Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include <bits/stdc++.h>
using namespace std;

const int Mask = (1 << 17) - 1;
const int mod = 1e9 + 7;

int f[47][Mask + 5];

int append(int status, int x) {
	return ((status << x) | (1 << (x - 1))) & Mask;
}

int main(){
    //freopen(".in","r",stdin);
    //freopen(".out","w",stdout);
	int n, x, y, z;
	
	cin >> n >> x >> y >> z;
	
	int S = 0;
	S = append(S, x);
	S = append(S, y);
	S = append(S, z);
	
	f[0][0] = 1;
	
	for(int i = 1; i <= n; i++) {
		for(int j = 0; j <= Mask; j++) 
			for(int k = 1; k <= 10; k++) {
				int NewStatus = append(j, k);
				if((NewStatus & S) == S) continue;
				f[i][NewStatus] = (f[i][NewStatus] + f[i - 1][j]) % mod;
			}
	}
	int ans = 1;
	for(int i = 1; i <= n; i++) ans = 10LL * ans % mod;
		
	for(int i = 0; i <= Mask; i++) ans = (ans - f[n][i]) % mod;
		cout << (ans + mod) % mod;
			 
    return 0;
}
