Q:

How to continue javascript execution when receiving errors during load

Not sure the best way to phrase the question, but suppose you are using jQuery to setup various things like so:
<script>

    function doSecond(){
        alert("Hi");
    }

    function dofirst(){
        var x = asdasd;
    }

    $(dofirst);
    $(doSecond);

</script>

So, imagine that dofirst and dosecond are completely independent. If dofirst throws an exception, which of course it will, then doSecond will never fire. I understand why this happens, but I'm wondering if there is a way of getting around this without having to wrap EVERY kind of jQuery handler that I want to set up in a try catch. E.g., I'd rather not do:
try{
 $(doFirst);
}
catch{
 //maybe log here?
}

try{
 $(doSecond);
}
catch{
 //maybe log here?
}

Now, if you're wondering why I want to do this? Well, take for example the code on the page you're looking at right now:
<script type="text/javascript">
        $(function() {
            $('#title').focus(function() { $('#how-to-tag').hide(); $('#how-to-format').hide(); $('#how-to-title').fadeIn('slow'); });
            $('#wmd-input').focus(function() { $('#how-to-tag').hide(); $('#how-to-format').fadeIn('slow'); $('#how-to-title').hide(); });
            $('#tagnames').focus(function() { $('#how-to-tag').fadeIn('slow'); $('#how-to-format').hide(); $('#how-to-title').hide(); });
        });
    </script>

Is it really necessary to have certain dom elements fade out when you click on them? No. But if you make a mistake in that function, then quite possibly other javascript that you really, really do need to run may never get setup. 

A:

A couple of ways to ensure things run independently of each other:

As you said, try/catch around each
Call each in a setTimeout (or
whatever the jQuery syntactic sugar
is for that)
Separate into different <script>
blocks

