Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.
def solve():
    u, v = map(int, input().split())
    if abs(u - v) % 2 != 0 or u > v: return -1
    elif u==v:
        return f"{1}\n{u}" if u!=0 else "0"
    else:
        x=(v-u)//2
        if(u&x):
            return f"3\n{u} {x} {x}"
        else:
            return f"2\n{u^x} {x}"

if __name__ == '__main__':
    print(solve())
