Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.
for _ in range(1):
    u,v=map(int,input().split())
    if u==v and u+v!=0:
        print(1)
        print(u)
    elif v<u:
        print(-1)
    elif (v-u)%2==1:
        print(-1)
    elif u+v==0:
        print(0)
    else:
        z=v-u
        if (z//2+u)^z//2==u:
            print(2)
            print(z//2+u,z//2)
        else:
            print(3)
            print(z//2,z//2,u)


        