Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

#define For(i, x, y) for (int i = x; i <= (int)(y); ++i)
#define Rep(i, x, y) for (int i = y; i >= (int)(x); --i)
#define While while
#define mem memset

const int mod = 1e9 + 7;
const int mask = (1 << 17);

int n, x, y, z, f[47][mask + 7];

int Ins(int S, int x) {
	return ((S << x) | (1 << (x - 1))) & (mask - 1);
}

int main() {
	scanf("%d%d%d%d", &n, &x, &y, &z);
	
	int S = 0; S = Ins(S, x); S = Ins(S, y); S = Ins(S, z);
	
	f[0][0] = 1;
	For(i, 1, n)
		For(j, 0, mask - 1) {
			For(k, 1, 10) {
				int now = Ins(j, k);
				if ((now & S) == S) continue;
				f[i][now] = (f[i][now] + f[i - 1][j]) % mod; 
			}
		}
	
	ll ans = 1;
	For(i, 1, n) ans = (ans * 10LL) % mod;
	For(i, 0, mask - 1) ans = (ans - f[n][i]) % mod;
	
	printf("%lld\n", (ans + mod) % mod);
	 
	return 0;
}
