Greg has an array a = a1, a2, ..., an and m operations. Each operation looks as: li, ri, di, (1 ≤ li ≤ ri ≤ n). To apply operation i to the array means to increase all array elements with numbers li, li + 1, ..., ri by value di.

Greg wrote down k queries on a piece of paper. Each query has the following form: xi, yi, (1 ≤ xi ≤ yi ≤ m). That means that one should apply operations with numbers xi, xi + 1, ..., yi to the array.

Now Greg is wondering, what the array a will be after all the queries are executed. Help Greg.

Input

The first line contains integers n, m, k (1 ≤ n, m, k ≤ 105). The second line contains n integers: a1, a2, ..., an (0 ≤ ai ≤ 105) — the initial array.

Next m lines contain operations, the operation number i is written as three integers: li, ri, di, (1 ≤ li ≤ ri ≤ n), (0 ≤ di ≤ 105).

Next k lines contain the queries, the query number i is written as two integers: xi, yi, (1 ≤ xi ≤ yi ≤ m).

The numbers in the lines are separated by single spaces.

Output

On a single line print n integers a1, a2, ..., an — the array after executing all the queries. Separate the printed numbers by spaces.

Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier.

Examples

Input

3 3 3
1 2 3
1 2 1
1 3 2
2 3 4
1 2
1 3
2 3


Output

9 18 17


Input

1 1 1
1
1 1 1
1 1


Output

2


Input

4 3 6
1 2 3 4
1 2 1
2 3 2
3 4 4
1 2
1 3
2 3
1 2
1 3
2 3


Output

5 18 31 20

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class DifferentArray {
  long[] nums;
  long[] d;

  public DifferentArray(int[] array) {
    nums = new long[array.length];
    for (int i = 0; i < array.length; i++){
      nums[i] = array[i];
    }
    d = new long[nums.length + 1];
    d[0] = nums[0];
    for (int i = 1; i < nums.length; i++) {
      d[i] = nums[i] - nums[i - 1];
    }
  }

  // 3 3 3
  // 1 2 3
  // 1 2 1
  // 1 3 2
  // 2 3 4
  // 1 2
  // 1 3
  // 2 3
  public static void main(String[] args) throws IOException {
    BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    String[] s = reader.readLine().split(" ");
    int n = Integer.parseInt(s[0]);
    int m = Integer.parseInt(s[1]);
    int k = Integer.parseInt(s[2]);
    int[] nums = new int[n];
    s = reader.readLine().split(" ");
    for (int i = 0; i < n; i++) {
      nums[i] = Integer.parseInt(s[i]);
    }
    DifferentArray da = new DifferentArray(nums);
    DifferentArray opDa = new DifferentArray(new int[m]);
    int[][] ops = new int[m][3];
    for (int i = 0; i < m; i++) {
      s = reader.readLine().split(" ");
      ops[i][0] = Integer.parseInt(s[0]);
      ops[i][1] = Integer.parseInt(s[1]);
      ops[i][2] = Integer.parseInt(s[2]);
    }
    while (k-- > 0) {
      s = reader.readLine().split(" ");
      opDa.update(Integer.parseInt(s[0]), Integer.parseInt(s[1]), 1);
    }
    long[] opsCount = opDa.getResult();
    for (int i = 0; i < m; i++) {
      da.update(ops[i][0], ops[i][1], ops[i][2] * opsCount[i]);
    }
    long[] result = da.getResult();
    StringBuilder sb = new StringBuilder();
    for (long tmp : result) {
      sb.append(tmp).append(" ");
    }
    System.out.println(sb.toString());
  }

  private long[] getResult() {
    nums[0] = d[0];
    for (int i = 1; i < nums.length; i++) {
      nums[i] = nums[i - 1] + d[i];
    }
    return nums;
  }

  private void update(int left, int right, long val) {
    d[left - 1] += val;
    d[right] -= val;
  }
}
