There are some beautiful girls in Arpa’s land as mentioned before.

Once Arpa came up with an obvious problem:

Given an array and a number x, count the number of pairs of indices i, j (1 ≤ i < j ≤ n) such that <image>, where <image> is bitwise xor operation (see notes for explanation).

<image>

Immediately, Mehrdad discovered a terrible solution that nobody trusted. Now Arpa needs your help to implement the solution to that problem.

Input

First line contains two integers n and x (1 ≤ n ≤ 105, 0 ≤ x ≤ 105) — the number of elements in the array and the integer x.

Second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the elements of the array.

Output

Print a single integer: the answer to the problem.

Examples

Input

2 3
1 2


Output

1

Input

6 1
5 1 2 3 4 1


Output

2

Note

In the first sample there is only one pair of i = 1 and j = 2. <image> so the answer is 1.

In the second sample the only two pairs are i = 3, j = 4 (since <image>) and i = 1, j = 5 (since <image>).

A bitwise xor takes two bit integers of equal length and performs the logical xor operation on each pair of corresponding bits. The result in each position is 1 if only the first bit is 1 or only the second bit is 1, but will be 0 if both are 0 or both are 1. You can read more about bitwise xor operation here: <https://en.wikipedia.org/wiki/Bitwise_operation#XOR>.
import java.io.IOException;
import java.io.InputStream;
import java.util.NoSuchElementException;

public class Main {

    private void solve(FastScanner sc) {
        int n = sc.nextInt();
        int x = sc.nextInt();
        int N = 100000;
        long[] a = new long[N + 1];
        for (int i = 0; i < n; i++) {
            a[sc.nextInt()]++;
        }
        if (x != 0) {
            long ans = 0;
            for (int k = 1; k < N + 1; k++) {
                long i = a[k];
                int p = k ^ x;
                if (p < 0 || p > N) p = 0;
                long j = a[p];
                ans += i * j;
            }
            System.out.println(ans / 2);
        } else {
            long ans = 0;
            for (int k = 1; k < N + 1; k++) {
                if (a[k] > 1) {
                    ans += a[k] * (a[k] - 1) / 2;
                }
            }
            System.out.println(ans);
        }
    }

    /*
     * template
     */

    public static void main(String[] args) {
        FastScanner sc = new FastScanner();
        new Main().solve(sc);
    }

    static class FastScanner {
        private final InputStream in = System.in;
        private final byte[] buffer = new byte[1024];
        private int ptr = 0;
        private int bufLen = 0;

        private boolean hasNextByte() {
            if (ptr < bufLen) {
                return true;
            } else {
                ptr = 0;
                try {
                    bufLen = in.read(buffer);
                } catch (IOException e) {
                    e.printStackTrace();
                }
                if (bufLen <= 0) {
                    return false;
                }
            }
            return true;
        }

        private int readByte() {
            if (hasNextByte()) return buffer[ptr++];
            else return -1;
        }

        private static boolean isPrintableChar(int c) {
            return 33 <= c && c <= 126;
        }

        boolean hasNext() {
            while (hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++;
            return hasNextByte();
        }

        String next() {
            if (!hasNext()) throw new NoSuchElementException();
            StringBuilder sb = new StringBuilder();
            int b = readByte();
            while (isPrintableChar(b)) {
                sb.appendCodePoint(b);
                b = readByte();
            }
            return sb.toString();
        }

        long nextLong() {
            if (!hasNext()) throw new NoSuchElementException();
            long n = 0;
            boolean minus = false;
            int b = readByte();
            if (b == '-') {
                minus = true;
                b = readByte();
            }
            if (b < '0' || '9' < b) {
                throw new NumberFormatException();
            }
            while (true) {
                if ('0' <= b && b <= '9') {
                    n *= 10;
                    n += b - '0';
                } else if (b == -1 || !isPrintableChar(b)) {
                    return minus ? -n : n;
                } else {
                    throw new NumberFormatException();
                }
                b = readByte();
            }
        }

        int nextInt() {
            long nl = nextLong();
            if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
            return (int) nl;
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }
    }
}