N hotels are located on a straight line. The coordinate of the i-th hotel (1 \leq i \leq N) is x_i.

Tak the traveler has the following two personal principles:

* He never travels a distance of more than L in a single day.
* He never sleeps in the open. That is, he must stay at a hotel at the end of a day.



You are given Q queries. The j-th (1 \leq j \leq Q) query is described by two distinct integers a_j and b_j. For each query, find the minimum number of days that Tak needs to travel from the a_j-th hotel to the b_j-th hotel following his principles. It is guaranteed that he can always travel from the a_j-th hotel to the b_j-th hotel, in any given input.

Constraints

* 2 \leq N \leq 10^5
* 1 \leq L \leq 10^9
* 1 \leq Q \leq 10^5
* 1 \leq x_i < x_2 < ... < x_N \leq 10^9
* x_{i+1} - x_i \leq L
* 1 \leq a_j,b_j \leq N
* a_j \neq b_j
* N,\,L,\,Q,\,x_i,\,a_j,\,b_j are integers.

Input

The input is given from Standard Input in the following format:


N
x_1 x_2 ... x_N
L
Q
a_1 b_1
a_2 b_2
:
a_Q b_Q


Output

Print Q lines. The j-th line (1 \leq j \leq Q) should contain the minimum number of days that Tak needs to travel from the a_j-th hotel to the b_j-th hotel.

Example

Input

9
1 3 6 13 15 18 19 29 31
10
4
1 8
7 3
6 7
8 5


Output

4
2
1
2
import sys
from bisect import bisect

n = int(input())
xxx = list(map(int, input().split()))
l = int(input())

reachable = [[bisect(xxx, x + l) - 1 for x in xxx]]
while reachable[-1][0] < n - 1:
    rp = reachable[-1]
    reachable.append(list(map(rp.__getitem__, rp)))

q = int(input())
buf = []
for line in sys.stdin:
    a, b = map(int, line.split())
    a -= 1
    b -= 1
    if a > b:
        a, b = b, a
    ans = 0
    for i in range(len(reachable) - 1, -1, -1):
        ria = reachable[i][a]
        if ria >= b:
            continue
        ans += 1 << i
        a = ria
    if a != b:
        ans += 1
    buf.append(ans)

print('\n'.join(map(str, buf)))
