Vasya works as a watchman in the gallery. Unfortunately, one of the most expensive paintings was stolen while he was on duty. He doesn't want to be fired, so he has to quickly restore the painting. He remembers some facts about it.

  * The painting is a square 3 × 3, each cell contains a single integer from 1 to n, and different cells may contain either different or equal integers. 
  * The sum of integers in each of four squares 2 × 2 is equal to the sum of integers in the top left square 2 × 2. 
  * Four elements a, b, c and d are known and are located as shown on the picture below. 

<image>

Help Vasya find out the number of distinct squares the satisfy all the conditions above. Note, that this number may be equal to 0, meaning Vasya remembers something wrong.

Two squares are considered to be different, if there exists a cell that contains two different integers in different squares.

Input

The first line of the input contains five integers n, a, b, c and d (1 ≤ n ≤ 100 000, 1 ≤ a, b, c, d ≤ n) — maximum possible value of an integer in the cell and four integers that Vasya remembers.

Output

Print one integer — the number of distinct valid squares.

Examples

Input

2 1 1 1 2


Output

2


Input

3 3 1 2 3


Output

6

Note

Below are all the possible paintings for the first sample. <image> <image>

In the second sample, only paintings displayed below satisfy all the rules. <image> <image> <image> <image> <image> <image>
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.io.Reader;
import java.util.HashSet;
import java.util.StringTokenizer;

// Codeforces Round #353 (Div. 2)
// Restoring Painting
public class Problem_675_B {
    

    public static void main(String[] args)
    {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        PrintWriter out = new PrintWriter(outputStream);
        Problem_675_B solver = new Problem_675_B();
        solver.solve(1, new InputStreamReader(inputStream), out);
        out.close();
    }

    public void solve(int test, Reader input, PrintWriter out)
    {
        MyScanner in = new MyScanner(input);
        
        int n = in.nextInt();
        int a = in.nextInt();
        int b = in.nextInt();
        int c = in.nextInt();
        int d = in.nextInt();
        
        long count = 0;
        
        HashSet<String> used = new HashSet<>();
        
        StringBuilder sb = new StringBuilder();
        for(int j = 1; j <= n; j++) {
          int e = j;
          int f = e + b - c;
          int h = a + e - d;
          int i = a + f - d;
          if(f < 1  || f > n || h < 1 || h > n || i < 1 || i > n || 
              (a + b + e) != (a + f + c) || (a + b + e) != (b + h + d) || (a + b + e) != (c + d + i)) continue;
          sb.setLength(0);
          sb.append(e);
          sb.append(',');
          sb.append(f);
          sb.append(',');
          sb.append(h);
          sb.append(',');
          sb.append(i);
          String k = sb.toString();
          if(!used.contains(k)) {
            count += n;
            used.add(k);
          }
        }
        out.println(count);
    }

    //-----------MyScanner class for faster input----------
    public static class MyScanner {
        BufferedReader br;
        StringTokenizer st;

        public MyScanner(Reader reader) {
            br = new BufferedReader(reader);
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }
        
        int[] nextIntArray(int n)
        {
            int[] r = new int[n];
            for(int i = 0; i < n; i++)
                r[i] = nextInt();
            return r;
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine(){
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

    }
    //--------------------------------------------------------

}
