Let n be an integer. Consider all permutations on integers 1 to n in lexicographic order, and concatenate them into one big sequence p. For example, if n = 3, then p = [1, 2, 3, 1, 3, 2, 2, 1, 3, 2, 3, 1, 3, 1, 2, 3, 2, 1]. The length of this sequence will be n ⋅ n!.

Let 1 ≤ i ≤ j ≤ n ⋅ n! be a pair of indices. We call the sequence (p_i, p_{i+1}, ..., p_{j-1}, p_j) a subarray of p. Its length is defined as the number of its elements, i.e., j - i + 1. Its sum is the sum of all its elements, i.e., ∑_{k=i}^j p_k. 

You are given n. Find the number of subarrays of p of length n having sum (n(n+1))/(2). Since this number may be large, output it modulo 998244353 (a prime number). 

Input

The only line contains one integer n (1 ≤ n ≤ 10^6), as described in the problem statement.

Output

Output a single integer — the number of subarrays of length n having sum (n(n+1))/(2), modulo 998244353.

Examples

Input


3


Output


9


Input


4


Output


56


Input


10


Output


30052700

Note

In the first sample, there are 16 subarrays of length 3. In order of appearance, they are:

[1, 2, 3], [2, 3, 1], [3, 1, 3], [1, 3, 2], [3, 2, 2], [2, 2, 1], [2, 1, 3], [1, 3, 2], [3, 2, 3], [2, 3, 1], [3, 1, 3], [1, 3, 1], [3, 1, 2], [1, 2, 3], [2, 3, 2], [3, 2, 1]. 

Their sums are 6, 6, 7, 6, 7, 5, 6, 6, 8, 6, 7, 5, 6, 6, 7, 6. As (n(n+1))/(2) = 6, the answer is 9.
import java.io.*;
import java.util.*;


public class D {
    static BufferedReader inp = new BufferedReader(new InputStreamReader(System.in));
    static BufferedWriter out = new BufferedWriter(new OutputStreamWriter(System.out));

    public static void main(String[] args) throws IOException {


        int a = Integer.parseInt(inp.readLine());
        long mod = 998244353;

        int size = (int) 1e6;
        int[] dp = new int[size];
        dp[0] = 1;

        if(a<3){
            if(a==1){
                out.write(1+"\n");
            }
            else{
                out.write(2+"\n");
            }
        }
        else{

            long ans = 9;
            long one = 3;
            long amount = 6;

            while (one!=a){
                ans = (one+1)*((amount-1)+ans);
                ans%=mod;
                one++;
                amount= one*amount;
                amount%=mod;
            }
            out.write(ans+"\n");


        }



        out.flush();



    }

    public static ArrayList<Integer> decToBinary(long n)
    {
        ArrayList<Integer> list = new ArrayList<>();
        for (int i = 63; i >= 0; i--) {
            long k = n >> i;
            if ((k & 1L) > 0)
                list.add(1);
            else
                list.add(0);
        }
        return list;
    }
    static void print(int[] array){
        for(int j=0;j<array.length;j++){
            System.out.print(array[j]+" ");
        }
        System.out.println();
    }
    static void print(int[][] array){
        for(int i=0;i< array.length;i++) {
            for (int j = 0; j < array[0].length; j++) {
                System.out.print(array[i][j] + " ");
            }
            System.out.println();
        }
    }
    static void print(boolean[] array){
        for(int j=0;j<array.length;j++){
            System.out.print(array[j]+" ");
        }
        System.out.println();
    }
    static void print(boolean[][] array){
        for(int i=0;i< array.length;i++) {
            for (int j = 0; j < array[0].length; j++) {
                System.out.print(array[i][j] + " ");
            }
            System.out.println();
        }
    }
    static void print(long[] array){
        for(int j=0;j<array.length;j++){
            System.out.print(array[j]+" ");
        }
        System.out.println();
    }
    static void print(long[][] array){
        for(int i=0;i< array.length;i++) {
            for (int j = 0; j < array[0].length; j++) {
                System.out.print(array[i][j] + " ");
            }
            System.out.println();
        }
    }
    static void print(String[] array){
        for(int j=0;j<array.length;j++){
            System.out.print(array[j]+" ");
        }
        System.out.println();
    }
    static void print(String[][] array){
        for(int i=0;i< array.length;i++) {
            for (int j = 0; j < array[0].length; j++) {
                System.out.print(array[i][j] + " ");
            }
            System.out.println();
        }
    }
    static long calc(int a,int b){
        long c = b-a+1;
        c = c*(c+1);
        c/=2l;
        return c;
    }
}