Nicholas has an array a that contains n distinct integers from 1 to n. In other words, Nicholas has a permutation of size n.

Nicholas want the minimum element (integer 1) and the maximum element (integer n) to be as far as possible from each other. He wants to perform exactly one swap in order to maximize the distance between the minimum and the maximum elements. The distance between two elements is considered to be equal to the absolute difference between their positions.

Input

The first line of the input contains a single integer n (2 ≤ n ≤ 100) — the size of the permutation.

The second line of the input contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ n), where ai is equal to the element at the i-th position.

Output

Print a single integer — the maximum possible distance between the minimum and the maximum elements Nicholas can achieve by performing exactly one swap.

Examples

Input

5
4 5 1 3 2


Output

3


Input

7
1 6 5 3 4 7 2


Output

6


Input

6
6 5 4 3 2 1


Output

5

Note

In the first sample, one may obtain the optimal answer by swapping elements 1 and 2.

In the second sample, the minimum and the maximum elements will be located in the opposite ends of the array if we swap 7 and 2.

In the third sample, the distance between the minimum and the maximum elements is already maximum possible, so we just perform some unnecessary swap, for example, one can swap 5 and 2.
import java.io.*;
import java.math.*;
import java.util.*;
/**
 * @author ramilagger
 *
 */
public class Main {

    final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;



    public void solve() throws Exception {

        int n = nextInt();
        int[] a = nextArray(n);
        int max = Integer.MIN_VALUE;
        int min = Integer.MAX_VALUE;
        int mini = 0;
        int maxi = 0;
        for (int i = 0; i < n; i++) {
            if(a[i] > max){
                max = a[i];
                maxi = i;
            }if(a[i] < min){
                mini = i;
                min = a[i];
            }
        }
        if(mini == 0 || maxi == 0 || maxi == n - 1 || mini == n - 1){
            pw.println(n - 1);
        }else {
            max = Math.max(mini,maxi);
            min = Math.min(mini,maxi);
            pw.println(Math.max(n - 1 - min, max));
        }
    }

    public void run() throws Exception {
        long start = System.currentTimeMillis();
        solve();
        if(!ONLINE_JUDGE){
            long end = System.currentTimeMillis();
            System.err.println(end - start + " ms");
        }
        pw.close();
    }

    public Main() throws Exception {

        br = (ONLINE_JUDGE) ? new BufferedReader(new InputStreamReader(System.in))
                : new BufferedReader(new FileReader("in.txt"));

        pw = (ONLINE_JUDGE) ?
                new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)))
                : new PrintWriter(new BufferedWriter(new FileWriter("out.txt")));

    }

    public static void main(String[] args) throws Exception {
        new Main().run();
    }

    public String next() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(br.readLine());
        }
        return st.nextToken();
    }

    public int nextInt() throws IOException {
        return Integer.parseInt(next());
    }

    public long nextLong() throws IOException {
        return Long.parseLong(next());
    }

    public double nextDouble() throws IOException {
        return Double.parseDouble(next());
    }

    public BigInteger nextBigInteger () throws IOException {
        return new BigInteger(next());
    }

    public String nextLine() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            return br.readLine();
        }
        StringBuilder sb = new StringBuilder(st.nextToken());
        while (st.hasMoreTokens()){
            sb.append(" " + st.nextToken());
        }
        return sb.toString();
    }

    public int[] nextArray(int n) throws IOException {
        int[] temp = new int[n];
        for (int i = 0; i < n; i++) {
            temp[i] = nextInt();
        }
        return temp;
    }

    public long[] nextLArray(int n) throws IOException {
        long[] temp = new long[n];
        for (int i = 0; i < n; i++) {
            temp[i] = nextLong();
        }
        return temp;
    }

    final BufferedReader br;
    final PrintWriter pw;
    StringTokenizer st;
}