Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include<bits/stdc++.h>
#define int long long
using namespace std; 
const int N=50,M=(1<<17)+5,mod=1e9+7; 
int n,x,y,z,st,dp[N][M],sum=1,k,ans;
signed main(){
	scanf("%lld%lld%lld%lld",&n,&x,&y,&z); 
	st=((1<<(x+y+z-1)))|(1<<(y+z-1))|(1<<(z-1));
	dp[0][0]=1;
	for(int i=1;i<=n;i++){ 
		sum=sum*10%mod; 
		for(int S=0;S<(1<<(x+y+z));S++)
			if(dp[i-1][S]&&(S&st)!=st)
				for(int c=1;c<=10;c++){ 
					k=((S<<c)|(1<<(c-1)))&((1<<(x+y+z))-1);
					dp[i][k]=(dp[i][k]+dp[i-1][S])%mod;
				} 
	} 
	for(int S=0;S<(1<<(x+y+z));S++)
		if((S&st)!=st) ans=(ans+dp[n][S])%mod;
	printf("%lld\n",(sum-ans+mod)%mod);
	return 0;
}