Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.
u, v = [int(x) for x in raw_input().split()]
diff = v - u
if diff < 0 or diff % 2 == 1:
    print -1
else:
    if v == 0:
        print 0
    elif diff == 0:
        print 1
        print u
    else:
        l = diff / 2
        sol = None
        if u & l != 0:
	    sol = [u, l, l]
        else:
            sol = [u + l, l]
     
        sol = [str(x) for x in sol if x != 0]
        print len(sol)
        print " ".join(sol)
