Snuke's town has a subway system, consisting of N stations and M railway lines. The stations are numbered 1 through N. Each line is operated by a company. Each company has an identification number.

The i-th ( 1 \leq i \leq M ) line connects station p_i and q_i bidirectionally. There is no intermediate station. This line is operated by company c_i.

You can change trains at a station where multiple lines are available.

The fare system used in this subway system is a bit strange. When a passenger only uses lines that are operated by the same company, the fare is 1 yen (the currency of Japan). Whenever a passenger changes to a line that is operated by a different company from the current line, the passenger is charged an additional fare of 1 yen. In a case where a passenger who changed from some company A's line to another company's line changes to company A's line again, the additional fare is incurred again.

Snuke is now at station 1 and wants to travel to station N by subway. Find the minimum required fare.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq M \leq 2×10^5
* 1 \leq p_i \leq N (1 \leq i \leq M)
* 1 \leq q_i \leq N (1 \leq i \leq M)
* 1 \leq c_i \leq 10^6 (1 \leq i \leq M)
* p_i \neq q_i (1 \leq i \leq M)

Input

The input is given from Standard Input in the following format:


N M
p_1 q_1 c_1
:
p_M q_M c_M


Output

Print the minimum required fare. If it is impossible to get to station N by subway, print `-1` instead.

Examples

Input

3 3
1 2 1
2 3 1
3 1 2


Output

1


Input

8 11
1 3 1
1 4 2
2 3 1
2 5 1
3 4 3
3 6 3
3 7 3
4 8 4
5 6 1
6 7 5
7 8 5


Output

2


Input

2 0


Output

-1
def main():
  from heapq import heappush,heappop,heapify
  inf=2**31-1
  n,m,*t=map(int,open(0).read().split())
  z=[]
  for a,b,c in zip(t[::3],t[1::3],t[2::3]):
    z.extend([a,b,a+n*c,b+n*c])
  z={i:v for v,i in enumerate(sorted(set(z)))}
  try:
    z[1]
  except:
    print(-1)
    exit()
  edge=[[]for _ in range(len(z))]
  d={}
  l=[]
  for a,b,c in zip(t[::3],t[1::3],t[2::3]):
    if b<a:a,b=b,a
    i,j,x,y=z[a],z[b],z[a+n*c],z[b+n*c]
    if b==n:
      l.append(y)
    edge[i].append((1,x))
    edge[j].append((1,y))
    edge[x].extend([(0,i),(0,y)])
    edge[y].extend([(0,j),(0,x)])
  used=[False]+[True]*~-len(z)
  d=[0]+[inf]*~-len(z)
  edgelist=edge[0]
  heapify(edgelist)
  while edgelist:
    m=heappop(edgelist)
    if not used[m[1]]:
      continue
    d[m[1]]=m[0]
    used[m[1]]=False
    for e in edge[m[1]]:
      if used[e[1]]:
        heappush(edgelist,(e[0]+m[0],e[1]))
  a=min([d[i]for i in l]or[inf])
  print([a,-1][a==inf])
if __name__=='__main__':
  main()