Q:

Check what numbers in a list are divisible by certain numbers?

Write a function that receives a list of numbers
and a list of terms and returns only the elements that are divisible
by all of those terms. You must use two nested list comprehensions to solve it.
divisible_numbers([12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1], [2, 3])  # returns  [12, 6]
def divisible_numbers(a_list, a_list_of_terms):
I have a vague pseudo code so far, that consists of check list, check if divisible if it is append to a new list,  check new list check if divisible by next term and repeat until, you have gone through all terms, I don't want anyone to do this for me but maybe a hint in the correct direction?

A:

The inner expression should check if for a particular number, that number is evenly divisible by all of the terms in the second list
all(i%j==0 for j in a_list_of_terms)

Then an outer list comprehension to iterate through the items of the first list
[i for i in a_list if all(i%j==0 for j in a_list_of_terms)]

All together
def divisible_numbers(a_list, a_list_of_terms):
    return [i for i in a_list if all(i%j==0 for j in a_list_of_terms)]

Testing
>>> divisible_numbers([12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1], [2, 3])
[12, 6]

