Q:

Binomial Probability Problem -HARD!

In the final match a boxer is facing another boxer and is expected to win 48% of the time. In reality they win 80% of the time.
What is the probability of that occurring in 10 matches?
2) In the very next match (in a different tournament), the boxer who won the previous match only wins 40% of the time.

With the winning rate in the previous match, whats the probability of seeing that winning rate in 10 matches?

How would you go about this problem? I believe this a binomial problem but i do not know what the 48% and 80% are. Is one the varience and the other the expected mean? I dont know what equations i need in order to solve this problem. Also, how could I calculate this on excel. So if someone could guide me through this that would be great.

A:

Both questions are VERY poorly written.
I'm pretty sure that the intention of the first question is for you to calculate the probability of winning exactly 8 matches if the probability of each win is 0.48
$$ P_8 = \binom{10}8 (0.48)^8 (0.52)^2  $$
I can't imagine what it is the second question wants.

