Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include<bits/stdc++.h>
#define qwq 1000000007
using namespace std;
long long a,i,j,k,n,m,v,x,y,z,ans,f[41][131072];
int main()
{
    ios::sync_with_stdio(false);
    cin>>n>>x>>y>>z; ans=1; f[0][0]=1;
    for (i=0;i<n;i++) (ans*=10)%=qwq;
    y+=z; x+=y; v=(1<<x-1)|(1<<y-1)|(1<<z-1); m=1<<x;
    for (i=1;i<=n;i++)
    for (j=0;j<m;j++)
    {
        if (!f[i-1][j]) continue;
        for (k=1;k<11;k++)
        {
            a=((j<<k)|(1<<k-1))&(m-1);
            if ((a&v)!=v) (f[i][a]+=f[i-1][j])%=qwq;
        }
    }
    for (i=0;i<m;i++) ans=(ans-f[n][i]+qwq)%qwq; cout<<ans;
    return 0;
}