There is a grass field that stretches infinitely.

In this field, there is a negligibly small cow. Let (x, y) denote the point that is x\ \mathrm{cm} south and y\ \mathrm{cm} east of the point where the cow stands now. The cow itself is standing at (0, 0).

There are also N north-south lines and M east-west lines drawn on the field. The i-th north-south line is the segment connecting the points (A_i, C_i) and (B_i, C_i), and the j-th east-west line is the segment connecting the points (D_j, E_j) and (D_j, F_j).

What is the area of the region the cow can reach when it can move around as long as it does not cross the segments (including the endpoints)? If this area is infinite, print `INF` instead.

Constraints

* All values in input are integers between -10^9 and 10^9 (inclusive).
* 1 \leq N, M \leq 1000
* A_i < B_i\ (1 \leq i \leq N)
* E_j < F_j\ (1 \leq j \leq M)
* The point (0, 0) does not lie on any of the given segments.

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1 C_1
:
A_N B_N C_N
D_1 E_1 F_1
:
D_M E_M F_M


Output

If the area of the region the cow can reach is infinite, print `INF`; otherwise, print an integer representing the area in \mathrm{cm^2}.

(Under the constraints, it can be proved that the area of the region is always an integer if it is not infinite.)

Examples

Input

5 6
1 2 0
0 1 1
0 2 2
-3 4 -1
-2 6 3
1 0 1
0 1 2
2 0 2
-1 -4 5
3 -2 4
1 2 4


Output

13


Input

6 1
-3 -1 -2
-3 -1 1
-2 -1 2
1 4 -2
1 4 -1
1 4 1
3 1 4


Output

INF
class UnionFind:
    def __init__(self, n):
        self.parent = list(range(n)) #親ノード
        self.size = [1]*n #グループの要素数
 
    def root(self, x): #root(x): xの根ノードを返す．
        while self.parent[x] != x:
            self.parent[x] = self.parent[self.parent[x]]
            x = self.parent[x]
        return x 
 
    def merge(self, x, y): #merge(x,y): xのいる組とyのいる組をまとめる
        x, y = self.root(x), self.root(y)
        if x == y: return False
        if self.size[x] < self.size[y]: x,y=y,x #xの要素数が大きいように
        self.size[x] += self.size[y] #xの要素数を更新
        self.parent[y] = x #yをxにつなぐ
        return True
 
    def issame(self, x, y): #same(x,y): xとyが同じ組ならTrue
        return self.root(x) == self.root(y)
        
    def getsize(self,x): #size(x): xのいるグループの要素数を返す
        return self.size[self.root(x)]

# coding: utf-8
# Your code here!
import sys
readline = sys.stdin.readline
read = sys.stdin.read

n,m = map(int, readline().split())
yoko = [list(map(int, readline().split())) for _ in range(n)]
tate = [list(map(int, readline().split())) for _ in range(m)]

INF = 10**9+5
xcoord = [-INF,0,INF]
ycoord = [-INF,0,INF]

for a,b,c in yoko: # (a,c) to (b,c)
    xcoord.append(a)
    xcoord.append(b)
    ycoord.append(c)
for d,e,f in tate: # (d,e) to (d,f)
    ycoord.append(e)
    ycoord.append(f)
    xcoord.append(d)

xcoord = list(sorted(set(xcoord)))
ycoord = list(sorted(set(ycoord)))

zaatu_x = {a:i for i,a in enumerate(xcoord)}
zaatu_y = {a:i for i,a in enumerate(ycoord)}

P = len(xcoord)
Q = len(ycoord)
QQ=Q-1


# (i,j) から右 or 上 に行けるか？
ok_up = [[0]*P for _ in range(Q)]
ok_ri = [[0]*Q for _ in range(P)]

for a,b,c in yoko: # (a,c) to (b,c)
    xa = zaatu_x[a]
    xb = zaatu_x[b]
    yc = zaatu_y[c]
    ok_up[yc-1][xa] += 1
    ok_up[yc-1][xb] -= 1


for d,e,f in tate: # (d,e) to (d,f)
    ye = zaatu_y[e]
    yf = zaatu_y[f]
    xd = zaatu_x[d]
    ok_ri[xd-1][ye] += 1
    ok_ri[xd-1][yf] -= 1

#print(ok_up)
#print(ok_ri)
from itertools import accumulate
for i in range(Q):
    ok_up[i] = list(accumulate(ok_up[i]))
for j in range(P):
    ok_ri[j] = list(accumulate(ok_ri[j]))

#print(*[i for i in ok_ri],sep="\n")

UF = UnionFind((P-1)*QQ)
for i in range(P-1):
    for j in range(Q-2):
        v = i*QQ+j
        if ok_up[j][i]==0: UF.merge(v,v+1)
for i in range(P-2):
    for j in range(Q-1):
        v = i*QQ+j
        if ok_ri[i][j]==0: UF.merge(v,v+QQ)
        
x0 = zaatu_x[0]
y0 = zaatu_y[0]

#print([UF.root(i) for i in range((P-1)*(Q-1))])
r = UF.root(x0*QQ+y0) 
if UF.root(0) == r:
    print("INF")
else:
    ans = sum((xcoord[i+1]-xcoord[i])*(ycoord[j+1]-ycoord[j]) for i in range(P-1) for j in range(Q-1) if UF.root(i*QQ+j) == r)
    print(ans)

#print(xcoord)
#print(ycoord)


