Recently Lynyrd and Skynyrd went to a shop where Lynyrd bought a permutation p of length n, and Skynyrd bought an array a of length m, consisting of integers from 1 to n. 

Lynyrd and Skynyrd became bored, so they asked you q queries, each of which has the following form: "does the subsegment of a from the l-th to the r-th positions, inclusive, have a subsequence that is a cyclic shift of p?" Please answer the queries.

A permutation of length n is a sequence of n integers such that each integer from 1 to n appears exactly once in it.

A cyclic shift of a permutation (p_1, p_2, …, p_n) is a permutation (p_i, p_{i + 1}, …, p_{n}, p_1, p_2, …, p_{i - 1}) for some i from 1 to n. For example, a permutation (2, 1, 3) has three distinct cyclic shifts: (2, 1, 3), (1, 3, 2), (3, 2, 1).

A subsequence of a subsegment of array a from the l-th to the r-th positions, inclusive, is a sequence a_{i_1}, a_{i_2}, …, a_{i_k} for some i_1, i_2, …, i_k such that l ≤ i_1 < i_2 < … < i_k ≤ r.

Input

The first line contains three integers n, m, q (1 ≤ n, m, q ≤ 2 ⋅ 10^5) — the length of the permutation p, the length of the array a and the number of queries.

The next line contains n integers from 1 to n, where the i-th of them is the i-th element of the permutation. Each integer from 1 to n appears exactly once.

The next line contains m integers from 1 to n, the i-th of them is the i-th element of the array a.

The next q lines describe queries. The i-th of these lines contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ m), meaning that the i-th query is about the subsegment of the array from the l_i-th to the r_i-th positions, inclusive.

Output

Print a single string of length q, consisting of 0 and 1, the digit on the i-th positions should be 1, if the subsegment of array a from the l_i-th to the r_i-th positions, inclusive, contains a subsequence that is a cyclic shift of p, and 0 otherwise.

Examples

Input

3 6 3
2 1 3
1 2 3 1 2 3
1 5
2 6
3 5


Output

110


Input

2 4 3
2 1
1 1 2 2
1 2
2 3
3 4


Output

010

Note

In the first example the segment from the 1-st to the 5-th positions is 1, 2, 3, 1, 2. There is a subsequence 1, 3, 2 that is a cyclic shift of the permutation. The subsegment from the 2-nd to the 6-th positions also contains a subsequence 2, 1, 3 that is equal to the permutation. The subsegment from the 3-rd to the 5-th positions is 3, 1, 2, there is only one subsequence of length 3 (3, 1, 2), but it is not a cyclic shift of the permutation.

In the second example the possible cyclic shifts are 1, 2 and 2, 1. The subsegment from the 1-st to the 2-nd positions is 1, 1, its subsequences are not cyclic shifts of the permutation. The subsegment from the 2-nd to the 3-rd positions is 1, 2, it coincides with the permutation. The subsegment from the 3 to the 4 positions is 2, 2, its subsequences are not cyclic shifts of the permutation.
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.util.Arrays;
import java.util.function.LongBinaryOperator;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.io.UncheckedIOException;
import java.util.List;
import java.nio.charset.Charset;
import java.util.StringTokenizer;
import java.io.Writer;
import java.io.OutputStreamWriter;
import java.io.BufferedReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author mikit
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        LightScanner in = new LightScanner(inputStream);
        LightWriter out = new LightWriter(outputStream);
        BLynyrdSkynyrd solver = new BLynyrdSkynyrd();
        solver.solve(1, in, out);
        out.close();
    }

    static class BLynyrdSkynyrd {
        public void solve(int testNumber, LightScanner in, LightWriter out) {
            // out.setBoolLabel(LightWriter.BoolLabel.YES_NO_FIRST_UP);
            int n = in.ints(), m = in.ints(), q = in.ints();
            int[] p = new int[n], pr = new int[n], a = new int[m];
            for (int i = 0; i < n; i++) {
                p[i] = in.ints() - 1;
                pr[p[i]] = i;
            }
            for (int i = 0; i < m; i++) a[i] = in.ints() - 1;

