Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.
u, v = map(int, input().split())
if u > v:
    print (-1)
elif u == 0 and v == 0:
    print (0)
elif u == v:
    print (1)
    print (u)
elif (v-u) % 2 == 0:
    d = (v-u) // 2
    if (u+d) ^ d == u:
        print (2)
        print (u+d, d)
    else:
        print (3)
        print (u, d, d)
else:
    print (-1)
