For a finite set of integers X, let f(X)=\max X - \min X.

Given are N integers A_1,...,A_N.

We will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.

Since the answer can be enormous, print it \bmod (10^9+7).

Constraints

* 1 \leq N \leq 10^5
* 1 \leq K \leq N
* |A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:


N K
A_1 ... A_N


Output

Print the answer \bmod (10^9+7).

Examples

Input

4 2
1 1 3 4


Output

11


Input

6 3
10 10 10 -10 -10 -10


Output

360


Input

3 1
1 1 1


Output

0


Input

10 6
1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0


Output

999998537
MOD = 10**9 + 7
fac = [1 for k in range(200010)]
inv = [1 for k in range(200010)]
finv = [1 for k in range(200010)]
for k in range(2,200010):
    fac[k] = (fac[k-1]*k)%MOD
    inv[k] = (MOD - inv[MOD%k] * (MOD // k))%MOD
    finv[k] = (finv[k - 1] * inv[k]) % MOD;
def nCr(n,r):
    return (fac[n]*finv[r]*finv[n-r])%MOD

N, K = map(int,input().split())
A = sorted(list(map(int,input().split())))
m = 0
for k in range(N-K+1):
    m += A[k]*nCr(N-k-1,K-1)
    m %= MOD
A = A[::-1]
M = 0
for k in range(N-K+1):
    M += A[k]*nCr(N-k-1,K-1)
    M %= MOD
print(M-m if M>=m else M-m+MOD)
