Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.

Help Kefa cope with this task!

Input

The first line contains integer n (1 ≤ n ≤ 105).

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109).

Output

Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.

Examples

Input

6
2 2 1 3 4 1


Output

3

Input

3
2 2 9


Output

3

Note

In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.

In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.
import sys
from collections import *
from math import *
import re
def sieve(n):
    prime=[True for i in range(n+1)]
    p=2
    while p*p<=n:
        if prime[p]==True:
            for i in range(p*p,n+1,p):
                prime[i]=False
        p+=1
    c=0
    for i in range(2,n):
        if prime[i]:
            #print(i)
            c+=1
    return c

def iseven(n):return[False,True][0 if n%2 else 1]
def inp_arr():return list(map(int,input().split()))
def inp():return map(int,input().split())
def lcm(a,b):return (a*b)/gcd(a,b)
max_int = sys.maxsize
mod = 10**9+7

n=int(input())
arr=inp_arr()
include,ans=1,0
for i in range(1,n):
    if arr[i]>=arr[i-1]:include+=1
    else:
        ans=max(ans,include)
        include=1
print(max(ans,include))