For a finite set of integers X, let f(X)=\max X - \min X.

Given are N integers A_1,...,A_N.

We will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.

Since the answer can be enormous, print it \bmod (10^9+7).

Constraints

* 1 \leq N \leq 10^5
* 1 \leq K \leq N
* |A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:


N K
A_1 ... A_N


Output

Print the answer \bmod (10^9+7).

Examples

Input

4 2
1 1 3 4


Output

11


Input

6 3
10 10 10 -10 -10 -10


Output

360


Input

3 1
1 1 1


Output

0


Input

10 6
1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0


Output

999998537
mod = 10**9+7
n,k = map(int,input().split())
A = list(map(int,input().split()))
A.sort()
frac = [1]*(n+1)
finv = [1]*(n+1)
for i in range(n):
    frac[i+1] = (i+1)*frac[i]%mod
finv[-1] = pow(frac[-1],mod-2,mod)
for i in range(1,n+1):
    finv[n-i] = finv[n-i+1]*(n-i+1)%mod
def nCr(n,r):
    if n<0 or r<0 or n<r: return 0
    r = min(r,n-r)
    return frac[n]*finv[n-r]*finv[r]%mod
maxv = 0
for i,a in enumerate(A):
    maxv += nCr(i,k-1)*a
    maxv %=mod
minv = 0
for i,a in enumerate(A):
    minv += nCr(n-i-1,k-1)*a
    minv %= mod
print((maxv-minv)%mod)