There are n students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent pieces, and then discuss the results together. It takes the i-th student ai minutes to finish his/her independent piece.

If students work at different paces, it can be frustrating for the faster students and stressful for the slower ones. In particular, the imbalance of a group is defined as the maximum ai in the group minus the minimum ai in the group. Note that a group containing a single student has an imbalance of 0. How many ways are there for the students to divide into groups so that the total imbalance of all groups is at most k?

Two divisions are considered distinct if there exists a pair of students who work in the same group in one division but different groups in the other.

Input

The first line contains two space-separated integers n and k (1 ≤ n ≤ 200, 0 ≤ k ≤ 1000) — the number of students and the maximum total imbalance allowed, respectively.

The second line contains n space-separated integers ai (1 ≤ ai ≤ 500) — the time it takes the i-th student to complete his/her independent piece of work.

Output

Print a single integer, the number of ways the students can form groups. As the answer may be large, print its value modulo 109 + 7.

Examples

Input

3 2
2 4 5


Output

3


Input

4 3
7 8 9 10


Output

13


Input

4 0
5 10 20 21


Output

1

Note

In the first sample, we have three options: 

  * The first and second students form a group, and the third student forms a group. Total imbalance is 2 + 0 = 2. 
  * The first student forms a group, and the second and third students form a group. Total imbalance is 0 + 1 = 1. 
  * All three students form their own groups. Total imbalance is 0. 



In the third sample, the total imbalance must be 0, so each student must work individually.
import java.io.*;
import java.util.*;

import static java.math.BigDecimal.valueOf;

public class Main {
    static MyScanner sc;
    private static PrintWriter out;
    static long M2 = 1_000_000_000L + 7;

    public static void main(String[] s) throws Exception {
        StringBuilder stringBuilder = new StringBuilder();

//        stringBuilder.append("4 10 4 0 4 4 0 4 0 0");
//        stringBuilder.append("3 10\n" +
//                "3 1\n" +
//                "0 2\n" +
//                "5 3");
//        stringBuilder.append("110 2");
        if (stringBuilder.length() == 0) {
            sc = new MyScanner(System.in);
        } else {
            sc = new MyScanner(new BufferedReader(new StringReader(stringBuilder.toString())));
        }


        out = new PrintWriter(new OutputStreamWriter(System.out));
        initData();
        solve();
        out.flush();
    }


    private static void initData() {

    }


    private static void solve() throws IOException {
        int n = sc.nextInt();
        int k = sc.nextInt();
        int[] data = sc.na(n);
        Arrays.sort(data);
        long[][] res = new long[n + 1][k + 1];
        res[0][0] = 1;
        for (int s = 0; s < n; s++) {
            long[][] next = new long[n + 1][k + 1];
            int diff = s == 0 ? 0 : (data[s] - data[s - 1]);
            for (int sets = 0; sets <= n / 2; sets++) {
                for (int curK = 0; curK <= k; curK++) {
                    int val = diff * sets;
                    if (curK + val > k) continue;
                    if (sets > 0) {
                        // close
                        next[sets - 1][curK + val] += (sets * res[sets][curK]) % M2;
                        next[sets - 1][curK + val] %= M2;
                        // add to existing
                        next[sets][curK + val] += (sets * res[sets][curK]) % M2;
                        next[sets][curK + val] %= M2;
                    }
                    // open and close
                    next[sets][curK + val] += res[sets][curK];
                    next[sets][curK + val] %= M2;
                    // create new
                    next[sets + 1][curK + val] += res[sets][curK];
                    next[sets + 1][curK + val] %= M2;
                }
            }
            res = next;
        }
        out.println(Arrays.stream(res[0]).sum() % M2);
    }

    private static int ccw(int[] i1, int[] i2) {
        return ccw(i1, i2, new int[]{0, 0});
    }

    private static int ccw(int[] s1, int[] s2, int[] right) {
        long xa = s1[0] - right[0];
        long xb = s1[1] - right[1];
        long ya = s2[0] - right[0];
        long yb = s2[1] - right[1];
        return Long.compare(xb * ya, xa * yb);
    }


    private static void solveT() throws IOException {
        int t = sc.nextInt();
        while (t-- > 0) {
            solve();
        }
    }

    private static long gcd(long l, long l1) {
        if (l > l1) return gcd(l1, l);
        if (l == 0) return l1;
        return gcd(l1 % l, l);
    }

    private static long pow(long a, long b, long m) {
        if (b == 0) return 1;
        if (b == 1) return a;
        long pp = pow(a, b / 2, m);
        pp *= pp;
        pp %= m;
        return (pp * (b % 2 == 0 ? 1 : a)) % m;
    }


    static class MyScanner {
        BufferedReader br;
        StringTokenizer st;

        MyScanner(BufferedReader br) {
            this.br = br;
        }

        public MyScanner(InputStream in) {
            this(new BufferedReader(new InputStreamReader(in)));
        }

        void findToken() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
        }

        String next() {
            findToken();
            return st.nextToken();
        }

        Integer[] nab(int n) {
            Integer[] k = new Integer[n];
            for (int i = 0; i < n; i++) {
                k[i] = sc.fi();
            }
            return k;
        }

        int[] na(int n) {
            int[] k = new int[n];
            for (int i = 0; i < n; i++) {
                k[i] = sc.fi();
            }
            return k;
        }

        long[] nl(int n) {
            long[] k = new long[n];
            for (int i = 0; i < n; i++) {
                k[i] = sc.nextLong();
            }
            return k;
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        int fi() {
            String t = next();
            int cur = 0;
            boolean n = t.charAt(0) == '-';
            for (int a = n ? 1 : 0; a < t.length(); a++) {
                cur = cur * 10 + t.charAt(a) - '0';
            }
            return n ? -cur : cur;
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }
    }


}