Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include <bits/stdc++.h>
using namespace std;

const int64_t MOD = 1e9+7;
void add(int64_t& a, int64_t b){
    a = (a+b) % MOD;
}
void mul(int64_t& a, int64_t b){
    a = a*b % MOD;
}

int nth_bit(int64_t num, int n){
    return (num >> n) & 1;
}

int main(){
    int N, X, Y, Z;
    cin >> N >> X >> Y >> Z;

    int XYZ = (1<<Z) + (1<<(Y+Z)) + (1<<(X+Y+Z));
    const int M = 1<<18;
    const int B = M-1;
    static int64_t dp[41][M][2];
    dp[0][1][0] = 1;
    for(int i=0; i<N; i++) for(int j=0; j<M; j++) for(int k=0; k<2; k++) for(int l=1; l<=10; l++){
        int j2 = ((j<<l) + 1) & B;
        int k2 = k | (XYZ == (XYZ&j2));
        add(dp[i+1][j2][k2], dp[i][j][k]);
    }
    int64_t ans = 0;
    for(int j=0; j<M; j++) add(ans, dp[N][j][1]);
    cout << ans << endl;
}