Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileWriter;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.*;

public class BinaryPeriod {

	static BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
	static BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(System.out));

	static char[] s;
	
	static void process() throws Exception {
		boolean flag = false;
		for (int i = 1; i < s.length; i++) {
			if (s[i] != s[i - 1]) {
				flag = true;
				break;
			}
		}
		char[] ans = null;
		if (flag) {
			ans = new char[s.length * 2];
			int one = 0;
			if (s[0] == '0') {
				one = 1;
			}
			for (int i = 0; i < ans.length; i++) {
				if ((one ^ 1) == 1) {
					ans[i] = '1';
				} else {
					ans[i] = '0';
				}
				one ^= 1;
			}
		} else {
			ans = new char[s.length];
			for (int i = 0; i < s.length; i++) {
				ans[i] = s[i];
			}
		}
		writer.write(new String(ans));
		writer.newLine();
	}

	public static void main(String[] args) throws Exception {
		//		writer = new BufferedWriter(new FileWriter("output.txt"));
		String data[], input;
		int t = Integer.parseInt(reader.readLine());
		while (t-- != 0) {
			s = reader.readLine().toCharArray();
			process();
		}
		writer.close();
	}

}
