Let us call a pair of integer numbers m-perfect, if at least one number in the pair is greater than or equal to m. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not.

Two integers x, y are written on the blackboard. It is allowed to erase one of them and replace it with the sum of the numbers, (x + y).

What is the minimum number of such operations one has to perform in order to make the given pair of integers m-perfect?

Input

Single line of the input contains three integers x, y and m ( - 1018 ≤ x, y, m ≤ 1018).

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preffered to use the cin, cout streams or the %I64d specifier.

Output

Print the minimum number of operations or "-1" (without quotes), if it is impossible to transform the given pair to the m-perfect one.

Examples

Input

1 2 5


Output

2


Input

-1 4 15


Output

4


Input

0 -1 5


Output

-1

Note

In the first sample the following sequence of operations is suitable: (1, 2) <image> (3, 2) <image> (5, 2).

In the second sample: (-1, 4) <image> (3, 4) <image> (7, 4) <image> (11, 4) <image> (15, 4).

Finally, in the third sample x, y cannot be made positive, hence there is no proper sequence of operations.
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.InputMismatchException;
import java.io.PrintStream;
import java.io.BufferedReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.io.Writer;
import java.util.StringTokenizer;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 * @author RiaD
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Reader in = new Reader(inputStream);
        OutputWriter out = new OutputWriter(outputStream);
        TaskA solver = new TaskA();
        solver.solve(1, in, out);
        out.close();
    }
}

class TaskA {
    public void solve(int testNumber, Reader in, OutputWriter out) {
        long x = in.nextLong();

        long y = in.nextLong();
        long m = in.nextLong();

        long ans = 0;
        while(true) {
           
            if(x >= m || y >= m) {

                break;
            }
            if(x <= 0 && y <= 0) {
                out.print(-1)
                ;
                return;
            }
            if(x > y) {
                long tmp = x;
                x = y;
                y = tmp;
            }

            if(x < 0) {
                long k = (-x) / y;
                ans += k;
                x += k * y;
            }
            ++ans;
            x = x + y;
        }

        out.println(ans);
    }
}

class Reader {
    private BufferedReader reader;
    private StringTokenizer tokenizer;

    public Reader(BufferedReader reader) {
        this.reader = reader;
    }

    public Reader(InputStream stream) {
        this(new BufferedReader(new InputStreamReader(stream)));
    }

    public String nextString() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            tokenizer = new StringTokenizer(readLine());
        }
        return tokenizer.nextToken();
    }

    public long nextLong() {
        return Long.parseLong(nextString());
    }

    private String readLine() {
        try {
            return reader.readLine();
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }
}

class OutputWriter extends PrintWriter {

    public OutputWriter(OutputStream out) {
        super(out);
    }

    public OutputWriter(java.io.Writer writer){
        super(writer);
    }

    }