Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.

Help Kefa cope with this task!

Input

The first line contains integer n (1 ≤ n ≤ 105).

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109).

Output

Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.

Examples

Input

6
2 2 1 3 4 1


Output

3

Input

3
2 2 9


Output

3

Note

In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.

In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class A {

	static BufferedReader br = new BufferedReader(new InputStreamReader(
			System.in));
	static StringTokenizer st;
	static PrintWriter out;

	public static String next() throws IOException {
		while (st == null || !st.hasMoreTokens()) {
			st = new StringTokenizer(br.readLine());
		}
		return st.nextToken();
	}

	public static int nextInt() throws IOException {
		return Integer.parseInt(next());
	}

	public static long nextLong() throws IOException {
		return Long.parseLong(next());
	}

	public static float nextFloat() throws IOException {
		return Float.parseFloat(next());
	}

	public static double nextDouble() throws IOException {
		return Double.parseDouble(next());
	}

	public static void main(String[] args) throws IOException {

		int res = 0;

		int x = nextInt();

		int[] t = new int[x];

		int m = 1;

		for (int i = 0; i < x; i++) {
			t[i] = nextInt();
			if (i != 0) {
				if (t[i] >= t[i - 1]) {
					m++;
				} else {
					if (m > res)
						res = m;
					m = 1;
				}
			}
		}

		if (m > res)
			res = m;

		// output
		System.out.println(res);

	}

	static double log2(int a) {
		return Math.log(a) / Math.log(2);
	}
}
