Recently Lynyrd and Skynyrd went to a shop where Lynyrd bought a permutation p of length n, and Skynyrd bought an array a of length m, consisting of integers from 1 to n. 

Lynyrd and Skynyrd became bored, so they asked you q queries, each of which has the following form: "does the subsegment of a from the l-th to the r-th positions, inclusive, have a subsequence that is a cyclic shift of p?" Please answer the queries.

A permutation of length n is a sequence of n integers such that each integer from 1 to n appears exactly once in it.

A cyclic shift of a permutation (p_1, p_2, …, p_n) is a permutation (p_i, p_{i + 1}, …, p_{n}, p_1, p_2, …, p_{i - 1}) for some i from 1 to n. For example, a permutation (2, 1, 3) has three distinct cyclic shifts: (2, 1, 3), (1, 3, 2), (3, 2, 1).

A subsequence of a subsegment of array a from the l-th to the r-th positions, inclusive, is a sequence a_{i_1}, a_{i_2}, …, a_{i_k} for some i_1, i_2, …, i_k such that l ≤ i_1 < i_2 < … < i_k ≤ r.

Input

The first line contains three integers n, m, q (1 ≤ n, m, q ≤ 2 ⋅ 10^5) — the length of the permutation p, the length of the array a and the number of queries.

The next line contains n integers from 1 to n, where the i-th of them is the i-th element of the permutation. Each integer from 1 to n appears exactly once.

The next line contains m integers from 1 to n, the i-th of them is the i-th element of the array a.

The next q lines describe queries. The i-th of these lines contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ m), meaning that the i-th query is about the subsegment of the array from the l_i-th to the r_i-th positions, inclusive.

Output

Print a single string of length q, consisting of 0 and 1, the digit on the i-th positions should be 1, if the subsegment of array a from the l_i-th to the r_i-th positions, inclusive, contains a subsequence that is a cyclic shift of p, and 0 otherwise.

Examples

Input

3 6 3
2 1 3
1 2 3 1 2 3
1 5
2 6
3 5


Output

110


Input

2 4 3
2 1
1 1 2 2
1 2
2 3
3 4


Output

010

Note

In the first example the segment from the 1-st to the 5-th positions is 1, 2, 3, 1, 2. There is a subsequence 1, 3, 2 that is a cyclic shift of the permutation. The subsegment from the 2-nd to the 6-th positions also contains a subsequence 2, 1, 3 that is equal to the permutation. The subsegment from the 3-rd to the 5-th positions is 3, 1, 2, there is only one subsequence of length 3 (3, 1, 2), but it is not a cyclic shift of the permutation.

In the second example the possible cyclic shifts are 1, 2 and 2, 1. The subsegment from the 1-st to the 2-nd positions is 1, 1, its subsequences are not cyclic shifts of the permutation. The subsegment from the 2-nd to the 3-rd positions is 1, 2, it coincides with the permutation. The subsegment from the 3 to the 4 positions is 2, 2, its subsequences are not cyclic shifts of the permutation.
import java.io.*; 
import java.util.*; 


import java.io.*; 
import java.util.*; 


public class D  
{
   public static int up[][];
   public static int maxe;
   public static void main(String[] args) throws Exception {
      FastScanner sc = new FastScanner();
      PrintWriter out = new PrintWriter(System.out);
      int N = sc.nextInt();
      int M = sc.nextInt();
      int Q = sc.nextInt();
      
