Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;
public class GregAndArray {
	public static void main(String[] args) throws IOException {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int m = sc.nextInt();
		int k = sc.nextInt();
		int[] arr = new int[n];
		for(int i=0;i<n;i++)
			arr[i] = sc.nextInt();
		Triple[] q = new Triple[m];
		for(int i=0;i<m;i++)
			q[i] = new Triple(sc.nextInt()-1, sc.nextInt()-1, sc.nextInt());
		
		long[] dx = new long[n+1];
		int[] queries = new int[m+1];
		while(k-->0)
		{
			int x = sc.nextInt()-1;
			int y = sc.nextInt()-1;
			queries[x]++;
			queries[y+1]--;
		}
		for(int i=1;i<queries.length;i++)
			queries[i]+= queries[i-1];
		
		for(int i=0;i<q.length;i++)
		{
			int l = q[i].l;
			int r = q[i].r;
			int d = q[i].d;
			dx[l]+=(1l*queries[i]*d);
			dx[r+1]-=(1l*queries[i]*d);
		}
		
		for(int i=1;i<dx.length;i++)
			dx[i]+= dx[i-1];
		
		PrintWriter pw = new PrintWriter(System.out);
		for(int i=0;i<n;i++)
			pw.print((dx[i]+arr[i])+" ");
		pw.flush();
	}
	static class Triple{
		int l,r,d;
		Triple(int a,int b,int c){l=a;r=b;d=c;}
	}
	static class Scanner{
		StringTokenizer st;BufferedReader br;
		public Scanner(InputStream s){	br = new BufferedReader(new InputStreamReader(s));}
		public String next() throws IOException 
		{while (st == null || !st.hasMoreTokens()) st = new StringTokenizer(br.readLine());return st.nextToken();}
		public int nextInt() throws IOException {return Integer.parseInt(next());}
		public long nextLong() throws IOException {return Long.parseLong(next());}
		public String nextLine() throws IOException {return br.readLine();}
		public double nextDouble() throws IOException {return Double.parseDouble(next());}
		public boolean ready() throws IOException {return br.ready();}
	}
}