For a finite set of integers X, let f(X)=\max X - \min X.

Given are N integers A_1,...,A_N.

We will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.

Since the answer can be enormous, print it \bmod (10^9+7).

Constraints

* 1 \leq N \leq 10^5
* 1 \leq K \leq N
* |A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:


N K
A_1 ... A_N


Output

Print the answer \bmod (10^9+7).

Examples

Input

4 2
1 1 3 4


Output

11


Input

6 3
10 10 10 -10 -10 -10


Output

360


Input

3 1
1 1 1


Output

0


Input

10 6
1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0


Output

999998537
n,k=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
U = 2*10**5
MOD = 10**9+7
fact = [1]*(U+1)
fact_inv = [1]*(U+1)
for i in range(1,U+1):
  fact[i] = (fact[i-1]*i)%MOD
fact_inv[U] = pow(fact[U],MOD-2,MOD)
for i in range(U,0,-1):
	fact_inv[i-1] = (fact_inv[i]*i)%MOD
def comb(n,k):
  if k < 0 or k > n:
    return 0
  x = fact[n]
  x *= fact_inv[k]
  x %= MOD
  x *= fact_inv[n-k]
  x %= MOD
  return x

mod=10**9+7
p=a[:n-k+1][::-1]
q=a[k-1:]
ans=0
for i in range(1,len(p)+1):
    ans+=(q[i-1]-p[i-1])*comb(k-2+i,k-1)
    ans%=mod
print(ans)