      int[] perm = sc.nextInts(N);
      int[] arr = sc.nextInts(M);
      Map<Integer, Integer> pos = new HashMap<Integer, Integer>();
      for(int i = 0; i < N; i++){
         pos.put(perm[i], i);
      }
      maxe = (int)(Math.log(M)/Math.log(2)) + 1;
      up = new int[M][maxe];
      for(int i =  0; i < M; i++){
         Arrays.fill(up[i], -1);
      }
      Stack<Integer> stack[] = new Stack[N+1];
      for(int i = 0; i < N+1; i++){
         stack[i] = new Stack<Integer>();
      }
      for(int i = 0; i < M; i++){
         int prevc = perm[(pos.get(arr[i])+N-1)%N];
         if(!stack[prevc].isEmpty()){
            up[i][0] = stack[prevc].peek();
         }
         stack[arr[i]].push(i);
      }
      for(int l = 1; l < maxe; l++){
         for(int j = 0; j < M; j++){
            if(up[j][l-1] != -1) up[j][l] = up[up[j][l-1]][l-1];
         }
      }
      int[] ans = new int[M];
      int lastpos = -1;
      for(int i = 0; i < M; i++){
         lastpos = Math.max(lastpos, lift(i, N-1));
         ans[i] = lastpos;
      }
      for(int q = 0; q < Q; q++){
         int l = sc.nextInt()-1;
         int r = sc.nextInt()-1;
         if(ans[r] >= l){
            out.print(1);
         }
         else{
            out.print(0);
         }
      }
      out.close();
   }
   public static int lift(int node, int k){
      for(int l = 0; l < maxe; l++){
         if(node != -1){
            if((k & (1 << l)) != 0){
               node = up[node][l];
            }
         }
      }
      return node;
   }
   
   
   
   static class FastScanner {
      private int BS = 1 << 16;
      private char NC = (char) 0;
      private byte[] buf = new byte[BS];
      private int bId = 0, size = 0;
      private char c = NC;
      private double cnt = 1;
      private BufferedInputStream in;
   
      public FastScanner() {
         in = new BufferedInputStream(System.in, BS);
      }
   
      public FastScanner(String s) {
         try {
            in = new BufferedInputStream(new FileInputStream(new File(s)), BS);
         } catch (Exception e) {
            in = new BufferedInputStream(System.in, BS);
         }
      }
   
      private char getChar() {
         while (bId == size) {
            try {
               size = in.read(buf);
            } catch (Exception e) {
               return NC;
            }
            if (size == -1) 
               return NC;
            bId = 0;
         }
         return (char) buf[bId++];
      }
   
      public int nextInt() {
         return (int) nextLong();
      }
   
      public int[] nextInts(int N) {
         int[] res = new int[N];
         for (int i = 0; i < N; i++) {
            res[i] = (int) nextLong();
         }
         return res;
      }
   
      public long[] nextLongs(int N) {
         long[] res = new long[N];
         for (int i = 0; i < N; i++) {
            res[i] = nextLong();
         }
         return res;
      }
   
      public long nextLong() {
         cnt = 1;
         boolean neg = false;
         if (c == NC) c = getChar();
         for (; (c < '0' || c > '9'); c = getChar()) {
            if (c == '-') neg = true;
         }
         long res = 0;
         for (; c >= '0' && c <= '9'; c = getChar()) {
            res = (res << 3) + (res << 1) + c - '0';
            cnt *= 10;
         }
         return neg ? -res : res;
      }
   
      public double nextDouble() {
         double cur = nextLong();
         return c != '.' ? cur : cur + nextLong() / cnt;
      }
   
      public double[] nextDoubles(int N) {
         double[] res = new double[N];
         for (int i = 0; i < N; i++) {
            res[i] = nextDouble();
         }
         return res;
      }
   
      public String next() {
         StringBuilder res = new StringBuilder();
         while (c <= 32) c = getChar();
         while (c > 32) {
            res.append(c);
            c = getChar();
         }
         return res.toString();
      }
   
      public String nextLine() {
         StringBuilder res = new StringBuilder();
         while (c <= 32) c = getChar();
         while (c != '\n') {
            res.append(c);
            c = getChar();
         }
         return res.toString();
      }
   
      public boolean hasNext() {
         if (c > 32) 
            return true;
         while (true) {
            c = getChar();
            if (c == NC) 
               return false;
            else if (c > 32) 
               return true;
         }
      }
   }

   static void ASSERT(boolean assertion, String message) {
      if (!assertion) throw new AssertionError(message);
   }
}
