Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.

He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle a.

Will the robot be able to build the fence Emuskald wants? In other words, is there a regular polygon which angles are equal to a?

Input

The first line of input contains an integer t (0 < t < 180) — the number of tests. Each of the following t lines contains a single integer a (0 < a < 180) — the angle the robot can make corners at measured in degrees.

Output

For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible.

Examples

Input

3
30
60
90


Output

NO
YES
YES

Note

In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <image>.

In the second test case, the fence is a regular triangle, and in the last test case — a square.
import os
import sys
from atexit import register
from io import BytesIO

sys.stdin = BytesIO(os.read(0, os.fstat(0).st_size))
sys.stdout = BytesIO()
register(lambda: os.write(1, sys.stdout.getvalue()))

input = lambda: sys.stdin.readline().rstrip('\r\n')

# ref. https://codeforces.com/blog/entry/71884
# 1) inp(), For taking integer inputs.
# 2) inlt(), For taking List inputs.
# 3) insr(), For taking string inputs. 
#           Actually it returns a List of Characters, 
#           instead of a string, which is easier to use in Python, 
#           because in Python, Strings are Immutable.
# 4) invr(), For taking space seperated integer variable inputs.

def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    s = input()
    return(list(s[:len(s)]))
def invr():
    return(map(int,input().split()))

n = inp()

while n > 0:
    x = float(inp())
    s = -360/(x - 180)
    
    if s - int(s) == 0:
        sys.stdout.write('YES\n')
    else:
        sys.stdout.write('NO\n')

    n-=1
