Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.

He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle a.

Will the robot be able to build the fence Emuskald wants? In other words, is there a regular polygon which angles are equal to a?

Input

The first line of input contains an integer t (0 < t < 180) — the number of tests. Each of the following t lines contains a single integer a (0 < a < 180) — the angle the robot can make corners at measured in degrees.

Output

For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible.

Examples

Input

3
30
60
90


Output

NO
YES
YES

Note

In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <image>.

In the second test case, the fence is a regular triangle, and in the last test case — a square.
import java.io.*;
import java.util.Scanner;

/**
 * User: Oleksiy Pylypenko
 * Date: 1/6/13
 * Time: 1:46 PM
 */
public class A {
    static boolean debug = !"true".equalsIgnoreCase(System.getProperty("ONLINE_JUDGE"));
    private Scanner in;
    private PrintWriter out;

    private void solve() throws IOException {
        int n = in.nextInt();
        for (int i = 0; i < n; i++) {
            out.println(360 % (180 - in.nextInt()) == 0 ? "YES" : "NO");
        }
    }

    public static void main(String[] args) throws IOException {
        new A().exec();
    }

    private void exec() {
        if (debug) {
            try {
                System.setIn(new FileInputStream(getClass().getName() + ".in"));
            } catch (FileNotFoundException e) {
                System.out.println(e);
                System.exit(1);
            }
        }
        in = new Scanner(new InputStreamReader(System.in));
        out = new PrintWriter(System.out, true);

        try {
            if (debug) {
                while (in.hasNext()) {
                    solve();
                }
            } else {
                solve();
            }
        } catch (IOException e) {
            if (debug) {
                System.out.println(e);
                System.exit(1);
            }
        } finally {
            out.close();
            in.close();
        }
    }

}
