For a finite set of integers X, let f(X)=\max X - \min X.

Given are N integers A_1,...,A_N.

We will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.

Since the answer can be enormous, print it \bmod (10^9+7).

Constraints

* 1 \leq N \leq 10^5
* 1 \leq K \leq N
* |A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:


N K
A_1 ... A_N


Output

Print the answer \bmod (10^9+7).

Examples

Input

4 2
1 1 3 4


Output

11


Input

6 3
10 10 10 -10 -10 -10


Output

360


Input

3 1
1 1 1


Output

0


Input

10 6
1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0


Output

999998537
def prepare(m, mod=10 ** 9 + 7):
	fac = [1] * (m + 1)
	inv = [1] * (m + 1)
	for i in range(1, m + 1):
		fac[i] = fac[i - 1] * i % mod
	inv[-1] = pow(fac[-1], mod - 2, mod)
	for i in range(m - 1, -1, -1):
		inv[i] = inv[i + 1] * (i + 1) % mod
	return fac, inv

n,k,*a=map(int,open(0).read().split())
mod=10**9+7
a.sort()
fac,inv=prepare(n)

def cmb(n, r):
	assert n >= r >= 0
	return fac[n] * inv[n - r] * inv[r] % mod

m=M=0
for i,x in enumerate(a):
	if not n-i+1<=k:
		m+=cmb(n-i-1,k-1)*x
		m%=mod
	if not i+2<=k:
		M+=cmb(i,k-1)*x
		M%=mod
print((M-m)%mod)
