Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class GregArray {
	private static final int N = 100005;
	
	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		String[] line = in.readLine().split(" ");
		int n, m, k;
		n = Integer.parseInt(line[0]);
		m = Integer.parseInt(line[1]);
		k = Integer.parseInt(line[2]);
		long[] l = new long[N], r = new long[N], d = new long[N], a = new long[N], op = new long[N], b = new long[N];
		line = in.readLine().split(" ");
		for (int i = 1; i <= n; i++) {
			a[i] = Long.parseLong(line[i - 1]);
		}
		for (int i = 1; i <= m; i++) {
			line = in.readLine().split(" ");
			l[i] = Long.parseLong(line[0]);
			r[i] = Long.parseLong(line[1]);
			d[i] = Long.parseLong(line[2]);
		}
		int x, y;
		for (int i = 1; i <= k; i++) {
			line = in.readLine().split(" ");
			x = Integer.parseInt(line[0]);
			y = Integer.parseInt(line[1]);
			op[x]++;
			op[y + 1]--;
		}
		for (int i = 1; i <= m; i++) {
			op[i] += op[i - 1];
			d[i] *= op[i];
		}
		for (int i = 1; i <= m; i++) {
			b[(int) l[i]] += d[i];
			b[(int) r[i] + 1] -= d[i];
		}
		for (int i = 1; i <= n; i++) {
			b[i] += b[i - 1];
			a[i] += b[i];
		}
		for (int i = 1; i < n; i++) {
			System.out.print(a[i]);
			System.out.print(" ");
		}
		System.out.println(a[n]);
	}

}
