Iahub is a big fan of tourists. He wants to become a tourist himself, so he planned a trip. There are n destinations on a straight road that Iahub wants to visit. Iahub starts the excursion from kilometer 0. The n destinations are described by a non-negative integers sequence a1, a2, ..., an. The number ak represents that the kth destination is at distance ak kilometers from the starting point. No two destinations are located in the same place. 

Iahub wants to visit each destination only once. Note that, crossing through a destination is not considered visiting, unless Iahub explicitly wants to visit it at that point. Also, after Iahub visits his last destination, he doesn't come back to kilometer 0, as he stops his trip at the last destination. 

The distance between destination located at kilometer x and next destination, located at kilometer y, is |x - y| kilometers. We call a "route" an order of visiting the destinations. Iahub can visit destinations in any order he wants, as long as he visits all n destinations and he doesn't visit a destination more than once. 

Iahub starts writing out on a paper all possible routes and for each of them, he notes the total distance he would walk. He's interested in the average number of kilometers he would walk by choosing a route. As he got bored of writing out all the routes, he asks you to help him.

Input

The first line contains integer n (2 ≤ n ≤ 105). Next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 107).

Output

Output two integers — the numerator and denominator of a fraction which is equal to the wanted average number. The fraction must be irreducible.

Examples

Input

3
2 3 5


Output

22 3

Note

Consider 6 possible routes:

  * [2, 3, 5]: total distance traveled: |2 – 0| + |3 – 2| + |5 – 3| = 5; 
  * [2, 5, 3]: |2 – 0| + |5 – 2| + |3 – 5| = 7; 
  * [3, 2, 5]: |3 – 0| + |2 – 3| + |5 – 2| = 7; 
  * [3, 5, 2]: |3 – 0| + |5 – 3| + |2 – 5| = 8; 
  * [5, 2, 3]: |5 – 0| + |2 – 5| + |3 – 2| = 9; 
  * [5, 3, 2]: |5 – 0| + |3 – 5| + |2 – 3| = 8. 



The average travel distance is <image> = <image> = <image>.
import java.io.*;
import java.util.Arrays;
import java.util.StringTokenizer;

public class A {

	final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;
	BufferedReader in;
	PrintWriter out;
	StringTokenizer tok = new StringTokenizer("");

	void solve() throws IOException {
		int n = readInt();
		Long[] a = new Long[n];
		for (int i = 0; i < n; i++) {
			a[i] = readLong();
		}
		long res = 0;
		long sum = 0;
		for (int i = 0; i < n; i++) {
			sum += a[i];
		}
		res += sum;
		Arrays.sort(a);

		long[] left = new long[n];
		long[] right = new long[n];
		left[0] = a[0];
		right[n-1] = a[n-1];
		for(int i = 1; i < n-1; i++) {
			left[i] = left[i-1] +a[i];
		}
		for(int i = n-2; i >= 0; i--) {
			right[i] = right[i+1] + a[i];
		}

		for (int i = 0; i < n; i++) {
			long cur = right[i] - (n-i+1)*a[i];
			cur += a[i]*(i+1) - left[i];
			res += cur;
		}
		long gcd = gcd(res, n);
		out.println(res/gcd);
		out.println(n/gcd);
	}

	long gcd(long a, long b) {
		if(a == 0) return b;
		if(b == 0) return a;
		if(a < b) {
			return gcd(b%a, a);
		} else {
			return gcd(a%b, b);
		}
	}

	void init() throws FileNotFoundException {
		if (ONLINE_JUDGE) {
			in = new BufferedReader(new InputStreamReader(System.in));
			out = new PrintWriter(System.out);
		} else {
			in = new BufferedReader(new FileReader("input.txt"));
			out = new PrintWriter("output.txt");
		}
	}

	String readString() throws IOException {
		while (!tok.hasMoreTokens()) {
			tok = new StringTokenizer(in.readLine());
		}
		return tok.nextToken();
	}

	int readInt() throws IOException {
		return Integer.parseInt(readString());
	}

	long readLong() throws IOException {
		return Long.parseLong(readString());
	}

	double readDouble() throws IOException {
		return Double.parseDouble(readString());
	}

	int[] readArr(int n) throws IOException {
		int[] res = new int[n];
		for (int i = 0; i < n; i++) {
			res[i] = readInt();
		}
		return res;
	}

	long[] readArrL(int n) throws IOException {
		long[] res = new long[n];
		for (int i = 0; i < n; i++) {
			res[i] = readLong();
		}
		return res;
	}

	public static void main(String[] args) {
		new A().run();
	}

	public void run() {
		try {
			long t1 = System.currentTimeMillis();
			init();
			solve();
			out.close();
			long t2 = System.currentTimeMillis();
			System.err.println("Time = " + (t2 - t1));
		} catch (Exception e) {
			e.printStackTrace(System.err);
			System.exit(-1);
		}
	}
}