We have a weighted directed graph with N vertices numbered 0 to N-1.

The graph initially has N-1 edges. The i-th edge (0 \leq i \leq N-2) is directed from Vertex i to Vertex i+1 and has a weight of 0.

Snuke will now add a new edge (i → j) for every pair i, j (0 \leq i,j \leq N-1,\ i \neq j). The weight of the edge will be -1 if i < j, and 1 otherwise.

Ringo is a boy. A negative cycle (a cycle whose total weight is negative) in a graph makes him sad. He will delete some of the edges added by Snuke so that the graph will no longer contain a negative cycle. The cost of deleting the edge (i → j) is A_{i,j}. He cannot delete edges that have been present from the beginning.

Find the minimum total cost required to achieve Ringo's objective.

Constraints

* 3 \leq N \leq 500
* 1 \leq A_{i,j} \leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_{0,1} A_{0,2} A_{0,3} \cdots A_{0,N-1}
A_{1,0} A_{1,2} A_{1,3} \cdots A_{1,N-1}
A_{2,0} A_{2,1} A_{2,3} \cdots A_{2,N-1}
\vdots
A_{N-1,0} A_{N-1,1} A_{N-1,2} \cdots A_{N-1,N-2}


Output

Print the minimum total cost required to achieve Ringo's objective.

Examples

Input

3
2 1
1 4
3 3


Output

2


Input

4
1 1 1
1 1 1
1 1 1
1 1 1


Output

2


Input

10
190587 2038070 142162180 88207341 215145790 38 2 5 20
32047998 21426 4177178 52 734621629 2596 102224223 5 1864
41 481241221 1518272 51 772 146 8805349 3243297 449
918151 126080576 5186563 46354 6646 491776 5750138 2897 161
3656 7551068 2919714 43035419 495 3408 26 3317 2698
455357 3 12 1857 5459 7870 4123856 2402 258
3 25700 16191 102120 971821039 52375 40449 20548149 16186673
2 16 130300357 18 6574485 29175 179 1693 2681
99 833 131 2 414045824 57357 56 302669472 95
8408 7 1266941 60620177 129747 41382505 38966 187 5151064


Output

2280211
#include<bits/stdc++.h>
#define read() Read<int>()
namespace pb_ds{   
    namespace io{
        const int MaxBuff=1<<15;
        const int Output=1<<23;
        char B[MaxBuff],*S=B,*T=B;
		#define getc() ((S==T)&&(T=(S=B)+fread(B,1,MaxBuff,stdin),S==T)?0:*S++)
        char Out[Output],*iter=Out;
        inline void flush(){
            fwrite(Out,1,iter-Out,stdout);
            iter=Out;
        }
    }
    template<class Type> inline Type Read(){
        using namespace io;
        register char ch;
        register Type ans=0; 
        register bool neg=0;
        while(ch=getc(),(ch<'0' || ch>'9') && ch!='-');
        ch=='-'?neg=1:ans=ch-'0';
        while(ch=getc(),'0'<= ch && ch<='9') ans=ans*10+ch-'0';
        return neg?-ans:ans;
    }
    template<class Type> inline void Print(register Type x,register char ch='\n'){
        using namespace io;
        if(!x) *iter++='0';
        else{
            if(x<0) *iter++='-',x=-x;
            static int s[100]; 
            register int t=0;
            while(x) s[++t]=x%10,x/=10;
            while(t) *iter++='0'+s[t--];
        }
        *iter++=ch;
    }
}
using namespace pb_ds;
using namespace std;
typedef long long ll;
const int N=505;
const ll inf=(ll)1e18;
int n;
int a[N][N],b[N][N];
ll ans=inf;
ll c[N][N],d[N][N],dp[N][N];
int main(){
	//freopen("negative.in","r",stdin);
	//freopen("negative.out","w",stdout);
	n=read();
	for (int i=1;i<=n;++i){
		for (int j=1;j<i;++j) a[j][i]=read();
		for (int j=i+1;j<=n;++j) b[i][j]=read();
	}
	for (int i=1;i<=n+1;++i){
		for (int j=i;j<=n+1;++j){
			c[i][j]=c[i-1][j];
			for (int k=j;k<=n;++k) c[i][j]+=a[i][k];
		}
	}
	for (int i=n+1;i;--i){
		for (int j=i;j<=n+1;++j){
			d[i][j]=d[i+1][j];
			for (int k=i;k<=j;++k) d[i][j]+=b[i][k];
		}
	}
	memset(dp,0x3f,sizeof(dp));
	dp[0][0]=0;
	for (int i=1;i<=n+1;++i)
		for (int j=0;j<i;++j)
			for (int k=0;k<=j;++k)
				dp[i][j]=min(dp[i][j],dp[j][k]+c[j][i+1]-c[k][i+1]+d[j+1][i]);
	for (int i=0;i<=n;++i)
		ans=min(ans,dp[n+1][i]);
	printf("%lld\n",ans);
	return 0;
}