Mr. Kitayuta has just bought an undirected graph with n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.

Mr. Kitayuta wants you to process the following q queries.

In the i-th query, he gives you two integers - ui and vi.

Find the number of the colors that satisfy the following condition: the edges of that color connect vertex ui and vertex vi directly or indirectly.

Input

The first line of the input contains space-separated two integers - n and m(2 ≤ n ≤ 105, 1 ≤ m ≤ 105), denoting the number of the vertices and the number of the edges, respectively.

The next m lines contain space-separated three integers - ai, bi(1 ≤ ai < bi ≤ n) and ci(1 ≤ ci ≤ m). Note that there can be multiple edges between two vertices. However, there are no multiple edges of the same color between two vertices, that is, if i ≠ j, (ai, bi, ci) ≠ (aj, bj, cj).

The next line contains a integer- q(1 ≤ q ≤ 105), denoting the number of the queries.

Then follows q lines, containing space-separated two integers - ui and vi(1 ≤ ui, vi ≤ n). It is guaranteed that ui ≠ vi.

Output

For each query, print the answer in a separate line.

Examples

Input

4 5
1 2 1
1 2 2
2 3 1
2 3 3
2 4 3
3
1 2
3 4
1 4


Output

2
1
0


Input

5 7
1 5 1
2 5 1
3 5 1
4 5 1
1 2 2
2 3 2
3 4 2
5
1 5
5 1
2 5
1 5
1 4


Output

1
1
1
1
2

Note

Let's consider the first sample. 

<image> The figure above shows the first sample. 

  * Vertex 1 and vertex 2 are connected by color 1 and 2. 
  * Vertex 3 and vertex 4 are connected by color 3. 
  * Vertex 1 and vertex 4 are not connected by any single color. 
#include <bits/stdc++.h>
using namespace std;
constexpr int INF = 2e9;
struct UnionFind {
  vector<int> data;
  int __size;
  UnionFind(int sz) {
    data.assign(sz, -1);
    __size = sz;
  }
  bool unite(int x, int y) {
    x = find(x), y = find(y);
    if (x == y) return (false);
    if (data[x] > data[y]) swap(x, y);
    __size--;
    data[x] += data[y];
    data[y] = x;
    return (true);
  }
  int find(int k) {
    if (data[k] < 0) return (k);
    return (data[k] = find(data[k]));
  }
  bool same(int x, int y) { return find(x) == find(y); }
  int size(int k) { return (-data[find(k)]); }
  int union_count() { return (__size); }
};
int main() {
  int n, m;
  cin >> n >> m;
  vector<UnionFind> uf(m, UnionFind(n));
  for (int i = 0; i < m; i++) {
    int u, v, c;
    cin >> u >> v >> c;
    u--;
    v--;
    c--;
    uf[c].unite(u, v);
  }
  int q;
  cin >> q;
  while (q--) {
    int u, v;
    cin >> u >> v;
    u--;
    v--;
    int res = 0;
    for (int i = 0; i < m; i++) {
      res += uf[i].same(u, v);
    }
    cout << res << endl;
  }
  return 0;
}
