Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.
u,v=[int(i) for i in input().split()]
if(u==0 and v==0):print("0")
elif(u>v or (v-u)%2==1):
    print("-1")
elif(u==v):
    print("1")
    print(u)
else:
    a=u+(v-u)//2
    if(a^(v-a)==u):
        print("2")
        print(str(a)+" "+str(v-a))
    else:
        print("3")
        a=str((v-u)//2)
        print(str(u)+" "+a+" "+a)
    
