Q:

8086 programming using TASM: pc to pc communication

.model small
.stack 100
.data
.code

mov ah,00h
mov al,0e3h
mov dx,00h
int 14h

back: nop

l1: mov ah,03h
    mov dx,00h
    int 14h

    and ah,01h
    cmp ah,01h
    jne l1

    mov ah,02h
    mov dx,00h
    int 21h

mov dl,al
mov ah,02h
int 21h

jmb back
mov ah,4ch
int 21h

end

This a pc to pc commnication receiver program.  I would like to know
why it uses the mov dx,00h command and what mov al,0e3h means?

A:

Take a look here. AX will contain the transmission parameters (baud rate etc) and DX chooses the port number. E3 = 9600 rate, no parity, two stop bits, 8 bits char size.

