Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.

Help Kefa cope with this task!

Input

The first line contains integer n (1 ≤ n ≤ 105).

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109).

Output

Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.

Examples

Input

6
2 2 1 3 4 1


Output

3

Input

3
2 2 9


Output

3

Note

In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.

In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.

def lenOfLongIncSubArr(arr, n) :
 
    # 'max' to store the length of longest
    # increasing subarray
    # 'len' to store the lengths of longest
    # increasing subarray at diiferent 
    # instants of time
    m = 1
    l = 1
      
    # traverse the array from the 2nd element
    for i in range(1, n) :
 
        # if current element if greater than previous
        # element, then this element helps in building
        # up the previous increasing subarray encountered
        # so far
        if (arr[i] >= arr[i-1]) :
            l =l + 1
        else :
 
            # check if 'max' length is less than the length
            # of the current increasing subarray. If true, 
            # then update 'max'
            if (m < l)  :
                m = l 
 
            # reset 'len' to 1 as from this element
            # again the length of the new increasing
            # subarray is being calculated    
            l = 1
         
         
    # comparing the length of the last
    # increasing subarray with 'max'
    if (m < l) :
        m = l
      
    # required maximum length
    return m
n=int(input())
arr=list(map(int,input().split()))
print(lenOfLongIncSubArr(arr,n))