            List<List<Integer>> loop = new ArrayList<>();
            for (int i = 0; i < n; i++) loop.add(new ArrayList<>());
            for (int i = 0; i < m; i++) {
                loop.get(a[i]).add(i);
            }

            int[][] next = new int[20][m];
            for (int i = 0; i < m; i++) {
                int v = p[(pr[a[i]] + 1) % n];
                List<Integer> indices = loop.get(v);
                if (indices.isEmpty()) {
                    next[0][i] = -1;
                    continue;
                }
                int min = 0, max = indices.size();
                while (max - min > 0) {
                    int mid = (min + max) / 2;
                    if (indices.get(mid) <= i) {
                        min = mid + 1;
                    } else {
                        max = mid;
                    }
                }

                if (min == indices.size()) {
                    next[0][i] = -1;
                } else {
                    next[0][i] = indices.get(min);
                }
            }

            for (int i = 1; i < 20; i++) {
                for (int j = 0; j < m; j++) {
                    if (next[i - 1][j] == -1) {
                        next[i][j] = -1;
                    } else {
                        next[i][j] = next[i - 1][next[i - 1][j]];
                    }
                }
            }

            long[] nlate = new long[m];
            outer:
            for (int i = 0; i < m; i++) {
                int cur = i;
                for (int j = 19; j >= 0; j--) {
                    if (((n - 1) & (1 << j)) == 0) {
                        continue;
                    }
                    cur = next[j][cur];
                    if (cur == -1) {
                        nlate[i] = Long.MAX_VALUE;
                        continue outer;
                    }
                }
                nlate[i] = cur;
            }

            IntSegmentTree st = new IntSegmentTree(nlate, Math::min, Long.MAX_VALUE, (x, u) -> 0);
            for (int i = 0; i < q; i++) {
                int l = in.ints() - 1, r = in.ints();
                if (st.query(l, r) < r) {
                    out.print('1');
                } else {
                    out.print('0');
                }
            }
            out.ln();
            //System.out.println(Arrays.toString(nlate));
        }

    }

    static class LightWriter implements AutoCloseable {
        private final Writer out;
        private boolean autoflush = false;
        private boolean breaked = true;

        public LightWriter(Writer out) {
            this.out = out;
        }

        public LightWriter(OutputStream out) {
            this(new BufferedWriter(new OutputStreamWriter(out, Charset.defaultCharset())));
        }

        public LightWriter print(char c) {
            try {
                out.write(c);
                breaked = false;
            } catch (IOException ex) {
                throw new UncheckedIOException(ex);
            }
            return this;
        }

        public LightWriter print(String s) {
            try {
                out.write(s, 0, s.length());
                breaked = false;
            } catch (IOException ex) {
                throw new UncheckedIOException(ex);
            }
            return this;
        }

        public LightWriter ln() {
            print(System.lineSeparator());
            breaked = true;
            if (autoflush) {
                try {
                    out.flush();
                } catch (IOException ex) {
                    throw new UncheckedIOException(ex);
                }
            }
            return this;
        }

        public void close() {
            try {
                out.close();
            } catch (IOException ex) {
                throw new UncheckedIOException(ex);
            }
        }

    }

    static class LightScanner {
        private BufferedReader reader = null;
        private StringTokenizer tokenizer = null;

        public LightScanner(InputStream in) {
            reader = new BufferedReader(new InputStreamReader(in));
        }

        public String string() {
            if (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new UncheckedIOException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int ints() {
            return Integer.parseInt(string());
        }

    }

    static final class BitMath {
        private BitMath() {
        }

        public static int extractMsb(int v) {
            v = (v & 0xFFFF0000) > 0 ? v & 0xFFFF0000 : v;
            v = (v & 0xFF00FF00) > 0 ? v & 0xFF00FF00 : v;
            v = (v & 0xF0F0F0F0) > 0 ? v & 0xF0F0F0F0 : v;
            v = (v & 0xCCCCCCCC) > 0 ? v & 0xCCCCCCCC : v;
            v = (v & 0xAAAAAAAA) > 0 ? v & 0xAAAAAAAA : v;
            return v;
        }

    }

    static class IntSegmentTree {
        private final int n;
        private final int m;
        private final long[] tree;
        private final LongBinaryOperator op;
        private final LongBinaryOperator up;
        private final long zero;

        public IntSegmentTree(long[] array, LongBinaryOperator op, long zero, LongBinaryOperator up) {
            this.n = array.length;
            int msb = BitMath.extractMsb(n);
            this.m = n == msb ? msb : (msb << 1);
            this.tree = new long[m * 2 - 1];
            this.op = op;
            this.up = up;
            this.zero = zero;
            Arrays.fill(tree, zero);
            System.arraycopy(array, 0, this.tree, m - 1, array.length);
            for (int i = m - 2; i >= 0; i--) {
                tree[i] = op.applyAsLong(tree[2 * i + 1], tree[2 * i + 2]);
            }
        }

        public long query(int l, int r) {
            long left = zero, right = zero;
            l += m - 1;
            r += m - 1;
            while (l < r) {
                if ((l & 1) == 0) {
                    left = op.applyAsLong(left, tree[l]);
                }
                if ((r & 1) == 0) {
                    right = op.applyAsLong(tree[r - 1], right);
                }
                l = l / 2;
                r = (r - 1) / 2;
            }
            return op.applyAsLong(left, right);
        }

    }
}

