Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.

You are given string t consisting only of 0's and 1's and you need to find such string s that:

  1. String s consists only of 0's and 1's; 
  2. The length of s doesn't exceed 2 ⋅ |t|; 
  3. String t is a subsequence of string s; 
  4. String s has smallest possible period among all strings that meet conditions 1—3. 



Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".

Input

The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

Input


4
00
01
111
110


Output


00
01
11111
1010

Note

In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
//created by Whiplash99
import java.io.*;
import java.util.*;
public class B
{
    public static void main(String[] args) throws IOException
    {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

        int i,N;

        int T=Integer.parseInt(br.readLine().trim());
        StringBuilder sb=new StringBuilder();

        while(T-->0)
        {
            char[] t=br.readLine().trim().toCharArray();
            N=t.length;

            char[] s=new char[2*N];
            Arrays.fill(s,'0');

            for(i=0;i<N;i++) if(t[i]!='0') break;
            if(i==N)
            {
                sb.append(s).append("\n");
                continue;
            }
            for(i=0;i<N;i++) if(t[i]!='1') break;
            if(i==N)
            {
                Arrays.fill(s,'1');
                sb.append(s).append("\n");
                continue;
            }

            if(t[0]=='1')
            {
                for(i=0;i<2*N;i+=2) s[i]='1';
            }
            else
            {
                for(i=1;i<2*N;i+=2)
                {
                    s[i] = '1';
                }
            }

            sb.append(s).append("\n");
        }
        System.out.println(sb);
    }
}