Monocarp is playing a game "Assimilation IV". In this game he manages a great empire: builds cities and conquers new lands.

Monocarp's empire has n cities. In order to conquer new lands he plans to build one Monument in each city. The game is turn-based and, since Monocarp is still amateur, he builds exactly one Monument per turn.

Monocarp has m points on the map he'd like to control using the constructed Monuments. For each point he knows the distance between it and each city. Monuments work in the following way: when built in some city, a Monument controls all points at distance at most 1 to this city. Next turn, the Monument controls all points at distance at most 2, the turn after — at distance at most 3, and so on. Monocarp will build n Monuments in n turns and his empire will conquer all points that are controlled by at least one Monument.

Monocarp can't figure out any strategy, so during each turn he will choose a city for a Monument randomly among all remaining cities (cities without Monuments). Monocarp wants to know how many points (among m of them) he will conquer at the end of turn number n. Help him to calculate the expected number of conquered points!

Input

The first line contains two integers n and m (1 ≤ n ≤ 20; 1 ≤ m ≤ 5 ⋅ 10^4) — the number of cities and the number of points.

Next n lines contains m integers each: the j-th integer of the i-th line d_{i, j} (1 ≤ d_{i, j} ≤ n + 1) is the distance between the i-th city and the j-th point.

Output

It can be shown that the expected number of points Monocarp conquers at the end of the n-th turn can be represented as an irreducible fraction x/y. Print this fraction modulo 998 244 353, i. e. value x ⋅ y^{-1} mod 998244353 where y^{-1} is such number that y ⋅ y^{-1} mod 998244353 = 1.

Example

Input


3 5
1 4 4 3 4
1 4 1 4 2
1 4 4 4 3


Output


166374062

Note

Let's look at all possible orders of cities Monuments will be build in: 

  * [1, 2, 3]: 
    * the first city controls all points at distance at most 3, in other words, points 1 and 4; 
    * the second city controls all points at distance at most 2, or points 1, 3 and 5; 
    * the third city controls all points at distance at most 1, or point 1. 
In total, 4 points are controlled. 
  * [1, 3, 2]: the first city controls points 1 and 4; the second city — points 1 and 3; the third city — point 1. In total, 3 points. 
  * [2, 1, 3]: the first city controls point 1; the second city — points 1, 3 and 5; the third city — point 1. In total, 3 points. 
  * [2, 3, 1]: the first city controls point 1; the second city — points 1, 3 and 5; the third city — point 1. In total, 3 points. 
  * [3, 1, 2]: the first city controls point 1; the second city — points 1 and 3; the third city — points 1 and 5. In total, 3 points. 
  * [3, 2, 1]: the first city controls point 1; the second city — points 1, 3 and 5; the third city — points 1 and 5. In total, 3 points. 

The expected number of controlled points is (4 + 3 + 3 + 3 + 3 + 3)/(6) = 19/6 or 19 ⋅ 6^{-1} ≡ 19 ⋅ 166374059 ≡ 166374062 \pmod{998244353}
import java.util.*;
import java.io.*;

public class Sol{
static InputStream inputStream = System.in;
static OutputStream outputStream = System.out;
static FastReader in=new FastReader(inputStream);
static PrintWriter out=new PrintWriter(outputStream);

static class FastReader 
{ 
  BufferedReader br; 
  StringTokenizer st; 
 
  public FastReader(InputStream in) 
  { 
      br = new BufferedReader(new
               InputStreamReader(System.in)); 
  } 
 
  public String next() 
  { 
      while (st == null || !st.hasMoreElements()) 
      { 
          try
          { 
              st = new StringTokenizer(br.readLine()); 
          } 
          catch (IOException  e) 
          { 
              e.printStackTrace(); 
          } 
      } 
      return st.nextToken(); 
  } 
 
  public int nextInt() 
  { 
      return Integer.parseInt(next()); 
  } 
 
  public long nextLong() 
  { 
      return Long.parseLong(next()); 
  } 
 
 public  double nextDouble() 
  { 
      return Double.parseDouble(next()); 
  } 
 
 
  String nextLine() 
  { 
      String str = ""; 
      try
      { 
          str = br.readLine(); 
      } 
      catch (IOException e) 
      { 
          e.printStackTrace(); 
      } 
      return str; 
  } 
}



