Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include<iostream>
#include<cstdio>
typedef long long ll;
const ll mod=1e9+7;
int T,n,x,y,z,es,t;
ll dp[42][1<<19],f[42];
ll dfs(int p,int c) {
    if(p>=n) return 0;
    if(dp[p][c]!=-1) return dp[p][c];
    ll &res=dp[p][c];res=0;
    for(int i=1;i<=10;i++) {
        int to=c<<i|1;to%=1<<t;
        if((to&es)==es) res+=f[n-p-1],res%=mod;
        else res+=dfs(p+1,to),res%=mod;
    }
    return res;
}
int main() {
    f[0]=1;for(int i=1;i<=40;i++) f[i]=f[i-1]*10%mod;
    //scanf("%d",&T);
    //while(T--) {
        scanf("%d%d%d%d",&n,&x,&y,&z);
        es=1<<(x+y+z)|1<<(y+z)|1<<z;t=x+y+z+1;
        for(int i=0;i<n;i++) for(int j=0;j<1<<t;j++) dp[i][j]=-1;
        printf("%lld\n",dfs(0,1));
    //}
    return 0;
}
