Given 2 integers u and v, find the shortest array such that [bitwise-xor](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of its elements is u, and the sum of its elements is v.

Input

The only line contains 2 integers u and v (0 ≤ u,v ≤ 10^{18}).

Output

If there's no array that satisfies the condition, print "-1". Otherwise:

The first line should contain one integer, n, representing the length of the desired array. The next line should contain n positive integers, the array itself. If there are multiple possible answers, print any.

Examples

Input


2 4


Output


2
3 1

Input


1 3


Output


3
1 1 1

Input


8 5


Output


-1

Input


0 0


Output


0

Note

In the first sample, 3⊕ 1 = 2 and 3 + 1 = 4. There is no valid array of smaller length.

Notice that in the fourth sample the array is empty.

import java.util.*;

public class Main {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner sc = new Scanner(System.in);
        long u = sc.nextLong();
        long v = sc.nextLong();
        if (u % 2 != v % 2 || u > v) {
            System.out.println(-1);
            return;
        }
        if (u == v) {
            if (u == 0) {
                System.out.println(0);
            } else {
                System.out.println(1);
                System.out.println(u);
            }
            return;
        }

        long x = (v - u) / 2;
        
        if ((u & x)!=0) {
            System.out.println(3);
            long [] arr= new long [3];
            arr[0]=x;
            arr[1]=u;
            arr[2]=x;
            Arrays.sort(arr);
            System.out.println(arr[0]+ " " + arr[1] + " " + arr[2]);
        }

        else {
            System.out.println(2);
            long [] arr= new long [2];
            arr[0]=x;
            arr[1]=(u ^ x) ;
            Arrays.sort(arr);
            System.out.println(arr[0]+ " " +arr[1]);
        }
    }

}