The Cartesian coordinate system is set in the sky. There you can see n stars, the i-th has coordinates (xi, yi), a maximum brightness c, equal for all stars, and an initial brightness si (0 ≤ si ≤ c).

Over time the stars twinkle. At moment 0 the i-th star has brightness si. Let at moment t some star has brightness x. Then at moment (t + 1) this star will have brightness x + 1, if x + 1 ≤ c, and 0, otherwise.

You want to look at the sky q times. In the i-th time you will look at the moment ti and you will see a rectangle with sides parallel to the coordinate axes, the lower left corner has coordinates (x1i, y1i) and the upper right — (x2i, y2i). For each view, you want to know the total brightness of the stars lying in the viewed rectangle.

A star lies in a rectangle if it lies on its border or lies strictly inside it.

Input

The first line contains three integers n, q, c (1 ≤ n, q ≤ 105, 1 ≤ c ≤ 10) — the number of the stars, the number of the views and the maximum brightness of the stars.

The next n lines contain the stars description. The i-th from these lines contains three integers xi, yi, si (1 ≤ xi, yi ≤ 100, 0 ≤ si ≤ c ≤ 10) — the coordinates of i-th star and its initial brightness.

The next q lines contain the views description. The i-th from these lines contains five integers ti, x1i, y1i, x2i, y2i (0 ≤ ti ≤ 109, 1 ≤ x1i < x2i ≤ 100, 1 ≤ y1i < y2i ≤ 100) — the moment of the i-th view and the coordinates of the viewed rectangle.

Output

For each view print the total brightness of the viewed stars.

Examples

Input

2 3 3
1 1 1
3 2 0
2 1 1 2 2
0 2 1 4 5
5 1 1 5 5


Output

3
0
3


Input

3 4 5
1 1 2
2 3 0
3 3 1
0 1 1 100 100
1 2 2 4 4
2 2 1 4 7
1 50 50 51 51


Output

3
3
5
0

Note

Let's consider the first example.

At the first view, you can see only the first star. At moment 2 its brightness is 3, so the answer is 3.

At the second view, you can see only the second star. At moment 0 its brightness is 0, so the answer is 0.

At the third view, you can see both stars. At moment 5 brightness of the first is 2, and brightness of the second is 1, so the answer is 3.
import java.util.*;
import java.util.stream.*;
import java.io.*;
import java.math.*;

public class Main { 
    
    static boolean FROM_FILE = false;
    
    static class FastReader { 
        BufferedReader br; 
        StringTokenizer st; 
        public FastReader() { 
            if (FROM_FILE) {
                try {
                    br = new BufferedReader(new FileReader("input.txt")); 
                } catch (IOException error) {
                }   
            } else {
                br = new BufferedReader(new InputStreamReader(System.in));    
            }
        }
        String next() { 
            while (st == null || !st.hasMoreElements()) { 
                try { 
                    st = new StringTokenizer(br.readLine()); 
                } catch (IOException  e) { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        }
        int nextInt() { 
            return Integer.parseInt(next()); 
        }
        long nextLong() { 
            return Long.parseLong(next()); 
        }
  
        double nextDouble() { 
            return Double.parseDouble(next()); 
        } 
        String nextLine() { 
            String str = ""; 
            try { 
                str = br.readLine(); 
            } catch (IOException e) { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }
    static int max(int... nums) {
        int res = Integer.MIN_VALUE;
        for (int num: nums) res = Math.max(res, num);
        return res;
    }
    static int min(int... nums) {
        int res = Integer.MAX_VALUE;
        for (int num: nums) res = Math.min(res, num);
        return res;
    }
    
    public static void main(String[] args) { 
        FastReader fr = new FastReader(); 
        PrintWriter out = null;
        if (FROM_FILE) {
            try {
                out = new PrintWriter(new FileWriter("output.txt"));
            } catch (IOException error) {
                
            }
        } else {
            out = new PrintWriter(new OutputStreamWriter(System.out));
        }
        new Main().run(fr, out);
        out.flush();
        out.close();
    } 
    
    void run(FastReader fr, PrintWriter out) {
        int n = fr.nextInt(), q = fr.nextInt(), c = fr.nextInt();
        int max_num = 101;
        int[][][] stars = new int[max_num][max_num][c + 1];
        for (int i = 0; i < n; i += 1) {
            int x = fr.nextInt(), y = fr.nextInt(), t = fr.nextInt();
            for (int j = 0; j <= c; j += 1) stars[x][y][j] += (t + j) % (c + 1);
        }
        int[][][] dp = new int[max_num][max_num][c + 1];
        for (int k = 0; k <= c; k += 1) {
            for (int i = 1; i < max_num; i += 1) {
                for (int j = 1; j < max_num; j += 1) {
                    dp[i][j][k] = stars[i][j][k] + dp[i - 1][j][k] + dp[i][j - 1][k] - dp[i - 1][j - 1][k];
                }
            }
        }
        for (int i = 0; i < q; i += 1) {
            int t = fr.nextInt(), x1 = fr.nextInt(), y1 = fr.nextInt(), x2 = fr.nextInt(), y2 = fr.nextInt();
            int k = t % (c + 1);
            int val = dp[x2][y2][k] - dp[x2][y1 - 1][k] - dp[x1 - 1][y2][k] + dp[x1 - 1][y1 - 1][k];
            out.println(val);
        }
    }
}