Yaroslav has an array that consists of n integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.

Help Yaroslav.

Input

The first line contains integer n (1 ≤ n ≤ 100) — the number of elements in the array. The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 1000) — the array elements.

Output

In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise.

Examples

Input

1
1


Output

YES


Input

3
1 1 2


Output

YES


Input

4
7 7 7 7


Output

NO

Note

In the first sample the initial array fits well.

In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.

In the third sample Yarosav can't get the array he needs.
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Yaroslav {

    public static void main(String[] args) {
        Kattio io = new Kattio(System.in,System.out);
        int n=io.getInt();
        int[] a = new int[1001];
        int max=0;
        for(int i=0;i<n;i++){
            int map=io.getInt();
            a[map]++;
            max=Math.max(max, a[map]);
        }
        
    
        
        //io.println(Arrays.toString(a));
        io.println(max<=(n+1)/2?"YES":"NO");
        io.close();
    }

static class Kattio extends PrintWriter {

    public Kattio(InputStream i) {
    super(new BufferedOutputStream(System.out));
    r = new BufferedReader(new InputStreamReader(i));
    }
    public Kattio(InputStream i, OutputStream o) {
    super(new BufferedOutputStream(o));
    r = new BufferedReader(new InputStreamReader(i));
    }

    public boolean hasMoreTokens() {
    return peekToken() != null;
    }

    public int getInt() {
    return Integer.parseInt(nextToken());
    }

    public double getDouble() { 
    return Double.parseDouble(nextToken());
    }

    public long getLong() {
    return Long.parseLong(nextToken());
    }

    public String getWord() {
    return nextToken();
    }



    private BufferedReader r;
    private String line;
    private StringTokenizer st;
    private String token;

    private String peekToken() {
    if (token == null) 
        try {
        while (st == null || !st.hasMoreTokens()) {
            line = r.readLine();
            if (line == null) return null;
            st = new StringTokenizer(line);
        }
        token = st.nextToken();
        } catch (IOException e) { }
    return token;
    }

    private String nextToken() {
    String ans = peekToken();
    token = null;
    return ans;
    }
}
}
