Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
for _ in range(int(input())):
    t=input()
    if(len(t)>2):
        a=t[0]
        if(t.count('0')==len(t) or t.count('1')==len(t) ):
            print(t)
            continue
        if(a=='0'):
            ans=''
            v=0
            for i in t:
                if(v%2==0):
                    if(i=='0'):
                        ans+='0'
                        v+=1
                    else:
                        ans+='01'
                else:
                    if(i=='1'):
                        ans+='1'
                        v+=1
                    else:
                        ans+='10'
                
        if(a=='1'):
            ans=''
            v=1
            for i in t:
                if(v%2==0):
                    if(i=='0'):
                        ans+='0'
                        v+=1
                    else:
                        ans+='01'
                else:
                    if(i=='1'):
                        ans+='1'
                        v+=1
                    else:
                        ans+='10'
    
        print(ans)

    else:
        print(t)
'''
for _ in range(int(input())):
    x,y=map(int,input().split())
    a,b=map(int,input().split())
    if(x==0 and y==0):
        print(0)
        continue
    if(x==0):
        print(y*a)
        continue
    if(y==0):
        print(x*a)
        continue
    if(b>=2*a):
        print((x+y)*a)
    else:
        d=abs(x-y)
        print(min(x,y)*b + d*a)
    
'''