Mr. Kitayuta has just bought an undirected graph with n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.

Mr. Kitayuta wants you to process the following q queries.

In the i-th query, he gives you two integers - ui and vi.

Find the number of the colors that satisfy the following condition: the edges of that color connect vertex ui and vertex vi directly or indirectly.

Input

The first line of the input contains space-separated two integers - n and m(2 ≤ n ≤ 105, 1 ≤ m ≤ 105), denoting the number of the vertices and the number of the edges, respectively.

The next m lines contain space-separated three integers - ai, bi(1 ≤ ai < bi ≤ n) and ci(1 ≤ ci ≤ m). Note that there can be multiple edges between two vertices. However, there are no multiple edges of the same color between two vertices, that is, if i ≠ j, (ai, bi, ci) ≠ (aj, bj, cj).

The next line contains a integer- q(1 ≤ q ≤ 105), denoting the number of the queries.

Then follows q lines, containing space-separated two integers - ui and vi(1 ≤ ui, vi ≤ n). It is guaranteed that ui ≠ vi.

Output

For each query, print the answer in a separate line.

Examples

Input

4 5
1 2 1
1 2 2
2 3 1
2 3 3
2 4 3
3
1 2
3 4
1 4


Output

2
1
0


Input

5 7
1 5 1
2 5 1
3 5 1
4 5 1
1 2 2
2 3 2
3 4 2
5
1 5
5 1
2 5
1 5
1 4


Output

1
1
1
1
2

Note

Let's consider the first sample. 

<image> The figure above shows the first sample. 

  * Vertex 1 and vertex 2 are connected by color 1 and 2. 
  * Vertex 3 and vertex 4 are connected by color 3. 
  * Vertex 1 and vertex 4 are not connected by any single color. 

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {

    static boolean[] visited;
    static ArrayList<Edge>[] graph;
    static boolean[] colorVisited;
    static int end;
    static int count;

    public static void main(String[] args) {
        FastReader sc = new FastReader();

        int n = sc.nextInt();
        int m = sc.nextInt();
        visited = new boolean[n];
        colorVisited = new boolean[m + 1];


        graph = new ArrayList[n];
        for (int i = 0; i < graph.length; i++) {
            graph[i] = new ArrayList<>();
        }

        int a, b, c;

        for (int i = 0; i < m; i++) {
            a = sc.nextInt() - 1;
            b = sc.nextInt() - 1;
            c = sc.nextInt();
            graph[a].add(new Edge(b, c));
            graph[b].add(new Edge(a, c));
        }

        int q = sc.nextInt();
        int u;

        for (int i = 0; i < q; i++) {
            u = sc.nextInt() - 1;
            end = sc.nextInt() - 1;
            count = 0;

            Arrays.fill(colorVisited, false);

            // Visited auto fills false
            visited[u] = true;
            dfs(u, 0);
            visited[u] = false;
            System.out.println(count);
        }

    }


    public static void dfs(int curr, int color) {

        if (curr == end) {
            if (!colorVisited[color]) count++;
            colorVisited[color] = true;
            return;
        }

        for (Edge edge : graph[curr]) {

            if (visited[edge.to]) continue;

            if ((edge.color == color || color == 0) && !colorVisited[color]) {
                visited[edge.to] = true;
                dfs(edge.to, edge.color);
                visited[edge.to] = false;
            }
        }
    }

    static class Edge {
        public int to;
        public int color;

        public Edge(int to, int color) {
            this.to = to;
            this.color = color;
        }
    }

    static class FastReader
    {
        BufferedReader br;
        StringTokenizer st;

        public FastReader()
        {
            br = new BufferedReader(new
                    InputStreamReader(System.in));
        }

        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException  e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt()
        {
            return Integer.parseInt(next());
        }

        long nextLong()
        {
            return Long.parseLong(next());
        }

        double nextDouble()
        {
            return Double.parseDouble(next());
        }

        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
    }
}