Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.


import java.io.*;
import java.math.*;
import java.util.*;



// @author : Dinosparton 

public class test2 {
	
	static class Pair{ 
		   String x;
		   String y;
		   
		   Pair(String x,String y){ 
			   this.x = x;
			   this.y = y;
			   
		   }
	   }
	
	static boolean check(String s)
	   {
	      if(s.length()==2)
	       return true;
	       
	      for(int i=0;i<s.length()-1;i++)
	        {
	           if(s.charAt(i)!=s.charAt(i+1))
	             return false;
	        }
	      return true;
	   }
	   public static void main(String[] args) throws Exception
	    {
		   Scanner sc = new Scanner(System.in);
		   StringBuffer ans =new StringBuffer();
		  int tc = sc.nextInt();
		  while(tc-->0) {
		   String s=sc.next();
	       
	       boolean ok = check(s);
	       if(ok)
	        ans.append(s);
	       else
	        {
	         char pivot = s.charAt(0);
	         
	         if(pivot =='0')
	           {
	              for(int i=0;i<s.length()*2;i++)
	                {
	                   if(i%2==0)
	                   ans.append("0");
	                   else
	                   ans.append("1");
	                }
	           }
	          else
	           {for(int i=0;i<s.length()*2;i++)
	                {
	                   if(i%2==1)
	                   ans.append("0");
	                   else
	                   ans.append("1");
	                }
	              
	           }
	        }
	         ans.append("\n");
	        }
		  System.out.println(ans);
	    }
}  




