You play a computer game. In this game, you lead a party of m heroes, and you have to clear a dungeon with n monsters. Each monster is characterized by its power a_i. Each hero is characterized by his power p_i and endurance s_i.

The heroes clear the dungeon day by day. In the beginning of each day, you choose a hero (exactly one) who is going to enter the dungeon this day.

When the hero enters the dungeon, he is challenged by the first monster which was not defeated during the previous days (so, if the heroes have already defeated k monsters, the hero fights with the monster k + 1). When the hero fights the monster, there are two possible outcomes:

  * if the monster's power is strictly greater than the hero's power, the hero retreats from the dungeon. The current day ends; 
  * otherwise, the monster is defeated. 



After defeating a monster, the hero either continues fighting with the next monster or leaves the dungeon. He leaves the dungeon either if he has already defeated the number of monsters equal to his endurance during this day (so, the i-th hero cannot defeat more than s_i monsters during each day), or if all monsters are defeated — otherwise, he fights with the next monster. When the hero leaves the dungeon, the current day ends.

Your goal is to defeat the last monster. What is the minimum number of days that you need to achieve your goal? Each day you have to use exactly one hero; it is possible that some heroes don't fight the monsters at all. Each hero can be used arbitrary number of times.

Input

The first line contains one integer t (1 ≤ t ≤ 10^5) — the number of test cases. Then the test cases follow.

The first line of each test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of monsters in the dungeon.

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the power of the i-th monster.

The third line contains one integer m (1 ≤ m ≤ 2 ⋅ 10^5) — the number of heroes in your party.

Then m lines follow, each describing a hero. Each line contains two integers p_i and s_i (1 ≤ p_i ≤ 10^9, 1 ≤ s_i ≤ n) — the power and the endurance of the i-th hero.

It is guaranteed that the sum of n + m over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case print one integer — the minimum number of days you have to spend to defeat all of the monsters (or -1 if it is impossible).

Example

Input


2
6
2 3 11 14 1 8
2
3 2
100 1
5
3 5 100 2 3
2
30 5
90 1


Output


5
-1
/**
 * BaZ :D
 */
import java.util.*;
import java.io.*;
import static java.lang.Math.*;

