Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20
import sys

class Operation:
    def __init__(self, left, right, value):
        self.left = left
        self.right = right
        self.value = value
        
def main():
    data = [line.rstrip().split() for line in sys.stdin.readlines()]
    data = [[int(x) for x in row] for row in data]
    
    num_elements = data[0][0]
    num_ops = data[0][1]
    num_queries = data[0][2]
    l = [0] * 100000
    r = [0] * 100000
    d = [0] * 100000
    elements = [0] * 100000
    inc = [0] * 100001
    dInA = [0] * 100001
    
    
    for i in range(num_elements):
        elements[i] = data[1][i]
    
    for i in range(num_ops):
        l[i] = data[i + 2][0]
        r[i] = data[i + 2][1]
        d[i] = data[i + 2][2]
        
        # l.append(left)
        # r.append(right)
        # d.append(value)
        # operations.append(Operation(left=left, right=right, value=value)
        
    for i in range(num_queries):
        x = data[i + num_ops + 2][0]
        y = data[i + num_ops + 2][1]
        
        inc[x - 1] += 1
        inc[y] -= 1
        
    c = 0

    for i in range(num_ops):
        c += inc[i]
        newValueD = c * d[i]
        dInA[l[i]-1] += newValueD
        dInA[r[i]] -= newValueD
        
    c = 0
    for i in range(num_elements):
        c += dInA[i]
        if (i):
            print(" ")
        print(str(c + elements[i]))
        
        
main()
    