort this list on unique names?
I found this let unique = Array(Set(originals)) but it does not seem to work on a list of objects, I want to keep all the information of the object.
If my list contains these rows:
Adam, Adam, John, John, Michael, Nick, Tony

I only want to show:
Adam, John, Michael, Nick Tony

And I still want to be able to get Adams age for example.
Any ideas?
Edit
Person declaration
import Foundation

public class Person : NSObject {
    var id = ""
    var name = ""
    var age = 0
    var gender = ""
}

func ==(lhs: Person, rhs: Person) -> Bool {
    return lhs.name == rhs.name
}

A:

You need to add this extension to return an ordered set from your people array.
extension Collection where Element: Hashable {
    var orderedSet: [Element] {
        var set: Set<Element> = []
        return reduce(into: []){ set.insert($1).inserted ? $0.append($1) : ()  }
    }
}

You will also have to make your Person class Equatable:
func ==(lhs: Person, rhs: Person) -> Bool {
    return lhs.id == rhs.id
} 

class Person: Equatable { 
    let id: String 
    let name: String 
    init(id: String, name: String) { 
        self.id = id 
        self.name = name 
    } 
}

Testing 
let person1 = Person(id: "1", name: "Adam") 
let person2 = Person(id: "1", name: "Adam") 
let person3 = Person(id: "2", name: "John") 
let person4 = Person(id: "2", name: "John") 
let person5 = Person(id: "3", name: "Michael") 
let person6 = Person(id: "4", name: "Nick") 
let person7 = Person(id: "5", name: "Tony") 
let people = [person1,person2,person3,person4,person5,person6,person7] 
people.orderedSet //[{id "1", name "Adam"}, {id "2", name "John"}, {id "3", name "Michael"}, {id "4", name "Nick"}, {id "5", name "Tony"}]

