Q:

Calculate the sum of ILD

Input:
An integer
Output:
Sum of the input itself + the length of the input + each individual digit of the input.
nr + nr-length + {sum of digits} = output

Examples:
Input: 99
Output: 99 (nr) + 2 (nr-length) + (9 + 9) (digits) → 119
Input: 123
Output: 123 + 3 + (1 + 2 + 3) → 132
Challenge rules:

The input can also contain negative input, which are resolved special. The -/minus-sign is also +1 for the length, and is part of the first digit.
For example:  
Input: -123
Output: -123 + 4 + (-1 + 2 + 3) → -115
You can assume that the input nor output will ever be outside the range of an (32-bit) integer.

General rules:

This is code-golf, so shortest answer in bytes wins.
Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.
Standard rules apply for your answer, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.
Default Loopholes are forbidden.
If possible, please add a link with a test for your code.
Also, please add an explanation if necessary.

Test cases:
87901 → 87931
123 → 132
99 → 119
5 → 11
1 → 3
0 → 1
-3 → -4
-123 → -115
-900 → -905
-87901 → -87886

Semi-related: Count Sum of all Digits

A:

Python 2, 39 bytes
lambda x:x+len(`x`)+eval("+".join(`x`))

Test suite
Using the same eval-trick as in my Pyth-answer.

A:

05AB1E, 28 20 18 8 bytes
ÐgsS'+ýO

Explanation
Ð           # triplicate input
 g          # get length of input
  sS'+ý     # split input and merge with '+' as separator 
       O    # sum and implicitly display

Try it online
Saved 10 bytes thanks to @Adnan

A:

Pyth, 11 10 bytes
Thanks to @LeakyNun for a byte!
++vj\+`Ql`

Test suite
Explanation

++vj\+`Ql`QQ  # Q = input, last two implicitly added

  vj\+`Q      # Join the input on '+' and eval it
        l`Q   # Length of the input
           Q  # The input itself
++            # Add those three values to obtain the result

