Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.

Iroha is looking for X,Y,Z-Haiku (defined below) in integer sequences.

Consider all integer sequences of length N whose elements are between 1 and 10, inclusive. Out of those 10^N sequences, how many contain an X,Y,Z-Haiku?

Here, an integer sequence a_0, a_1, ..., a_{N-1} is said to contain an X,Y,Z-Haiku if and only if there exist four indices x, y, z, w (0 ≦ x < y < z < w ≦ N) such that all of the following are satisfied:

* a_x + a_{x+1} + ... + a_{y-1} = X
* a_y + a_{y+1} + ... + a_{z-1} = Y
* a_z + a_{z+1} + ... + a_{w-1} = Z



Since the answer can be extremely large, print the number modulo 10^9+7.

Constraints

* 3 ≦ N ≦ 40
* 1 ≦ X ≦ 5
* 1 ≦ Y ≦ 7
* 1 ≦ Z ≦ 5

Input

The input is given from Standard Input in the following format:


N X Y Z


Output

Print the number of the sequences that contain an X,Y,Z-Haiku, modulo 10^9+7.

Examples

Input

3 5 7 5


Output

1


Input

4 5 7 5


Output

34


Input

37 4 2 3


Output

863912418


Input

40 5 7 5


Output

562805100
#include<iostream>
#include<cstdio>
#include<cstring>
#define MOD 1000000007
#define LL long long
using namespace std;
int n, x, y, z;
int ff, sum;
int dp[60][1<<18];
LL d;
LL f(int b,int k)
{
	LL ans=1;
	int base=b;
	while(k)
	{
		if(k&1)
		{
			ans=(ans*base)%MOD;
		}
		base=base*base%MOD;
		k>>=1;
	}
	return ans%MOD;
}
int main()
{
	cin>>n>>x>>y>>z;
	ff=1<<x+y+z-1;
	ff=ff|(1<<y+z-1);
	ff=ff|(1<<z-1);
	sum=(1<<(x+y+z))-1;
	memset(dp,0,sizeof(dp));
	dp[0][0]=1;
	LL ans=1;
	for(int i=1;i<=n;i++)
	{
		ans*=10;
		ans%=MOD;
		for(int j=0;j<=sum;j++)
		{
			if(dp[i-1][j]==0) continue;
			for(int k=1;k<=10;k++)
			{
				int s=(j<<k)|(1<<(k-1));
				s&=sum;
				if((s&ff)!=ff)
				{
					dp[i][s]=(dp[i-1][j]+dp[i][s])%MOD;
				}
			}
		}
	}
	for(int i=0;i<=sum;i++)
	{
		ans=(ans-dp[n][i]+MOD)%MOD;
	}
	cout<<ans<<endl;
	return 0;
}