Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include<cstdio>
int a[1<<17|1][11],b[41][1<<17|1],i,j,k,n,p=1e9+7,x,y,z;
int main()
{
    scanf("%d%d%d%d",&n,&x,&y,&z),y+=x,z+=y;
    for(i=1;i<=1<<z;i++)
    for(j=1;j<11;j++)
    {
        for(a[i][j]=1,k=0;k+j<=z;k++)
        if((i>>k&1)&&!(k<x&&k+j>x)&&!(k<y&&k+j>y))a[i][j]|=1<<j+k;
        if(a[i][j]>=1<<z||i==1<<z)a[i][j]=1<<z;
    }
    for(b[0][1]=1,i=0;i<n;i++)
    for(j=1;j<=1<<z;j++)
    for(k=1;k<11;k++)
    b[i+1][a[j][k]]=(b[i+1][a[j][k]]+b[i][j])%p;
    printf("%d",b[n][1<<z]);
    return 0;
}