The Cartesian coordinate system is set in the sky. There you can see n stars, the i-th has coordinates (xi, yi), a maximum brightness c, equal for all stars, and an initial brightness si (0 ≤ si ≤ c).

Over time the stars twinkle. At moment 0 the i-th star has brightness si. Let at moment t some star has brightness x. Then at moment (t + 1) this star will have brightness x + 1, if x + 1 ≤ c, and 0, otherwise.

You want to look at the sky q times. In the i-th time you will look at the moment ti and you will see a rectangle with sides parallel to the coordinate axes, the lower left corner has coordinates (x1i, y1i) and the upper right — (x2i, y2i). For each view, you want to know the total brightness of the stars lying in the viewed rectangle.

A star lies in a rectangle if it lies on its border or lies strictly inside it.

Input

The first line contains three integers n, q, c (1 ≤ n, q ≤ 105, 1 ≤ c ≤ 10) — the number of the stars, the number of the views and the maximum brightness of the stars.

The next n lines contain the stars description. The i-th from these lines contains three integers xi, yi, si (1 ≤ xi, yi ≤ 100, 0 ≤ si ≤ c ≤ 10) — the coordinates of i-th star and its initial brightness.

The next q lines contain the views description. The i-th from these lines contains five integers ti, x1i, y1i, x2i, y2i (0 ≤ ti ≤ 109, 1 ≤ x1i < x2i ≤ 100, 1 ≤ y1i < y2i ≤ 100) — the moment of the i-th view and the coordinates of the viewed rectangle.

Output

For each view print the total brightness of the viewed stars.

Examples

Input

2 3 3
1 1 1
3 2 0
2 1 1 2 2
0 2 1 4 5
5 1 1 5 5


Output

3
0
3


Input

3 4 5
1 1 2
2 3 0
3 3 1
0 1 1 100 100
1 2 2 4 4
2 2 1 4 7
1 50 50 51 51


Output

3
3
5
0

Note

Let's consider the first example.

At the first view, you can see only the first star. At moment 2 its brightness is 3, so the answer is 3.

At the second view, you can see only the second star. At moment 0 its brightness is 0, so the answer is 0.

At the third view, you can see both stars. At moment 5 brightness of the first is 2, and brightness of the second is 1, so the answer is 3.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class P835C
{
	static int[][][] cumul;
	public static void main(String[] args)
	{
		FastScanner scan = new FastScanner();
		int n = scan.nextInt();
		int q = scan.nextInt();
		int c = scan.nextInt()+1;
		int[][][] brightness = new int[c][100][100];
		for (int i = 0; i < n; i++)
		{
			int x = scan.nextInt()-1, y = scan.nextInt()-1, s = scan.nextInt();
			for (int j = 0; j < c; j++)
			{				
				brightness[j][x][y] += (s+j)%c;
			}
		}
		cumul = new int[c][100][100];
		for (int t = 0; t < c; t++)
		{
			for (int i = 0; i < 100; i++)
			{
				for (int j = 0; j < 100; j++)
				{
					cumul[t][i][j] = brightness[t][i][j];
					if (i > 0)
						cumul[t][i][j] += cumul[t][i-1][j];
					if (j > 0)
						cumul[t][i][j] += cumul[t][i][j-1];
					if (i > 0 && j > 0)
						cumul[t][i][j] -= cumul[t][i-1][j-1];
				}
			}
		}
		PrintWriter pw = new PrintWriter(System.out);
		for (int i = 0; i < q; i++)
		{
			int t = scan.nextInt();
			int x1 = scan.nextInt()-1;
			int y1 = scan.nextInt()-1;
			int x2 = scan.nextInt()-1;
			int y2 = scan.nextInt()-1;
			pw.println(getTotal(x1, x2, y1, y2, t%c));
		}
		pw.flush();
	}
	private static int getTotal(int x1, int x2, int y1, int y2, int t)
	{
		int total = cumul[t][x2][y2];
		if (x1 > 0)
			total -= cumul[t][x1-1][y2];
		if (y1 > 0)
			total -= cumul[t][x2][y1-1];
		if (x1 > 0 && y1 > 0)
			total += cumul[t][x1-1][y1-1];
		return total;
	}
	static class FastScanner
	{
		BufferedReader r;
		StringTokenizer t;

		FastScanner()
		{
			r = new BufferedReader(new InputStreamReader(System.in));
			t = new StringTokenizer("");
		}

		String next()
		{
			while (!t.hasMoreElements())
				try
				{
					t = new StringTokenizer(r.readLine());
				} catch (IOException e)
				{
					e.printStackTrace();
				}
			return t.nextToken();
		}

		int nextInt()
		{
			return Integer.parseInt(next());
		}

		double nextDouble()
		{
			return Double.parseDouble(next());
		}
	}
}
