Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.

Help Kefa cope with this task!

Input

The first line contains integer n (1 ≤ n ≤ 105).

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109).

Output

Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.

Examples

Input

6
2 2 1 3 4 1


Output

3

Input

3
2 2 9


Output

3

Note

In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.

In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.
import sys
from random import choice,randint
 
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
 
def MI(): return map(int, sys.stdin.readline().strip().split())
def LI(): return list(map(int, sys.stdin.readline().strip().split()))
def LLI(): return [list(map(int, l.split())) for l in sys.stdin.readlines().strip()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().strip().split()]
def LF(): return [float(x) for x in sys.stdin.readline().strip().split()]
def LS(): return sys.stdin.readline().strip().split()
def I(): return int(sys.stdin.readline().strip())
def F(): return float(sys.stdin.readline().strip())
def S(): return sys.stdin.readline().strip()
def pf(s): return print(s, flush=True)
def pe(s): return print(str(s), file=sys.stderr)
def JA(a, sep): return sep.join(map(str, a))
def JAA(a, s, t): return s.join(t.join(map(str, b)) for b in a)

inp=sys.stdin.readline
out=sys.stdout.write

def main():
    n = I()
    a = LI()
    mx,i=0,0
    while i<n:
        j=i
        c=1
        f=1
        while j<n-1 and (a[j]<=a[j+1]):
            f=0
            c+=1
            j+=1
        if c>mx:
            mx=c
        if f==1:
            i+=1
        else:
            i=j+1
    pf(mx)

if __name__ == "__main__":
    main()