Q:

Can you make the constructor of base class in derived class?

Is this possible that we can make the constructor of base class in derived class?   
public class A 
    {
     // some stuff
    }

    public class B:A
    {

     public A()
     { }

     public B() { }
    }

A:

No you can't do that and it wouldn't be sensible. You can call  base class constructor in child class using base keyword. 
public class B : A
{
    public B()
        : base() //base class default constructor call. 
    { }
}

