The Cartesian coordinate system is set in the sky. There you can see n stars, the i-th has coordinates (xi, yi), a maximum brightness c, equal for all stars, and an initial brightness si (0 ≤ si ≤ c).

Over time the stars twinkle. At moment 0 the i-th star has brightness si. Let at moment t some star has brightness x. Then at moment (t + 1) this star will have brightness x + 1, if x + 1 ≤ c, and 0, otherwise.

You want to look at the sky q times. In the i-th time you will look at the moment ti and you will see a rectangle with sides parallel to the coordinate axes, the lower left corner has coordinates (x1i, y1i) and the upper right — (x2i, y2i). For each view, you want to know the total brightness of the stars lying in the viewed rectangle.

A star lies in a rectangle if it lies on its border or lies strictly inside it.

Input

The first line contains three integers n, q, c (1 ≤ n, q ≤ 105, 1 ≤ c ≤ 10) — the number of the stars, the number of the views and the maximum brightness of the stars.

The next n lines contain the stars description. The i-th from these lines contains three integers xi, yi, si (1 ≤ xi, yi ≤ 100, 0 ≤ si ≤ c ≤ 10) — the coordinates of i-th star and its initial brightness.

The next q lines contain the views description. The i-th from these lines contains five integers ti, x1i, y1i, x2i, y2i (0 ≤ ti ≤ 109, 1 ≤ x1i < x2i ≤ 100, 1 ≤ y1i < y2i ≤ 100) — the moment of the i-th view and the coordinates of the viewed rectangle.

Output

For each view print the total brightness of the viewed stars.

Examples

Input

2 3 3
1 1 1
3 2 0
2 1 1 2 2
0 2 1 4 5
5 1 1 5 5


Output

3
0
3


Input

3 4 5
1 1 2
2 3 0
3 3 1
0 1 1 100 100
1 2 2 4 4
2 2 1 4 7
1 50 50 51 51


Output

3
3
5
0

Note

Let's consider the first example.

At the first view, you can see only the first star. At moment 2 its brightness is 3, so the answer is 3.

At the second view, you can see only the second star. At moment 0 its brightness is 0, so the answer is 0.

At the third view, you can see both stars. At moment 5 brightness of the first is 2, and brightness of the second is 1, so the answer is 3.

import java.util.Scanner;

public class Starsky 
{
	static Scanner sc = new Scanner(System.in);
	static int n, views, maxbr;
//	static int[] x, y, b;
	static int[][][] cache;
	static int[][][] sky;
	
	static void printout()
	{
		for(int y = 0; y <= 100; y++)
		{
			for(int x = 0; x <= 100; x++)
			{
				int d = 0;
				for(int i = 0; i <= maxbr; i++)
				{
					d += cache[i][x][y];
				}
				System.out.print(d + " ");
			}
			System.out.print("\n");
		}
	}
	
	static int getpart(int t, int x1, int y1, int x2, int y2)
	{
		int ans = getfull(t, x2, y2) - getfull(t, x1-1, y2) - getfull(t, x2, y1-1) + getfull(t, x1-1, y1-1);
		
		return ans;
	}
	
	static int getfull(int t, int x, int y)
	{
		int bag = 0;
		
		if(x < 0 || y < 0)return 0;
		
		for(int i = 0; i <= maxbr; i++)
		{
			int cur = cache[i][x][y];
			int worth = (t + i)%(maxbr+1);
			bag += cur * worth;
		}
		
		return bag;
	}
	
	public static void main(String[] args) 
	{
		n = sc.nextInt();
		views = sc.nextInt();
		maxbr = sc.nextInt();
//		x = new int[n];
//		y = new int[n];
//		b = new int[n];
		cache = new int[maxbr+1][101][101];
		sky = new int[maxbr+1][101][101];

		for(int i = 0; i < n; i++)
		{
//			x[i] = sc.nextInt();
//			y[i] = sc.nextInt();
//			b[i] = sc.nextInt();
			int x = sc.nextInt();
			int y = sc.nextInt();
			int b = sc.nextInt();
			
			sky[b][x][y] += 1;
		}
		
		for(int b = 0; b <= maxbr; b++)
		{
			for(int y = 0; y <= 100; y++)
			{
				for(int x = 0; x <= 100; x++)
				{
					cache[b][x][y] = sky[b][x][y];
					if(x > 0)
					{
						cache[b][x][y] += cache[b][x-1][y];
					}
					if(y > 0)
					{
						cache[b][x][y] += cache[b][x][y-1];
					}
					if(x > 0 && y > 0)
					{
//						System.out.println(cache[b][x][y] + " - " + cache[b][x-1][y-1]);
						cache[b][x][y] -= cache[b][x-1][y-1];
					}
				}
			}
		}
		
//		printout();
		
		int ans = 0;
//		System.out.println("input views");
		for(int i = 0; i < views; i++)
		{
			int t = sc.nextInt();
			int x1 = sc.nextInt();
			int y1 = sc.nextInt();
			int x2 = sc.nextInt();
			int y2 = sc.nextInt();
			ans = getpart(t,x1,y1,x2,y2);
			System.out.println(ans);
		}
		
	}

}
