Let us call a pair of integer numbers m-perfect, if at least one number in the pair is greater than or equal to m. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not.

Two integers x, y are written on the blackboard. It is allowed to erase one of them and replace it with the sum of the numbers, (x + y).

What is the minimum number of such operations one has to perform in order to make the given pair of integers m-perfect?

Input

Single line of the input contains three integers x, y and m ( - 1018 ≤ x, y, m ≤ 1018).

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preffered to use the cin, cout streams or the %I64d specifier.

Output

Print the minimum number of operations or "-1" (without quotes), if it is impossible to transform the given pair to the m-perfect one.

Examples

Input

1 2 5


Output

2


Input

-1 4 15


Output

4


Input

0 -1 5


Output

-1

Note

In the first sample the following sequence of operations is suitable: (1, 2) <image> (3, 2) <image> (5, 2).

In the second sample: (-1, 4) <image> (3, 4) <image> (7, 4) <image> (11, 4) <image> (15, 4).

Finally, in the third sample x, y cannot be made positive, hence there is no proper sequence of operations.
import java.awt.*;
import java.awt.event.*;
import java.awt.geom.*;
import java.io.*;
import java.math.*;
import java.text.*; 
import java.util.*;

/*
br = new BufferedReader(new FileReader("input.txt"));
pw = new PrintWriter(new BufferedWriter(new FileWriter("output.txt")));
br = new BufferedReader(new InputStreamReader(System.in));
pw = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
 */

public class Main {
  private static BufferedReader br;
  private static StringTokenizer st;
  private static PrintWriter pw;

  public static void main(String[] args) throws IOException {
    br = new BufferedReader(new InputStreamReader(System.in));
    pw = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
    //int qq = 1;
    int qq = Integer.MAX_VALUE;
    //int qq = readInt();
    for(int casenum = 1; casenum <= qq; casenum++)  {
      long x = readLong();
      long y = readLong();
      long m = readLong();
      if(x>=m || y>=m) {
        pw.println(0);
      }
      else {
        if(x <= 0 && y <= 0) {
          pw.println(-1);
        }
        else {
          long ret = 0;
          if(y < 0) {
            long t = x;
            x = y;
            y = t;
          }
          if(x < 0) {
            ret = (Math.abs(x)+y-1)/y;
            x += ret * y;
          }
          while(x < m && y < m) {
            long s = x+y;
            if(x < y) {
              ret++;
              x=s;
            }
            else {
              ret++;
              y=s;
            }
          }
          pw.println(ret);
        }
      }
    }
    pw.close();
  }

  private static void exitImmediately() {
    pw.close();
    System.exit(0);
  }

  private static long readLong() throws IOException {
    return Long.parseLong(nextToken());
  }

  private static double readDouble() throws IOException {
    return Double.parseDouble(nextToken());
  }

  private static int readInt() throws IOException {
    return Integer.parseInt(nextToken());
  }

  private static String nextToken() throws IOException  {
    while(st == null || !st.hasMoreTokens())  {
      if(!br.ready()) {
        exitImmediately();
      }
      st = new StringTokenizer(br.readLine().trim());
    }
    return st.nextToken();
  }
}


