A positive integer is called a 2-3-integer, if it is equal to 2x·3y for some non-negative integers x and y. In other words, these integers are such integers that only have 2 and 3 among their prime divisors. For example, integers 1, 6, 9, 16 and 108 — are 2-3 integers, while 5, 10, 21 and 120 are not.

Print the number of 2-3-integers on the given segment [l, r], i. e. the number of sich 2-3-integers t that l ≤ t ≤ r.

Input

The only line contains two integers l and r (1 ≤ l ≤ r ≤ 2·109).

Output

Print a single integer the number of 2-3-integers on the segment [l, r].

Examples

Input

1 10


Output

7


Input

100 200


Output

5


Input

1 2000000000


Output

326

Note

In the first example the 2-3-integers are 1, 2, 3, 4, 6, 8 and 9.

In the second example the 2-3-integers are 108, 128, 144, 162 and 192.
#include <bits/stdc++.h>
const double PI = 3.141592653589793238460;
using namespace std;
long long pows(long long a, long long n, long long m) {
  long long res = 1;
  while (n) {
    if (n % 2 != 0) {
      res = (res * a) % m;
      n--;
    } else {
      a = (a * a) % m;
      n = n / 2;
    }
  }
  return res % m;
}
long long gcd(long long a, long long b) {
  if (b == 0)
    return a;
  else
    return gcd(b, a % b);
}
bool isprime(long long n) {
  if (n == 1) {
    return false;
  }
  for (long long i = 2; i * i <= n; i++) {
    if (n % i == 0) {
      return false;
    }
  }
  return true;
}
bool istrue(string s) {
  int i = 0;
  int j = s.size() - 1;
  while (i < j) {
    if (s[i] == s[j]) {
      i++;
      j--;
    } else {
      return false;
    }
  }
  return true;
}
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long l, r;
  cin >> l >> r;
  long long ans = 0;
  for (long long i = 1; i <= r; i = i * 2) {
    for (long long j = 1; j <= r; j = j * 3) {
      if (i * j >= l && i * j <= r) {
        ans++;
      }
    }
  }
  cout << ans << endl;
}
