Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
import java.io.*;
import java.math.*;
import java.util.*;

public class Main implements Runnable {
    private BufferedReader br;
    private StringTokenizer tok;
    private PrintWriter out;

    static final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;

    void solve() throws IOException {
        int n = nextInt(), m = nextInt(), k = nextInt();
        long[] a = new long[n];
        for (int i = 0; i < n; ++i) {
            a[i] = nextInt();
        }
        int[] l = new int[m];
        int[] r = new int[m];
        int[] d = new int[m];
        for (int i = 0; i < m; ++i) {
            l[i] = nextInt();
            r[i] = nextInt();
            d[i] = nextInt();
        }
        int[] cnt = new int[m];
        for (int i = 0; i < k; ++i) {
            int x = nextInt(), y = nextInt();
            ++cnt[x - 1];
           if (y < m) {
               --cnt[y];
           }
        }
        for (int i = 1; i < m; ++i) {
            cnt[i] += cnt[i - 1];
        }
        long[] add = new long[n];
        for (int i = 0; i < m; ++i) {
            add[l[i] - 1] += (long)d[i] * cnt[i];
            if (r[i] < n) {
                add[r[i]] -= (long)d[i] * cnt[i];
            }
        }
        for (int i = 1; i < n; ++i) {
            add[i] += add[i - 1];
        }
        for (int i = 0; i < n; ++i) {
            out.print((a[i] + add[i]) + " ");
        }
    }

    public void run() {
        try {
            if (ONLINE_JUDGE) {
                br = new BufferedReader(new InputStreamReader(System.in));
                out = new PrintWriter(System.out);
            } else {
                br = new BufferedReader(new FileReader(new File("input.txt")));
                out = new PrintWriter(new File("output.txt"));
            }
            solve();
            br.close();
            out.close();
        } catch (IOException e) {
            e.printStackTrace();
            System.exit(1);
        }
    }

    public static void main(String[] args) {
        new Thread(null, new Main(), "", 128 * (1L << 20)).start();
    }

    String nextToken() throws IOException {
        while (tok == null || !tok.hasMoreTokens())
            tok = new StringTokenizer(br.readLine());
        return tok.nextToken();
    }

    String nextString() throws IOException {
        return nextToken();
    }

    int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }

    long nextLong() throws IOException {
        return Long.parseLong(nextToken());
    }

    double nextDouble() throws IOException {
        return Double.parseDouble(nextToken());
    }

    BigInteger nextBigInteger() throws IOException {
        return new BigInteger(nextToken());
    }
}