Let us denote by f(x, m) the remainder of the Euclidean division of x by m.

Let A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M). Find \displaystyle{\sum_{i=1}^N A_i}.

Constraints

* 1 \leq N \leq 10^{10}
* 0 \leq X < M \leq 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N X M


Output

Print \displaystyle{\sum_{i=1}^N A_i}.

Examples

Input

6 2 1001


Output

1369


Input

1000 2 16


Output

6


Input

10000000000 10 99959


Output

492443256176507
n,x,m=map(int, input().split())
alist=[]
blist=[0]*m
num=x%m
while blist[num]==0:
  alist.append(num)
  blist[num]=1
  num=(num**2)%m
num1=alist.index(num)
num2=len(alist)
if x==1:
  print(n)
elif n<=num1:
  print(sum(alist[0:n]))
else:
  cycle=(n-num1)//(num2-num1)
  print(sum(alist[0:num1])+cycle*sum(alist[num1:num2+1])+sum(alist[num1:n-cycle*(num2-num1)]))