Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <bitset>
using namespace std;

#define MOD 1000000007

int N, X, Y, Z;
int dp[41][1<<18];

int main() {
  cin >> N >> X >> Y >> Z;

  const int MASK = (1<<(X+Y+Z)) - 1;
  const int NG = (1<<(Z-1)) | (1<<(Y+Z-1)) | (1<<(X+Y+Z-1));

  for (int k=1; k<=10; k++) dp[0][(1<<(k-1)) & MASK] += 1;
  for (int i=1; i<N; i++) {
    for (int b=0; b<=MASK; b++) {
      if (dp[i-1][b] == 0) continue;
      for (int k=1; k<=10; k++) {
        int nb = ((b<<k) | (1<<(k-1))) & MASK;
        if ((nb & NG) == NG) continue;
        dp[i][nb] = (dp[i][nb] + dp[i-1][b]) % MOD;
      }
    }
  }
  int p = 1;
  for (int i=0; i<N; i++) {
    p = (10LL*p) % MOD;
  }
  int s = 0;
  for (int b=0; b<=MASK; b++) {
    s += dp[N-1][b];
    s %= MOD;
  }
  s = MOD - s;
  cout << (p + s) % MOD << "\n";
  return 0;
}