//----------------------------------------------------------------------------------------------//

//----------------S  T  A  R  T  ---------------------------------------------------------------//

//----------------------------------------------------------------------------------------------//

/*linear sieve nlogn
int n=(int)Math.pow(10,6)+100;
long mod=998244353;
long d[]=new long[n];

for(int i=1;i<n;i++){ for(int j=i; j<n; j+=i){ d[j] += 1; }}

long pre[]=new long[n];

pre[1]=1;d[1]=1;
for(int i=2;i<n;i++){d[i]+=pre[i-1]%mod;pre[i] += (pre[i-1]+d[i])%mod;}*/

static class Pair {
        int id;long val;
        public Pair(int id,long val) {
          
          this.id=id;
         this.val=val;
        }
       
      }


/*----------DFS-------------
static void DFS(int v,int p){
dp[0][v]=0;dp[1][v]=0;
for(int u:adj[v]){
if(u==p)continue;
DFS(u,v);
dp[0][v]+=Math.max(Math.abs(A[0][u]-A[0][v]) + dp[0][u], Math.abs(A[1][u]-A[0][v]) + dp[1][u] );
dp[1][v]+=Math.max(Math.abs(A[0][u]-A[1][v]) + dp[0][u], Math.abs(A[1][u]-A[1][v]) + dp[1][u] );
}

}

static int N=(int)Math.pow(10,5)+10;
static ArrayList<Integer> adj[]=new ArrayList[N];
static long dp[][]=new long[2][N];
static long A[][]=new long[2][N];

-----------DFS--------------
*/
/*static class Edge implements Comparable<Edge>{
int destination;long cost;
Edge(int destination,long cost){this.cost=cost;this.destination=destination;}

@Override

		public int compareTo(Edge o) {
			return Long.compare(cost, o.cost);
		}
}

*/
static long mod  = 998244353;
  
// Function to return the GCD of given numbers
 static long gcd(long a, long b)
{
    if (a == 0)
        return b;
    return gcd(b % a, a);
}
  
// Recursive function to return (x ^ n) % m
static long modexp(long x, long n)
{
    if (n == 0) {
        return 1;
    }
    else if (n % 2 == 0) {
        return modexp((x * x) % mod, n / 2);
    }
    else {
        return (x * modexp((x * x) % mod, (n - 1) / 2) % mod);
    }
}
  
// Function to return the fraction modulo mod
static long getFractionModulo(long a, long b)
{
    long c = gcd(a, b);
  
    a = a / c;
    b = b / c;
  
    // (b ^ m-2) % m
    long  d = modexp(b, mod - 2);
  
    // Final answer
    long ans = ((a % mod) * (d % mod)) % mod;
  
    return ans;
}
  


/*----------nCx---------------
long Comb[][]=new long[61][61];

for(int i=1;i<=60;i++){Comb[i][0]=1;}
for(int i=1;i<=60;i++){Comb[i][1]=i;Comb[i][i]=1;}
for(int i=2;i<=60;i++){for(int j=1;j<i;j++){Comb[i][j]=Comb[i-1][j]+Comb[i-1][j-1];}}
----------nCx------------------
*/

public static void main(String []args){

int t=1;

while(t-->0){

int n=in.nextInt();int m=in.nextInt();
long x=1; long b=1;
while(x<=n){b*=x;  x++;}

long dp[][]=new long[m+1][n+1];
for(int i=1;i<=n;i++){for(int j=1;j<=m;j++){dp[j][i]=in.nextLong();}}

long a=0;
for(int i=1;i<=m;i++){ Arrays.sort(dp[i]);
            long count=0;long res=1;         
            for(int j=1;j<=n;j++){
                  
               
                  res*=( dp[i][j]-1-count );res%=mod;count++;       
            }  
            
            a+=b-res;
            a%=mod;
            
      }
b%=mod;
//out.println(a+" "+b);

out.println(getFractionModulo(a,b));
}out.close();}}