Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
# -------
# imports
# -------

import sys


# -------
# solve
# -------

def solve(r, w):
    """
    :param r:
    :param w:
    :return:
    """
    data = r.readline().split()
    num_elems = int(data[0])
    num_ops = int(data[1])
    num_queries = int(data[2])

    elem_list = [int(x) for x in r.readline().split()]
    a = [0] * (num_ops + 1)
    b = [0] * (num_elems + 1)

    # get operations
    op_list = []
    for _ in range(num_ops):
        op_list.append(tuple([int(x) for x in r.readline().split()]))

    for _ in range(num_queries):
        query = [int(x) for x in r.readline().split()]
        a[query[0] - 1] += 1
        a[query[1]] -= 1

    c = 0
    for i, cur_op in enumerate(op_list):
        cur_op = op_list[i]
        c += a[i]
        b[cur_op[0] - 1] += c * cur_op[2]
        b[cur_op[1]] -= c * cur_op[2]

    c = 0
    for i, elem in enumerate(elem_list):
        c += b[i]
        print(elem + c, end=' ')


# -------
# main
# -------

if __name__ == "__main__":
    solve(sys.stdin, sys.stdout)
