Vova had a pretty weird sleeping schedule. There are h hours in a day. Vova will sleep exactly n times. The i-th time he will sleep exactly after a_i hours from the time he woke up. You can assume that Vova woke up exactly at the beginning of this story (the initial time is 0). Each time Vova sleeps exactly one day (in other words, h hours).

Vova thinks that the i-th sleeping time is good if he starts to sleep between hours l and r inclusive.

Vova can control himself and before the i-th time can choose between two options: go to sleep after a_i hours or after a_i - 1 hours.

Your task is to say the maximum number of good sleeping times Vova can obtain if he acts optimally.

Input

The first line of the input contains four integers n, h, l and r (1 ≤ n ≤ 2000, 3 ≤ h ≤ 2000, 0 ≤ l ≤ r < h) — the number of times Vova goes to sleep, the number of hours in a day and the segment of the good sleeping time.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i < h), where a_i is the number of hours after which Vova goes to sleep the i-th time.

Output

Print one integer — the maximum number of good sleeping times Vova can obtain if he acts optimally.

Example

Input


7 24 21 23
16 17 14 20 20 11 22


Output


3

Note

The maximum number of good times in the example is 3.

The story starts from t=0. Then Vova goes to sleep after a_1 - 1 hours, now the time is 15. This time is not good. Then Vova goes to sleep after a_2 - 1 hours, now the time is 15 + 16 = 7. This time is also not good. Then Vova goes to sleep after a_3 hours, now the time is 7 + 14 = 21. This time is good. Then Vova goes to sleep after a_4 - 1 hours, now the time is 21 + 19 = 16. This time is not good. Then Vova goes to sleep after a_5 hours, now the time is 16 + 20 = 12. This time is not good. Then Vova goes to sleep after a_6 hours, now the time is 12 + 11 = 23. This time is good. Then Vova goes to sleep after a_7 hours, now the time is 23 + 22 = 21. This time is also good.
from __future__ import division, print_function
# import threading
# threading.stack_size(2**27)
# import sys
# sys.setrecursionlimit(10**7)
from sys import stdin, stdout
import bisect            #c++ upperbound
import math
import heapq
i_m=9223372036854775807
def modinv(n,p):
    return pow(n,p-2,p)
def cin():
    return map(int,sin().split())
def ain():                           #takes array as input
    return list(map(int,sin().split()))
def sin():
    return input()
def inin():
    return int(input())
import math  
def GCD(x, y): 
    x=abs(x)
    y=abs(y)
    if(min(x,y)==0):
        return max(x,y)
    while(y): 
        x, y = y, x % y 
    return x 
def Divisors(n) : 
    l = []  
    for i in range(1, int(math.sqrt(n) + 1)) :
        if (n % i == 0) : 
            if (n // i == i) : 
                l.append(i) 
            else : 
                l.append(i)
                l.append(n//i)
    return l
prime=[]
def SieveOfEratosthenes(n): 
    global prime
    prime = [True for i in range(n+1)] 
    p = 2
    while (p * p <= n): 
        if (prime[p] == True): 
            for i in range(p * p, n+1, p): 
                prime[i] = False
        p += 1
    f=[]
    for p in range(2, n): 
        if prime[p]: 
            f.append(p)
    return f
q=[]       
def dfs(n,d,v,c):
    global q
    v[n]=1
    if n not in d:
        return v
    x=d[n]
    q.append(n)
    j=c
    for i in x:
        if i not in v:
            v=dfs(i,d,v,c+1)
            # print(f)
    return v
    
"""*******************************************************"""
def main():
    n,h,x,y=cin()
    a=ain()
    d={0:0}
    for i in a:
        dd={}
        for j in d:
            p=j+i
            q=p-1
            p=p%h
            q=(q+h)%h
            t=0
            tt=0
            if(p<=y and p>=x):
                t=1
            if(q<=y and q>=x):
                tt=1
            if p not in dd:
                dd[p]=d[j]+t
            else:
                dd[p]=max(dd[p],d[j]+t)
            if q not in dd:
                dd[q]=d[j]+tt
            else:
                dd[q]=max(dd[q],d[j]+tt)
        d=dict(dd)
    print(max(d.values()))

######## Python 2 and 3 footer by Pajenegod and c1729
 
# Note because cf runs old PyPy3 version which doesn't have the sped up
# unicode strings, PyPy3 strings will many times be slower than pypy2.
# There is a way to get around this by using binary strings in PyPy3
# but its syntax is different which makes it kind of a mess to use.
 
# So on cf, use PyPy2 for best string performance.
 
py2 = round(0.5)
if py2:
    from future_builtins import ascii, filter, hex, map, oct, zip
    range = xrange
 
import os, sys
from io import IOBase, BytesIO
 
BUFSIZE = 8192
class FastIO(BytesIO):
    newlines = 0
 
    def __init__(self, file):
        self._file = file
        self._fd = file.fileno()
        self.writable = "x" in file.mode or "w" in file.mode
        self.write = super(FastIO, self).write if self.writable else None
 
    def _fill(self):
        s = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
        self.seek((self.tell(), self.seek(0,2), super(FastIO, self).write(s))[0])
        return s
 
    def read(self):
        while self._fill(): pass
        return super(FastIO,self).read()
 
    def readline(self):
        while self.newlines == 0:
            s = self._fill(); self.newlines = s.count(b"\n") + (not s)
        self.newlines -= 1
        return super(FastIO, self).readline()
 
    def flush(self):
        if self.writable:
            os.write(self._fd, self.getvalue())
            self.truncate(0), self.seek(0)
 
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        if py2:
            self.write = self.buffer.write
            self.read = self.buffer.read
            self.readline = self.buffer.readline
        else:
            self.write = lambda s:self.buffer.write(s.encode('ascii'))
            self.read = lambda:self.buffer.read().decode('ascii')
            self.readline = lambda:self.buffer.readline().decode('ascii')
 
 
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip('\r\n')
 
# Cout implemented in Python
import sys
class ostream:
    def __lshift__(self,a):
        sys.stdout.write(str(a))
        return self
cout = ostream()
endl = '\n'
 
# Read all remaining integers in stdin, type is given by optional argument, this is fast
def readnumbers(zero = 0):
    conv = ord if py2 else lambda x:x
    A = []; numb = zero; sign = 1; i = 0; s = sys.stdin.buffer.read()
    try:
        while True:
            if s[i] >= b'R' [0]:
                numb = 10 * numb + conv(s[i]) - 48
            elif s[i] == b'-' [0]: sign = -1
            elif s[i] != b'\r' [0]:
                A.append(sign*numb)
                numb = zero; sign = 1
            i += 1
    except:pass
    if s and s[-1] >= b'R' [0]:
        A.append(sign*numb)
    return A
 
# threading.Thread(target=main).start()
if __name__== "__main__":
  main()