Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.

import java.io.*;
import java.util.*;
import java.io.FileInputStream;
 

 
public  class solution{
	static BufferedReader ob;
	
	
	public static  void main (String args[])throws IOException{
		

		 ob =  new BufferedReader(new InputStreamReader(System.in));
		  
		 int t = Integer.parseInt(ob.readLine());
		 
		 while(t --> 0) {
		 String s = ob.readLine();
		 
		 int o = 0;
		 int z = 0;
		 
		 for(char c : s.toCharArray()) {
			 if(c == '1') {
				 o++;
			 }else {
				 z++;
			 }
		 }
		 
		 if(o == 0 || z == 0) {
			 System.out.println(s);
	
		 }else {
			 for(int i = 0; i < s.length(); i++) {
				 System.out.print("10");
			 }
			 System.out.println();
		 }
		 }
	}
  }