Poornimites are taught to add multi-digit numbers from right-to-left one digit at a time.
Many find the "carry" operation - in which 1 is carried from one digit position
to be added to the next - to be a significant challenge.  Your job is to
count the number of carry operations for each of addition problem so that educators may assess their difficulty.

For the input first line contains n number of records which is less then 1000. And then each line contains two numbers with spacing between them as shown in sample. 

SAMPLE INPUT
3
123 456
555 555
123 594

SAMPLE OUTPUT
No carry operation
3 carry operations
1 carry operation

Explanation

EXAMPLE 1:-

when the digits are added then there is no carry found as 3+6=9,2+5=7 and 1+4=5.

EXAMPLE 2:-

when the digits are added then carry is generated as 5+5 =10 so carry is found 3 times.

EXAMPLE 3:-

when the digits 9 and 2 are added only then carry is found so 1 time only.
t=int(input())
for tc in range(t):
	a,b=[list(i) for i in raw_input().split()]
	if len(a)<len(b):
		x,y=a,b
	else:
		y,x=a,b
	count=0
	for i,j in enumerate(x):
		if int(j)+int(y[i])>9:
			count=count+1
	if count==0:
		print('No carry operation')
	elif count==1:
		print('1 carry operation')
	else:
		print(str(count)+' carry operations')