Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.
x,y=map(int,input().split())
if(x==0 and y==0):
    print(0)
elif(x==y):
    print(1)
    print(x)
elif(abs(x-y)%2==1 or x>y):
    print(-1)
else:
    y=y-x
    y=y//2
    yy=y
    xx=x
    p=0
    while(yy>0):
        if(yy%2==1 and xx%2==1):
            p=1
            break
        xx//=2
        yy//=2
    if(p==1):
        print(3)
        print(y,y,x)
    else:
        print(2)
        print(y,x+y)