Two best friends Serozha and Gena play a game.

Initially there is one pile consisting of n stones on the table. During one move one pile should be taken and divided into an arbitrary number of piles consisting of a1 > a2 > ... > ak > 0 stones. The piles should meet the condition a1 - a2 = a2 - a3 = ... = ak - 1 - ak = 1. Naturally, the number of piles k should be no less than two.

The friends play in turns. The player who cannot make a move loses. Serozha makes the first move. Who will win if both players play in the optimal way?

Input

The single line contains a single integer n (1 ≤ n ≤ 105).

Output

If Serozha wins, print k, which represents the minimal number of piles into which he can split the initial one during the first move in order to win the game.

If Gena wins, print "-1" (without the quotes).

Examples

Input

3


Output

2


Input

6


Output

-1


Input

100


Output

8
import java.util.InputMismatchException;
import java.math.BigInteger;
import java.io.*;
import java.util.Arrays;

/**
 * Generated by Contest helper plug-in
 * Actual solution is at the bottom
 */
public class Main {
	public static void main(String[] args) {
		InputReader in = new StreamInputReader(System.in);
		PrintWriter out = new PrintWriter(System.out);
		run(in, out);
	}

	public static void run(InputReader in, PrintWriter out) {
		Solver solver = new TaskC();
		solver.solve(1, in, out);
		Exit.exit(in, out);
	}
}

abstract class InputReader {
	private boolean finished = false;

	public abstract int read();

	public int readInt() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		int res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res *= 10;
			res += c - '0';
			c = read();
		} while (!isSpaceChar(c));
		return res * sgn;
	}

	public String readString() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		StringBuffer res = new StringBuffer();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isSpaceChar(c));
		return res.toString();
	}

	private boolean isSpaceChar(int c) {
		return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
	}

	public void setFinished(boolean finished) {
		this.finished = finished;
	}

	public abstract void close();
}

class StreamInputReader extends InputReader {
	private InputStream stream;
	private byte[] buf = new byte[1024];
	private int curChar, numChars;

	public StreamInputReader(InputStream stream) {
		this.stream = stream;
	}

	public int read() {
		if (numChars == -1)
			throw new InputMismatchException();
		if (curChar >= numChars) {
			curChar = 0;
			try {
				numChars = stream.read(buf);
			} catch (IOException e) {
				throw new InputMismatchException();
			}
			if (numChars <= 0)
				return -1;
		}
		return buf[curChar++];
	}

	public void close() {
		try {
			stream.close();
		} catch (IOException ignored) {
		}
	}
}

class Exit {
	private Exit() {
	}

	public static void exit(InputReader in, PrintWriter out) {
		in.setFinished(true);
		in.close();
		out.close();
	}
}

interface Solver {
	public void solve(int testNumber, InputReader in, PrintWriter out);
}

class TaskC implements Solver {
	public void solve(int testNumber, InputReader in, PrintWriter out) {
		int n = in.readInt();
		int[] nimber = new int[n + 1];
		int[] minimum = new int[n + 1];
		Arrays.fill(minimum, -1);
		int[] value = new int[5 * n];
		for (int i = 3; i <= n; i++) {
			for (int j = 2; j * j < 2 * i; j++) {
				if (2 * i % j == 0) {
					int min = j;
					int max = 2 * i / j;
					if ((max & 1) == (min & 1))
						continue;
					int a = (min + max - 1) >> 1;
					int b = a - min;
					int current = 0;
					for (int k = b + 1; k <= a; k++)
						current ^= nimber[k];
					if (current == 0 && minimum[i] == -1)
						minimum[i] = min;
					value[current] = i;
				}
			}
			for (int j = 0; ; j++) {
				if (value[j] != i) {
					nimber[i] = j;
					break;
				}
			}
		}
		out.println(minimum[n]);
	}
}

