You are given an array consisting of n integers a_1, a_2, ..., a_n. Initially a_x = 1, all other elements are equal to 0.

You have to perform m operations. During the i-th operation, you choose two indices c and d such that l_i ≤ c, d ≤ r_i, and swap a_c and a_d.

Calculate the number of indices k such that it is possible to choose the operations so that a_k = 1 in the end.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. Then the description of t testcases follow.

The first line of each test case contains three integers n, x and m (1 ≤ n ≤ 10^9; 1 ≤ m ≤ 100; 1 ≤ x ≤ n).

Each of next m lines contains the descriptions of the operations; the i-th line contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n).

Output

For each test case print one integer — the number of indices k such that it is possible to choose the operations so that a_k = 1 in the end.

Example

Input


3
6 4 3
1 6
2 3
5 5
4 1 2
2 4
1 2
3 3 2
2 3
1 2


Output


6
2
3

Note

In the first test case, it is possible to achieve a_k = 1 for every k. To do so, you may use the following operations:

  1. swap a_k and a_4; 
  2. swap a_2 and a_2; 
  3. swap a_5 and a_5. 



In the second test case, only k = 1 and k = 2 are possible answers. To achieve a_1 = 1, you have to swap a_1 and a_1 during the second operation. To achieve a_2 = 1, you have to swap a_1 and a_2 during the second operation.
import java.io.*;
import java.text.DecimalFormat;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        int t = in.nextInt();
        for (int i = 0; i < t; i++)
            Solution.solve(in, out);
        out.close();
    }

    static long gcd(long x, long y) {
        if (x == 0)
            return y;
        if (y == 0)
            return x;
        long r = 0, a, b;
        a = Math.max(x, y);
        b = Math.min(x, y);
        r = b;
        while (a % b != 0) {
            r = a % b;
            a = b;
            b = r;
        }
        return r;
    }

    static long modulo(long a, long b, long c) {
        long x = 1, y = a % c;
        while (b > 0) {
            if (b % 2 == 1)
                x = (x * y) % c;
            y = (y * y) % c;
            b = b >> 1;
        }
        return x % c;
    }

    public static void debug(Object... o) {
        System.err.println(Arrays.deepToString(o));
    }

    static String printPrecision(double d) {
        DecimalFormat ft = new DecimalFormat("0.00000000000");
        return String.valueOf(ft.format(d));
    }

    static int countBit(long mask) {
        int ans = 0;
        while (mask != 0) {
            mask &= (mask - 1);
            ans++;
        }
        return ans;
    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public double nextDouble() {
            return Double.parseDouble(next());
        }

        public int[] readArray(int n) {
            int[] arr = new int[n];
            for (int i = 0; i < n; i++) arr[i] = nextInt();
            return arr;
        }
    }
}

class Solution {
    static long mod = (long) 1e9 + 7;
    static long mod1 = 998244353;
    static Main obj = new Main();

    public static void solve(Main.InputReader in, PrintWriter out) {
        int n = in.nextInt();
        int x = in.nextInt();
        int m = in.nextInt();
        long count = 1;
        int start = -1;
        int end = -1;
        for (int i = 0; i < m; i++) {
            int l = in.nextInt();
            int r = in.nextInt();
            if (start == -1 && l <= x && r >= x) {
                start = l;
                end = r;
            } else if (l < start && r > end) {
                start = l;
                end = r;
            } else if (l<start && r<=end && r>=start){
                start=l;
            }
            else if(l>=start && r>end && l<=end)
            {
                end=r;
            }
        }
        out.println(end - start + 1);
    }
}