Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
import sys
n,m,k=map(int,sys.stdin.readline().split())

O=[]
A=list(map(int,sys.stdin.readline().split()))

for i in range(m):
    l,r,d=map(int,sys.stdin.readline().split())
    O.append([l,r,d])

L=[0]*m


for i in range(k):
    x,y=map(int,sys.stdin.readline().split())
    L[x-1]+=1
    if(y!=m):
        L[y]-=1

I=[0]*n

for i in range(1,m):
    L[i]+=L[i-1]

for i in range(m):
    X=O[i]
    Increase=X[2]*L[i]
    if(X[1]!=n):
        I[X[1]]-=Increase
    I[X[0]-1]+=Increase

for i in range(1,n):
    I[i]+=I[i-1]

for i in range(n):
    A[i]+=I[i]
Ans=""
for item in A:
    Ans+=str(item)+" "
sys.stdout.write(Ans)
    
