Yaroslav has an array that consists of n integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.

Help Yaroslav.

Input

The first line contains integer n (1 ≤ n ≤ 100) — the number of elements in the array. The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 1000) — the array elements.

Output

In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise.

Examples

Input

1
1


Output

YES


Input

3
1 1 2


Output

YES


Input

4
7 7 7 7


Output

NO

Note

In the first sample the initial array fits well.

In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.

In the third sample Yarosav can't get the array he needs.


import java.io.BufferedInputStream;
import java.util.*;

import static java.lang.Math.*;

public class C296A {
	
	boolean allowedDebug = true;

	public void solve() throws Exception {
		int n = ni();
		int[] c = new int[1001];
		for (int i = 0; i < n; i++) {
			c[ni()]++;
		}
		if (n == 1) {
			println("YES");
			return;
		}
		for (int i = 0; i < c.length; i++) {
			if (c[i] > (n + 1) / 2) {
				println("NO");
				return;
			}
		}
		println("YES");
		return;
	}

	// ------------------------------------------------------

	void debug(Object... o) {
		if (allowedDebug) {
			System.err.println(Arrays.deepToString(o));
		}
	}

	void print(Object... os) {
		if (os != null && os.length > 0)
			System.out.print(os[0].toString());
		for (int i = 1; i < os.length; ++i)
			System.out.print(" " + os[i].toString());
	}

	void println(Object... os) {
		print(os);
		System.out.println();
	}

	BufferedInputStream bis = new BufferedInputStream(System.in);

	String nextWord() throws Exception {
		char c = (char) bis.read();
		while (c <= ' ')
			c = (char) bis.read();
		StringBuilder sb = new StringBuilder();
		while (c > ' ') {
			sb.append(c);
			c = (char) bis.read();
		}
		return new String(sb);
	}

	String nextLine() throws Exception {
		char c = (char) bis.read();
		while (c <= ' ')
			c = (char) bis.read();
		StringBuilder sb = new StringBuilder();
		while (c != '\n' && c != '\r') {
			sb.append(c);
			c = (char) bis.read();
		}
		return new String(sb);
	}

	int ni() throws Exception {
		return Integer.parseInt(nextWord());
	}

	long nl() throws Exception {
		return Long.parseLong(nextWord());
	}
	
	public static void main(String[] args) throws Exception {
		new C296A().solve();
	}
}