public class ACMIND
{
    static FastReader scan;
    static PrintWriter pw;
    static long MOD = 1_000_000_007;
    static long INF = 1_000_000_000_000_000_000L;
    static long inf = 2_000_000_000;
    public static void main(String[] args) {
        new Thread(null,null,"BaZ",1<<27)
        {
            public void run()
            {
                try
                {
                    solve();
                }
                catch(Exception e)
                {
                    e.printStackTrace();
                    System.exit(1);
                }
            }
        }.start();
    }
    static int n,m,arr[], suff_max[];
    static int tree[];
    static Pair brr[];
    static void solve() throws IOException
    {
        scan = new FastReader();
        pw = new PrintWriter(System.out,true);
        StringBuilder sb = new StringBuilder();
        int t = ni();
        while (t-->0) {
            n = ni();
            arr = new int[n];
            for(int i=0;i<n;++i) {
                arr[i] = ni();
            }
            int sz = (int)pow(2, ceil(log(n)/log(2))+1);
            tree = new int[sz];
            build(1,0,n-1);
            int dp[] = new int[n+1];
            m = ni();
            brr = new Pair[m];
            for(int i=0;i<m;++i) {
                brr[i] = new Pair(ni(), ni());
            }
            Arrays.sort(brr);
            suff_max = new int[m];
            for(int i=m-1;i>=0;--i) {
                suff_max[i] = brr[i].y;
                if(i+1<m) {
                    suff_max[i] = max(suff_max[i], suff_max[i+1]);
                }
            }
            for(int i=n-1;i>=0;--i) {
                int low = 0, high = (n-i), ans = low, mid;
                while(low<=high) {
                    mid = (low+high)>>1;
                    if(check(i, mid)) {
                        ans = mid;
                        low = ++mid;
                    }
                    else {
                        high = --mid;
                    }
                }
                //pl("From i : "+(ans));
                if(ans==0) {
                    dp[0] = -1;
                    break;
                }
                else {
                    dp[i] = 1+dp[i+ans];
                }
            }
            pl(dp[0]);
        }
        pw.flush();
        pw.close();
    }
    static boolean check(int idx, int len) {
        int max = query(idx, idx+len-1);
        int fidx = getFirst(max);
        if(fidx == -1) {
            return false;
        }
        return suff_max[fidx] >= len;
    }
    static int getFirst(int k) {
        if(brr[m-1].x<k) {
            return -1;
        }
        int low = 0, high = m-1, ans = high, mid;
        while(low<=high) {
            mid = (low+high)>>1;
            if(brr[mid].x >= k) {
                ans = mid;
                high = --mid;
            }
            else {
                low = ++mid;
            }
        }
        return ans;
    }
    static class Pair implements Comparable<Pair>
    {
        int x,y;
        Pair(int x,int y)
        {
            this.x=x;
            this.y=y;
        }
        public int compareTo(Pair other)
        {
            if(this.x!=other.x)
                return this.x-other.x;
            return this.y-other.y;
        }
        public String toString()
        {
            return "("+x+","+y+")";
        }
    }
    static void build(int treein,int low,int high)
    {
        if(low==high)
            tree[treein] = arr[low];
        else
        {
            int mid = (low+high)>>1;
            build(2*treein,low,mid);
            build(2*treein+1,mid+1,high);
            tree[treein] = max(tree[2*treein],tree[2*treein+1]);
        }
    }
    static void update(int treein,int low,int high,int idx,int val)
    {
        if(low==high)
            tree[treein] = val;
        else
        {
            int mid = (low+high)>>1;
            if(idx<=mid)
                update(2*treein,low,mid,idx,val);
            else update(2*treein+1,mid+1,high,idx,val);
            tree[treein] = max(tree[2*treein],tree[2*treein+1]);
        }
    }
    static int query(int treein,int low,int high,int l,int r)
    {
        if(l<=low && high<=r)
            return tree[treein];
        if(low>r || high<l)
            return 0;
        int mid = (low+high)>>1;
        return max(query(2*treein,low,mid,l,r),query(2*treein+1,mid+1,high,l,r));
    }
    static int query(int l,int r)
    {
        return query(1,0,n-1,l,r);
    }
    static void update(int idx,int val)
    {
        update(1,0,n-1,idx,val);
    }
    static int ni() throws IOException
    {
        return scan.nextInt();
    }
    static long nl() throws IOException
    {
        return scan.nextLong();
    }
    static double nd() throws IOException
    {
        return scan.nextDouble();
    }
    static void pl()
    {
        pw.println();
    }
    static void p(Object o)
    {
        pw.print(o+" ");
    }
    static void pl(Object o)
    {
        pw.println(o);
    }
    static void psb(StringBuilder sb)
    {
        pw.print(sb);
    }
    static void pa(String arrayName, Object arr[])
    {
        pl(arrayName+" : ");
        for(Object o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, int arr[])
    {
        pl(arrayName+" : ");
        for(int o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, long arr[])
    {
        pl(arrayName+" : ");
        for(long o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, double arr[])
    {
        pl(arrayName+" : ");
        for(double o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, char arr[])
    {
        pl(arrayName+" : ");
        for(char o : arr)
            p(o);
        pl();
    }
    static void pa(String listName, List list)
    {
        pl(listName+" : ");
        for(Object o : list)
            p(o);
        pl();
    }
    static void pa(String arrayName, Object[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(Object o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, int[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(int o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, long[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(long o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, char[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(char o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, double[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(double o : arr[i])
                p(o);
            pl();
        }
    }
    static class FastReader {
        final private int BUFFER_SIZE = 1 << 16;
        private DataInputStream din;
        private byte[] buffer;
        private int bufferPointer, bytesRead;

        public FastReader() {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public FastReader(String file_name) throws IOException {
            din = new DataInputStream(new FileInputStream(file_name));
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public String readLine() throws IOException {
            byte[] buf = new byte[1000000];
            int cnt = 0, c;
            while ((c = read()) != -1) {
                if (c == '\n') break;
                buf[cnt++] = (byte) c;
            }
            return new String(buf, 0, cnt);
        }

        public int nextInt() throws IOException {
            int ret = 0;
            byte c = read();
            while (c <= ' ') c = read();
            boolean neg = (c == '-');
            if (neg) c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg) return -ret;
            return ret;
        }

        public long nextLong() throws IOException {
            long ret = 0;
            byte c = read();
            while (c <= ' ') c = read();
            boolean neg = (c == '-');
            if (neg) c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg) return -ret;
            return ret;
        }

        public double nextDouble() throws IOException {
            double ret = 0, div = 1;
            byte c = read();
            while (c <= ' ') c = read();
            boolean neg = (c == '-');
            if (neg) c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (c == '.') while ((c = read()) >= '0' && c <= '9') ret += (c - '0') / (div *= 10);
            if (neg) return -ret;
            return ret;
        }

        private void fillBuffer() throws IOException {
            bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
            if (bytesRead == -1) buffer[0] = -1;
        }

        private byte read() throws IOException {
            if (bufferPointer == bytesRead) fillBuffer();
            return buffer[bufferPointer++];
        }

        public void close() throws IOException {
            if (din == null) return;
            din.close();
        }
    }
}