Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
n, m, k = map(int, input().strip().split())
a=[int(i) for i in input().split()]
l=[0]*m
r=[0]*m
d=[0]*m
j=m+1
arr=[0]*j
for i in range(m):
    t,o,v=map(int,input().strip().split())
    l[i]=t
    r[i]=o
    d[i]=v
while k>0:
    x,y=map(int,input().strip().split())
    x-=1
    y-=1
    pp=arr[x]
    uu=arr[y+1]
    arr[x]=pp+1
    arr[y+1]=uu-1
    k-=1
for i in range(1,m):
    ss=arr[i]
    arr[i]=ss+arr[i-1]
arr1=[0]*(n+1)
for i in range(m):
    mm=l[i]
    nn=r[i]
    mm-=1
    nn-=1
    arr1[mm]+=arr[i]*d[i]
    arr1[nn+1]-=arr[i]*d[i]
for i in range(1,n):
    hh=arr1[i]
    arr1[i]=hh+arr1[i-1]
l=[0]*n
for i in range(n):
    l[i]=a[i]+arr1[i]
print(" ".join(map(str,l)))